list方法返回的是结果集的list集合,iterate返回的是iterator迭代器。
list方法查询所有记录只发送一条sql语句,select * from 表名
iterate方法查询所有记录的话,先查询到满足条件的所有记录id,并不立即查询所有结果,当我们有用到某个记录的话,他才查询。如果显示所有记录的话需要n+1条sql语句。第一条查id,接下去根据id,一条一条查询,所以是n+1条。
list方法缓存中有记录了,他还是会发生sql语句到数据库中查询。
iterate方法缓存中有记录了,他只发送一条查符合条件的id的sql语句。
先看看list方法。
Session session =DBUtil.getSession(); String hql ="from Deptment" ; Query query = session.createQuery(hql); System.out.println("第一次查询"); List list1 = query.list(); Iterator iter1 = list1.iterator(); while(iter1.hasNext()) { System.out.println( iter1.next()); } System.out.println("第二次查询"); List list2 = query.list(); Iterator iter2 = list2.iterator(); while(iter2.hasNext()) { System.out.println( iter2.next()); } session.close();
结果:
第一次查询
Hibernate: select deptment0_.DEPTID as DEPTID0_, deptment0_.DEPTNAME as DEPTNAME0_ from SCOTT.DEPTMENT deptment0_
Deptment [deptid=2, deptname=sdsdzz]
Deptment [deptid=3, deptname=sdsdzz]
Deptment [deptid=4, deptname=sdsdzz]
Deptment [deptid=1, deptname=a]
第二次查询
Hibernate: select deptment0_.DEPTID as DEPTID0_, deptment0_.DEPTNAME as DEPTNAME0_ from SCOTT.DEPTMENT deptment0_
Deptment [deptid=2, deptname=sdsdzz]
Deptment [deptid=3, deptname=sdsdzz]
Deptment [deptid=4, deptname=sdsdzz]
Deptment [deptid=1, deptname=a]
iterate()方法
Session session =DBUtil.getSession(); String hql ="from Deptment" ; Query query = session.createQuery(hql); System.out.println("第一次查询"); Iterator iter1 = query.iterate(); while(iter1.hasNext()) { System.out.println( iter1.next()); } System.out.println("第二次查询"); Iterator iter2 = query.iterate(); while(iter2.hasNext()) { System.out.println( iter2.next()); } session.close();
结果:
第一次查询
Hibernate: select deptment0_.DEPTID as col_0_0_ from SCOTT.DEPTMENT deptment0_
Hibernate: select deptment0_.DEPTID as DEPTID0_0_, deptment0_.DEPTNAME as DEPTNAME0_0_ from SCOTT.DEPTMENT deptment0_ where deptment0_.DEPTID=?
Deptment [deptid=1, deptname=a]
Hibernate: select deptment0_.DEPTID as DEPTID0_0_, deptment0_.DEPTNAME as DEPTNAME0_0_ from SCOTT.DEPTMENT deptment0_ where deptment0_.DEPTID=?
Deptment [deptid=2, deptname=sdsdzz]
Hibernate: select deptment0_.DEPTID as DEPTID0_0_, deptment0_.DEPTNAME as DEPTNAME0_0_ from SCOTT.DEPTMENT deptment0_ where deptment0_.DEPTID=?
Deptment [deptid=3, deptname=sdsdzz]
Hibernate: select deptment0_.DEPTID as DEPTID0_0_, deptment0_.DEPTNAME as DEPTNAME0_0_ from SCOTT.DEPTMENT deptment0_ where deptment0_.DEPTID=?
Deptment [deptid=4, deptname=sdsdzz]
第二次查询
Hibernate: select deptment0_.DEPTID as col_0_0_ from SCOTT.DEPTMENT deptment0_
Deptment [deptid=1, deptname=a]
Deptment [deptid=2, deptname=sdsdzz]
Deptment [deptid=3, deptname=sdsdzz]
Deptment [deptid=4, deptname=sdsdzz]