• HDU 4741 Save Labman No.004 ( 三维计算几何 空间异面直线距离 )


    空间异面直线的距离直接套模板。

    求交点:求出两条直线的公共法向量,其中一条直线与法向量构成的平面另一条直线 的交点即可。还是套模板o(╯□╰)o

    1.不会有两条线平行的情况。

    2.两条直线可能相交

    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    
    using namespace std;
    
    const double EPS = 1e-9;
    const int MAXN = 40;
    
    struct Point3  //空间点
    {
        double x, y, z;
        Point3( double x=0, double y=0, double z=0 ): x(x), y(y), z(z) { }
        Point3( const Point3& a )
        {
            x = a.x;
            y = a.y;
            z = a.z;
            return;
        }
        void showP()
        {
            printf("%f %f %f 
    ", x, y, z);
        }
        Point3 operator+( Point3& rhs )
        {
            return Point3( x+rhs.x, y+rhs.y, z+rhs.z );
        }
    };
    
    struct Line3   //空间直线
    {
        Point3 a, b;
    };
    
    struct plane3   //空间平面
    {
        Point3 a, b, c;
        plane3() {}
        plane3( Point3 a, Point3 b, Point3 c ):
            a(a), b(b), c(c) { }
        void showPlane()
        {
            a.showP();
            b.showP();
            c.showP();
            return;
        }
    };
    
    double dcmp( double a )
    {
        if ( fabs( a ) < EPS ) return 0;
        return a < 0 ? -1 : 1;
    }
    
    //三维叉积
    Point3 Cross3( Point3 u, Point3 v )
    {
        Point3 ret;
        ret.x = u.y * v.z - v.y * u.z;
        ret.y = u.z * v.x - u.x * v.z;
        ret.z = u.x * v.y - u.y * v.x;
        return ret;
    }
    
    //三维点积
    double Dot3( Point3 u, Point3 v )
    {
        return u.x * v.x + u.y * v.y + u.z * v.z;
    }
    
    //矢量差
    Point3 Subt( Point3 u, Point3 v )
    {
        Point3 ret;
        ret.x = u.x - v.x;
        ret.y = u.y - v.y;
        ret.z = u.z - v.z;
        return ret;
    }
    
    //两点距离
    double TwoPointDistance( Point3 p1, Point3 p2 )
    {
        return sqrt( (p1.x - p2.x)*(p1.x - p2.x) + (p1.y - p2.y)*(p1.y - p2.y) + (p1.z - p2.z)*(p1.z - p2.z) );
    }
    
    //向量的模
    double VectorLenth( Point3 p )
    {
        return sqrt( p.x*p.x + p.y*p.y + p.z*p.z );
    }
    
    //空间直线距离
    double LineToLine( Line3 u, Line3 v, Point3& tmp )
    {
        tmp = Cross3( Subt( u.a, u.b ), Subt( v.a, v.b ) );
        return fabs( Dot3( Subt(u.a, v.a), tmp ) ) / VectorLenth(tmp);
    }
    
    //取平面法向量
    Point3 pvec( plane3 s )
    {
        return Cross3( Subt( s.a, s.b ), Subt( s.b, s.c ) );
    }
    
    //空间平面与直线的交点
    Point3 Intersection( Line3 l, plane3 s )
    {
        Point3 ret = pvec(s);
        double t = ( ret.x*(s.a.x-l.a.x)+ret.y*(s.a.y-l.a.y)+ret.z*(s.a.z-l.a.z) )/( ret.x*(l.b.x-l.a.x)+ret.y*(l.b.y-l.a.y)+ret.z*(l.b.z-l.a.z) );
        ret.x = l.a.x + ( l.b.x - l.a.x ) * t;
        ret.y = l.a.y + ( l.b.y - l.a.y ) * t;
        ret.z = l.a.z + ( l.b.z - l.a.z ) * t;
        return ret;
    }
    
    /************以上模板*************/
    
    void solved( Line3 A, Line3 B )
    {
        Point3 normal;
        double dis = LineToLine( A, B, normal );
        printf( "%.6f
    ", dis );
        plane3 pla;
        pla = plane3( A.a, A.b, A.a + normal );
        Point3 u = Intersection( B, pla );
        pla = plane3( B.a, B.b, B.a + normal );
        Point3 v = Intersection( A, pla );
        printf("%.6f %.6f %.6f %.6f %.6f %.6f
    ", v.x, v.y, v.z, u.x, u.y, u.z );
        return;
    }
    
    int main()
    {
        int T;
        scanf( "%d", &T );
        while ( T-- )
        {
            Line3 A, B;
            scanf("%lf%lf%lf", &A.a.x, &A.a.y, &A.a.z );
            scanf("%lf%lf%lf", &A.b.x, &A.b.y, &A.b.z );
            scanf("%lf%lf%lf", &B.a.x, &B.a.y, &B.a.z );
            scanf("%lf%lf%lf", &B.b.x, &B.b.y, &B.b.z );
            solved( A, B );
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/GBRgbr/p/3323023.html
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