跟矩阵链乘同类型的题……
输出用%llu不是%I64u……
几组数据:
14
1+2*4+3*4+5*0
0*5*6+7*3+2
3+0+6+7+0+4
4*5+7*1*1+1
2*0+3*4*0+5*6+7+8
1+2+3*1+2*1+0
0+2*2+3*0+4
8*9*0+2
2*0+1+0*3
2*0*3+7+1*0*3
1+3*0*5+2
1+1+1+1+1
2*1+1+2*1+2*1+6
1*2*4*0*6*3
#include <cstdio> #include <cstring> #include <cstdlib> #include <cctype> #include <algorithm> #define LL unsigned long long int using namespace std; const int MAXN = 110; int cntNum, cntOp; char str[MAXN]; char op[MAXN]; LL num[MAXN]; bool vis[MAXN][MAXN]; LL dpMax[MAXN][MAXN]; LL dpMin[MAXN][MAXN]; void show() { printf("All nums: "); for ( int i = 0; i < cntNum; ++i ) printf( "%I64d ", num[i] ); printf(" All Ops: "); for ( int i = 0; i < cntOp; ++i ) putchar( op[i] ); puts(""); return; } void chuli() { cntNum = cntOp = 0; int len = strlen(str); for ( int i = 0; i < len; ++i ) { LL tmp = 0; while ( i < len && isdigit( str[i] ) ) { tmp = tmp * 10 + ( str[i] - '0' ); ++i; } num[ cntNum++ ] = tmp; if ( i < len ) op[ cntOp++ ] = str[i]; } //show(); return; } LL DPMAX( int l, int r ) { LL &res = dpMax[l][r]; if ( vis[l][r] ) return res; vis[l][r] = true; if ( l == r ) return res = num[l]; res = 0; for ( int k = l; k < r; ++k ) { if ( op[k] == '+' ) res = max( res, DPMAX( l, k ) + DPMAX( k + 1, r ) ); else if ( op[k] == '*' ) res = max( res, DPMAX( l, k ) * DPMAX( k + 1, r ) ); } //printf( "dp[%d][%d]=%I64u ", l, r, res ); return res; } LL DPMIN( int l, int r ) { LL &res = dpMin[l][r]; if ( vis[l][r] ) return res; vis[l][r] = true; if ( l == r ) return res = num[l]; bool first = true; for ( int k = l; k < r; ++k ) { if ( op[k] == '+' ) { if ( first ) { res = DPMIN( l, k ) + DPMIN( k + 1, r ); first = false; } else res = min( res, DPMIN( l, k ) + DPMIN( k + 1, r ) ); } else if ( op[k] == '*' ) { if ( first ) { res = DPMIN( l, k ) * DPMIN( k + 1, r ); first = false; } else res = min( res, DPMIN( l, k ) * DPMIN( k + 1, r ) ); } } //printf( "dp[%d][%d]=%I64u ", l, r, res ); return res; } int main() { int T; scanf( "%d", &T ); while ( T-- ) { scanf( "%s", str ); chuli(); memset( dpMax, 0, sizeof(dpMax) ); memset( dpMin, 0, sizeof(dpMin) ); memset( vis, false, sizeof(vis) ); LL maxx = DPMAX( 0, cntNum - 1 ); memset( vis, false, sizeof(vis) ); LL minn = DPMIN( 0, cntNum - 1 ); printf( "%llu %llu ", maxx, minn ); } return 0; }