• HDU 3954 Level up (线段树特殊懒惰标记)


    http://blog.csdn.net/acm_cxlove/article/details/7548087

    感觉最巧的是定义了min_dis……将区间内有无英雄升级分开处理

    #include <cstdio>
    #include <cstring>
    #include <cstdlib>
    #include <algorithm>
    
    #define lson l, m, rt << 1
    #define rson m + 1, r, rt << 1 | 1
    #define lc rt << 1
    #define rc rt << 1 | 1
    
    using namespace std;
    
    const int MAXN = 12222;
    const int INF = 1 << 30;
    
    struct node
    {
        int exp, level;
        int min_dis;
        int flag;
    };
    
    int N, K, Q;
    node Tr[ MAXN << 2 ];
    int sum[20];
    
    void build( int l, int r, int rt )
    {
        Tr[rt].exp = Tr[rt].flag = 0;
        Tr[rt].level = 1;
        Tr[rt].min_dis = sum[1];
        if ( l == r ) return ;
        int m = ( l + r ) >> 1;
        build( lson );
        build( rson );
        return;
    }
    
    void PushDown( int rt )
    {
        if ( Tr[rt].flag )
        {
            Tr[lc].exp += Tr[rt].flag * Tr[lc].level;
            Tr[lc].min_dis -= Tr[rt].flag;
            Tr[lc].flag += Tr[rt].flag;
    
            Tr[rc].exp += Tr[rt].flag * Tr[rc].level;
            Tr[rc].min_dis -= Tr[rt].flag;
            Tr[rc].flag += Tr[rt].flag;
    
            Tr[rt].flag = 0;
        }
        return;
    }
    
    void PushUp( int rt )
    {
        Tr[rt].level = max( Tr[lc].level, Tr[rc].level );
        Tr[rt].exp = max( Tr[lc].exp, Tr[rc].exp );
        Tr[rt].min_dis = min( Tr[lc].min_dis, Tr[rc].min_dis );
        return;
    }
    
    void Update( int L, int R, int v, int l, int r, int rt )
    {
        if ( l == r )
        {
            Tr[rt].exp += Tr[rt].level * v;
            while ( Tr[rt].exp >= sum[ Tr[rt].level ] )
                ++Tr[rt].level;
            Tr[rt].min_dis = ( sum[ Tr[rt].level ] - Tr[rt].exp ) / Tr[rt].level;
            if( ( sum[ Tr[rt].level ] - Tr[rt].exp ) % Tr[rt].level ) ++Tr[rt].min_dis;
            return;
        }
        int m = ( l + r ) >> 1;
    
        if ( L == l && r == R )
        {
            if ( v >= Tr[rt].min_dis )
            {
                PushDown(rt);
                if ( R <= m ) Update( L, R, v, lson );
                else if ( L > m ) Update( L, R, v, rson );
                else
                {
                    Update( L, m, v, lson );
                    Update( m + 1, R, v, rson );
                }
                PushUp(rt);
            }
            else
            {
                Tr[rt].exp += Tr[rt].level * v;
                Tr[rt].min_dis -= v;
                Tr[rt].flag += v;
            }
            return;
        }
    
        PushDown(rt);
    
        if ( R <= m ) Update( L, R, v, lson );
        else if ( L > m ) Update( L, R, v, rson );
        else
        {
            Update( L, m, v, lson );
            Update( m + 1, R, v, rson );
        }
    
        PushUp(rt);
    
        return;
    }
    
    int Query( int L, int R, int l, int r, int rt )
    {
        if ( L <= l && r <= R ) return Tr[rt].exp;
        PushDown(rt);
        int m = ( l + r ) >> 1;
        int res = 0;
        if ( L <= m ) res = max( res, Query( L, R, lson ) );
        if ( R > m )  res = max( res, Query( L, R, rson ) );
        //PushUp(rt);
        return res;
    }
    
    int main()
    {
        int T;
        int cas = 0;
        scanf( "%d", &T );
        while ( T-- )
        {
            scanf( "%d%d%d", &N, &K, &Q );
            for ( int i = 1; i < K; ++i )
                scanf( "%d", &sum[i] );
            sum[K] = INF;
    
            build( 1, N, 1 );
            printf( "Case %d:
    ", ++cas );
            while ( Q-- )
            {
                char op[4];
                int a, b, c;
                scanf( "%s", op );
                if ( op[0] == 'W' )
                {
                    scanf( "%d%d%d", &a, &b, &c );
                    Update( a, b, c, 1, N, 1 );
                }
                else
                {
                    scanf( "%d%d", &a, &b );
                    printf("%d
    ", Query( a, b, 1, N, 1 ) );
                }
            }
            puts("");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/GBRgbr/p/3269668.html
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