• LeetCode 641. Design Circular Deque


    原题链接在这里:https://leetcode.com/problems/design-circular-deque/

    题目:

    Design your implementation of the circular double-ended queue (deque).

    Your implementation should support following operations:

    • MyCircularDeque(k): Constructor, set the size of the deque to be k.
    • insertFront(): Adds an item at the front of Deque. Return true if the operation is successful.
    • insertLast(): Adds an item at the rear of Deque. Return true if the operation is successful.
    • deleteFront(): Deletes an item from the front of Deque. Return true if the operation is successful.
    • deleteLast(): Deletes an item from the rear of Deque. Return true if the operation is successful.
    • getFront(): Gets the front item from the Deque. If the deque is empty, return -1.
    • getRear(): Gets the last item from Deque. If the deque is empty, return -1.
    • isEmpty(): Checks whether Deque is empty or not. 
    • isFull(): Checks whether Deque is full or not.

    Example:

    MyCircularDeque circularDeque = new MycircularDeque(3); // set the size to be 3
    circularDeque.insertLast(1);			// return true
    circularDeque.insertLast(2);			// return true
    circularDeque.insertFront(3);			// return true
    circularDeque.insertFront(4);			// return false, the queue is full
    circularDeque.getRear();  			// return 2
    circularDeque.isFull();				// return true
    circularDeque.deleteLast();			// return true
    circularDeque.insertFront(4);			// return true
    circularDeque.getFront();			// return 4

    Note:

    • All values will be in the range of [0, 1000].
    • The number of operations will be in the range of [1, 1000].
    • Please do not use the built-in Deque library.

    题解:

    Use an array to maintain values.

    start index pointing to queue head, initialized as -1.

    end index pointing to queue tail, initialized as -1.

    When insertFront, if start == -1, assign start as 0, else start = (start - 1 + k) % k. Assign new value to arr[start]. If end is -1, need to update end = start. This only happens at the beginning.

    When insertLast, end = (end + 1) % k. Assign new value to arr[end]. If start is -1, need to update start = end. This only happends at the begining.

    deleteFront, move start + 1.

    deleteLast, move end - 1.

    Time Complexity: MyCircularDeque, O(1). insertFront, O(1). insertLast, O(1). deleteFront, O(1). deleteLast, O(1). getFront, O(1). getRear, O(1). isEmpty, O(1). isEmpty, O(1).

    Space: O(k).

    AC Java:

      1 class MyCircularDeque {
      2     int [] arr;
      3     int start;
      4     int end;
      5     int len;
      6     int k;
      7     
      8     /** Initialize your data structure here. Set the size of the deque to be k. */
      9     public MyCircularDeque(int k) {
     10         arr = new int[k];
     11         start = -1;
     12         end = -1;
     13         len = 0;
     14         this.k = k;
     15     }
     16     
     17     /** Adds an item at the front of Deque. Return true if the operation is successful. */
     18     public boolean insertFront(int value) {
     19         if(isFull()){
     20             return false;
     21         }
     22         
     23         if(start == -1){
     24             start = 0;
     25         }else{
     26             start = (start - 1 + k) % k;
     27         }
     28         
     29         arr[start] = value;
     30         if(end == -1){
     31             end = start;
     32         }
     33         
     34         len++;
     35         return true;
     36     }
     37     
     38     /** Adds an item at the rear of Deque. Return true if the operation is successful. */
     39     public boolean insertLast(int value) {
     40         if(isFull()){
     41             return false;
     42         }
     43         
     44         end = (end + 1) % k;
     45         arr[end] = value;
     46         if(start == -1){
     47             start = end;
     48         }
     49         
     50         len++;
     51         return true;
     52     }
     53     
     54     /** Deletes an item from the front of Deque. Return true if the operation is successful. */
     55     public boolean deleteFront() {
     56         if(isEmpty()){
     57             return false;
     58         }
     59         
     60         start = (start + 1) % k;
     61         len--;
     62         return true;
     63     }
     64     
     65     /** Deletes an item from the rear of Deque. Return true if the operation is successful. */
     66     public boolean deleteLast() {
     67         if(isEmpty()){
     68             return false;
     69         }
     70         
     71         end = (end - 1 + k) % k;
     72         len--;
     73         return true;
     74     }
     75     
     76     /** Get the front item from the deque. */
     77     public int getFront() {
     78         return isEmpty() ? -1 : arr[start];
     79     }
     80     
     81     /** Get the last item from the deque. */
     82     public int getRear() {
     83         return isEmpty() ? -1 : arr[end];
     84     }
     85     
     86     /** Checks whether the circular deque is empty or not. */
     87     public boolean isEmpty() {
     88         return len == 0;
     89     }
     90     
     91     /** Checks whether the circular deque is full or not. */
     92     public boolean isFull() {
     93         return len == k;
     94     }
     95 }
     96 
     97 /**
     98  * Your MyCircularDeque object will be instantiated and called as such:
     99  * MyCircularDeque obj = new MyCircularDeque(k);
    100  * boolean param_1 = obj.insertFront(value);
    101  * boolean param_2 = obj.insertLast(value);
    102  * boolean param_3 = obj.deleteFront();
    103  * boolean param_4 = obj.deleteLast();
    104  * int param_5 = obj.getFront();
    105  * int param_6 = obj.getRear();
    106  * boolean param_7 = obj.isEmpty();
    107  * boolean param_8 = obj.isFull();
    108  */

    类似Design Circular Queue.

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  • 原文地址:https://www.cnblogs.com/Dylan-Java-NYC/p/12079440.html
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