Lowest Bit
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6591 Accepted Submission(s): 4836
Problem Description
Given an positive integer A (1 <= A <= 100), output the lowest bit of A.
For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.
Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.
Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
Input
Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data.
Output
For each A in the input, output a line containing only its lowest bit.
Sample Input
26
88
0
Sample Output
2
8
Author
SHI, Xiaohan
Source
Recommend
Ignatius.L
思路:位运算
代码:
#include <iostream> #include <algorithm> #include <cstring> #include <cstdlib> #include <cstdio> using namespace std; int n; int lowbit(int x) { return x & (- x); } int main() { while(scanf("%d",&n),n != 0) { printf("%d ",lowbit(n)); } return 0; }