题目链接: http://codeforces.com/contest/789/problem/A
题目描述: 水题
解题思路: 挨个遍历除以容量就可以
代码:
#include <iostream> #include <cstdio> #include <map> #include <iterator> #include <string> #include <algorithm> #include <vector> #include <cmath> #include <cstring> using namespace std; typedef long long ll; int main() { int n, k; scanf( "%d%d", &n, &k ); ll ans = 0; for( int i = 1; i <= n; i++ ) { int num; scanf( "%d", &num ); ans += ll(num/k+(num%k!=0)); } printf( "%lld ", ans/2+(ans%2!=0) ); return 0; }
思考: 这是我切的速度最快的一道水题了吧, 但是没想到第二道题让我痛不欲生的...........