• 【模板】树状数组


    现在来填坑,之前落下的知识,现在往回补。之前一直用线段树来顶树状数组和st表,但是跑得慢,写的也慢。。。

    单点修改,区间查询:

    #include<iostream>
    #include<cstdio>
    #include<cmath>
    #include<ctime>
    #include<queue>
    #include<algorithm>
    #include<cstring>
    using namespace std;
    #define duke(i,a,n) for(int i = a;i <= n;i++)
    #define lv(i,a,n) for(int i = a;i >= n;i--)
    #define clean(a) memset(a,0,sizeof(a))
    const int INF = 1 << 30;
    const int N = 300005;
    typedef long long ll;
    typedef double db;
    template <class T>
    void read(T &x)
    {
        char c;
        bool op = 0;
        while(c = getchar(), c < '0' || c > '9')
            if(c == '-') op = 1;
        x = c - '0';
        while(c = getchar(), c >= '0' && c <= '9')
            x = x * 10 + c - '0';
        if(op) x = -x;
    }
    template <class T>
    void write(T x)
    {
        if(x < 0) putchar('-'), x = -x;
        if(x >= 10) write(x / 10);
        putchar('0' + x % 10);
    }
    int n,m;
    int tree[2000000];
    int lowbit(int x)
    {
        return x & -x;
    }
    void update(int x,int y)
    {
        while(x <= n)
        tree[x] += y,x += lowbit(x);
    }
    int getsum(int x)
    {
        int tot = 0;
        while(x > 0)
        tot += tree[x],x -= lowbit(x);
        return tot;
    }
    int main()
    {
        read(n);read(m);
        duke(i,1,n)
        {
            int a;
            read(a); update(i,a);
        }
        while(m--)
        {
            int a,b,c;
            read(a);read(b);read(c);
            if(a == 1)
                update(b,c);
            else
            {
                printf("%d
    ",getsum(c) - getsum(b - 1));
            }
        }
        return 0;
    }

    区间修改,单点查询:(用到了差分思想,注意读入,然后直接查询就是答案)

    #include<iostream>
    #include<cstdio>
    #include<cmath>
    #include<ctime>
    #include<queue>
    #include<algorithm>
    #include<cstring>
    using namespace std;
    #define duke(i,a,n) for(int i = a;i <= n;i++)
    #define lv(i,a,n) for(int i = a;i >= n;i--)
    #define clean(a) memset(a,0,sizeof(a))
    const int INF = 1 << 30;
    const int N = 300005;
    typedef long long ll;
    typedef double db;
    template <class T>
    void read(T &x)
    {
        char c;
        bool op = 0;
        while(c = getchar(), c < '0' || c > '9')
            if(c == '-') op = 1;
        x = c - '0';
        while(c = getchar(), c >= '0' && c <= '9')
            x = x * 10 + c - '0';
        if(op) x = -x;
    }
    template <class T>
    void write(T x)
    {
        if(x < 0) putchar('-'), x = -x;
        if(x >= 10) write(x / 10);
        putchar('0' + x % 10);
    }
    int tree[500010],n,m;
    int lowbit(int x)
    {
        return x & -x;
    }
    void update(int x,int y)
    {
        while(x <= n)
        {
            tree[x] += y;
            x += lowbit(x);
        }
    }
    int query(int x)
    {
        int sum = 0;
        while(x > 0)
        {
            sum += tree[x];
            x -= lowbit(x);
        }
        return sum;
    }
    int main()
    {
        read(n);read(m);
        int lst = 0;
        duke(i,1,n)
        {
            int a;
            read(a);
            update(i,a - lst);
            lst = a;
        }
        while(m--)
        {
            int opt,x,l,r,z;
            read(opt);
            if(opt == 1)
            {
                read(l);read(r);read(z);
                update(l,z);
                update(r + 1,-z);
            }
            else
            {
                read(x);
                int tot = 0;
                tot = query(x);
                printf("%d
    ",tot);
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/DukeLv/p/9745885.html
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