• Leetcode: Reverse Words in a String II


    Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.
    
    The input string does not contain leading or trailing spaces and the words are always separated by a single space.
    
    For example,
    Given s = "the sky is blue",
    return "blue is sky the".
    
    Could you do it in-place without allocating extra space?

    这道题要求in-place做法,不能使用extra space, 那么,做法跟Rotate Array那道题非常相似

    (1)reverse the whole array

    (2)reverse each subarray seperated by ' '

    注意不要忘了reverse最后一个word

     1 public void reverseWords(char[] s) {
     2     // Three step to reverse
     3     // 1, reverse the whole sentence
     4     reverse(s, 0, s.length - 1);
     5     // 2, reverse each word
     6     int start = 0;
     7     int end = -1;
     8     for (int i = 0; i < s.length; i++) {
     9         if (s[i] == ' ') {
    10             reverse(s, start, i - 1);
    11             start = i + 1;
    12         }
    13     }
    14     // 3, reverse the last word, if there is only one word this will solve the corner case
    15     reverse(s, start, s.length - 1);
    16 }
    17 
    18 public void reverse(char[] s, int start, int end) {
    19     while (start < end) {
    20         char temp = s[start];
    21         s[start] = s[end];
    22         s[end] = temp;
    23         start++;
    24         end--;
    25     }
    26 }
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  • 原文地址:https://www.cnblogs.com/EdwardLiu/p/4306561.html
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