• Treap模板(旋转)


    目前见过作为名次树实现的用法,其他暂时没见过←_←

    #include<bits/stdc++.h>
    #include<stdio.h>
    #include<algorithm>
    #include<queue>
    #include<string.h>
    #include<iostream>
    #include<math.h>
    #include<set>
    #include<map>
    #include<vector>
    #include<iomanip>
    using namespace std;
    #define ll long long
    #define ull unsigned long long
    #define pb push_back
    #define FOR(a) for(int i=1;i<=a;i++)
    const int inf=0x3f3f3f3f;
    const int maxn=2e6+7; 
    const long long mod=1e9+7;
    
    struct NODE{
    	NODE *ch[2];
    	int v,r,s,w;//数据,名次,节点大小,数据出现次数
    	NODE(int v):v(v){
    		ch[0]=ch[1]=NULL;
    		r=rand();s=w=1;
    	}
    	bool operator < (const NODE &rhs)const{return r<rhs.r;}
    	int cmp(int x)const{
    		if(x==v)return -1;
    		return x<v?0:1;		//左边0右边1
    	}
    	int cmp1(int x)const{	//第k大查询的比较
    		int sz=w;
    		if(ch[0])sz+=ch[0]->s;
    		if(sz-w+1<=x && x<=sz)return -1;//找到自身
    		if(x<=sz-w)return 0;
    		return 1;
    	}
    	void maintain(){
    		s=w;if(ch[0])s+=ch[0]->s;if(ch[1])s+=ch[1]->s;
    	}
    }*root;
    void rotate(NODE* &o,int d){	//0左旋
    	NODE *k=o->ch[d^1];
    	o->ch[d^1]=k->ch[d];
    	k->ch[d]=o;
    	o->maintain();k->maintain();
    	o=k;
    }
    void insert(NODE* &o,int v){
    	if(!o){							//空节点
    		o=new NODE(v);
    		return;
    	}else{
    		int d=o->cmp(v);
    		if(d==-1)o->w++;
    		else{
    			insert(o->ch[d],v);		//先插到叶子,再往上旋
    			if(o->ch[d]>o)rotate(o,d^1);//左儿子大就右旋~
    		}
    	}
    	o->maintain();
    }
    void del(NODE* &o,int v){
    	int d=o->cmp(v);
    	if(d==-1){
    		if(o->w > 1)o->w--;
    		else if(o->ch[0]&&o->ch[1]){
    			int d2=0;
    			if(o->ch[0]>o->ch[1])d2=1;
    			rotate(o,d2);
    			del(o->ch[d2],v);
    		}else{
    			if(o->ch[0])o=o->ch[0];
    			else o=o->ch[1];
    		}
    	}else del(o->ch[d],v);
    	if(o)o->maintain();
    }
    void remove(NODE* &o){
    	if(!o)return;
    	if(o->ch[0])remove(o->ch[0]);
    	if(o->ch[1])remove(o->ch[1]);
    	delete o;
    	o=NULL;
    }
    int find(NODE* &o,int x){
    	if(o==NULL)return 0;
    	int d=o->cmp(x);
    	if(d==-1)return o->w;
    	return find(o->ch[d],x);
    }
    int kth(NODE* o,int k){		//按尺寸进子树查找
    	int d=o->cmp1(k);
    	int sz=o->w;
    	if(o->ch[0])sz+=o->ch[0]->s;
    	if(d==-1)return o->v;
    	if(d==0)return kth(o->ch[0],k);
    	return kth(o->ch[1],k-sz);
    }
    int query(NODE *o,int x){	//求排名,前面有多少个
    	if(!o)return 0;
    	int d=o->cmp(x);
    	int sz=o->w;
    	if(o->ch[0])sz+=o->ch[0]->s;
    	if(d==-1)return sz-o->w;
    	else if(d==0)return query(o->ch[0],x);
    	else return query(o->ch[1],x)+sz;
    }
    /*
    //求前驱:
    int sz=query(root,x);	
    printf("%d
    ",kth(root,sz));
    
    //求后继:
    int sz=query(root,x);
    sz+=find(root,x)+1;
    printf("%d
    ",kth(root,sz));
    
    int main(){
    	insert(root,1);
    	insert(root,2);
    	insert(root,3);
    	cout<<query(root,3)<<endl;
    }
    */
    
    int main(){
    	int n;scanf("%d",&n);
    	int op,x;
    	while(n--){
    		scanf("%d%d",&op,&x);
    		if(op==1){insert(root,x);}
    		else if(op==2){
    			del(root,x);
    		}else if(op==3){
    			printf("%d
    ",query(root,x)+1);
    		}else if(op==4){
    			printf("%d
    ",kth(root,x));
    		}else if(op==5){
    			int sz=query(root,x);
    			printf("%d
    ",kth(root,sz));
    		}else if(op==6){
    			int sz=query(root,x);
    			sz+=find(root,x)+1;
    			printf("%d
    ",kth(root,sz));
    		}
    	}
    }

    哪天有空细化一下分类吧。。

    --------------------------------------------------------------

    增加了一下随机数优化的版本:

    #include<bits/stdc++.h>
    #include<stdio.h>
    #include<algorithm>
    #include<queue>
    #include<string.h>
    #include<iostream>
    #include<math.h>
    #include<set>
    #include<map>
    #include<vector>
    #include<iomanip>
    using namespace std;
    #define ll long long
    #define ull unsigned long long
    #define pb push_back
    #define FOR(a) for(int i=1;i<=a;i++)
    const int inf=0x3f3f3f3f;
    const int maxn=2e6+7; 
    const long long mod=1e9+7;
    
    inline int Random(){
    	static int seed=703;
    	return seed=int(seed*48271ll%2147483647);
    }
    struct NODE{
    	NODE *ch[2];
    	int v,r,s,w;//数据,名次,节点大小,数据出现次数
    	NODE(int v):v(v){
    		ch[0]=ch[1]=NULL;
    		r=Random();s=w=1;
    	}
    	bool operator < (const NODE &rhs)const{return r<rhs.r;}
    	inline int cmp(int x)const{
    		if(x==v)return -1;
    		return x<v?0:1;		//左边0右边1
    	}
    	inline int cmp1(int x)const{	//第k大查询的比较
    		int sz=w;
    		if(ch[0])sz+=ch[0]->s;
    		if(sz-w+1<=x && x<=sz)return -1;//找到自身
    		if(x<=sz-w)return 0;
    		return 1;
    	}
    	inline void maintain(){
    		s=w;if(ch[0])s+=ch[0]->s;if(ch[1])s+=ch[1]->s;
    	}
    }*root;
    inline void rotate(NODE* &o,int d){	//0左旋
    	NODE *k=o->ch[d^1];
    	o->ch[d^1]=k->ch[d];
    	k->ch[d]=o;
    	o->maintain();k->maintain();
    	o=k;
    }
    inline void insert(NODE* &o,int v){
    	if(!o){							//空节点
    		o=new NODE(v);
    		return;
    	}else{
    		int d=o->cmp(v);
    		if(d==-1)o->w++;
    		else{
    			insert(o->ch[d],v);		//先插到叶子,再往上旋
    			if(o->ch[d]>o)rotate(o,d^1);//左儿子大就右旋~
    		}
    	}
    	o->maintain();
    }
    inline void del(NODE* &o,int v){
    	int d=o->cmp(v);
    	if(d==-1){
    		if(o->w > 1)o->w--;
    		else if(o->ch[0]&&o->ch[1]){
    			int d2=0;
    			if(o->ch[0]>o->ch[1])d2=1;
    			rotate(o,d2);
    			del(o->ch[d2],v);
    		}else{
    			if(o->ch[0])o=o->ch[0];
    			else o=o->ch[1];
    		}
    	}else del(o->ch[d],v);
    	if(o)o->maintain();
    }
    inline void remove(NODE* &o){
    	if(!o)return;
    	if(o->ch[0])remove(o->ch[0]);
    	if(o->ch[1])remove(o->ch[1]);
    	delete o;
    	o=NULL;
    }
    inline int find(NODE* &o,int x){
    	if(o==NULL)return 0;
    	int d=o->cmp(x);
    	if(d==-1)return o->w;
    	return find(o->ch[d],x);
    }
    inline int kth(NODE* o,int k){		//按尺寸进子树查找
    	int d=o->cmp1(k);
    	int sz=o->w;
    	if(o->ch[0])sz+=o->ch[0]->s;
    	if(d==-1)return o->v;
    	if(d==0)return kth(o->ch[0],k);
    	return kth(o->ch[1],k-sz);
    }
    inline int query(NODE *o,int x){	//求排名,前面有多少个
    	if(!o)return 0;
    	int d=o->cmp(x);
    	int sz=o->w;
    	if(o->ch[0])sz+=o->ch[0]->s;
    	if(d==-1)return sz-o->w;
    	else if(d==0)return query(o->ch[0],x);
    	else return query(o->ch[1],x)+sz;
    }
    /*
    //求前驱:
    int sz=query(root,x);	
    printf("%d
    ",kth(root,sz));
    
    //求后继:
    int sz=query(root,x);
    sz+=find(root,x)+1;
    printf("%d
    ",kth(root,sz));
    
    int main(){
    	insert(root,1);
    	insert(root,2);
    	insert(root,3);
    	cout<<query(root,3)<<endl;
    }
    */
    
    int main(){
    	int n;scanf("%d",&n);
    	int op,x;
    	while(n--){
    		scanf("%d%d",&op,&x);
    		if(op==1){insert(root,x);}
    		else if(op==2){
    			del(root,x);
    		}else if(op==3){
    			printf("%d
    ",query(root,x)+1);
    		}else if(op==4){
    			printf("%d
    ",kth(root,x));
    		}else if(op==5){
    			int sz=query(root,x);
    			printf("%d
    ",kth(root,sz));
    		}else if(op==6){
    			int sz=query(root,x);
    			sz+=find(root,x)+1;
    			printf("%d
    ",kth(root,sz));
    		}
    	}
    }

    -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

    数组版,写起来舒服多了,但多次删除会存在爆空间的可能

    #include<bits/stdc++.h>
    #include<stdio.h>
    #include<algorithm>
    #include<queue>
    #include<string.h>
    #include<iostream>
    #include<math.h>
    #include<set>
    #include<map>
    #include<vector>
    #include<iomanip>
    using namespace std;
    #define ll long long
    #define ull unsigned long long
    #define pb push_back
    #define FOR(a) for(int i=1;i<=a;i++)
    const int inf=0x3f3f3f3f;
    const int maxn=1e5+7; 
    const long long mod=1e9+7;
    
    int nodecnt,root;
    int val[maxn],happen[maxn],l[maxn],r[maxn],rnd[maxn],size[maxn];
    
    void maintain(int x){size[x]=size[l[x]]+size[r[x]]+happen[x];}
    void rturn(int &k){int t=l[k];l[k]=r[t];r[t]=k;maintain(k);maintain(t);k=t;}
    void lturn(int &k){int t=r[k];r[k]=l[t];l[t]=k;maintain(k);maintain(t);k=t;}
    void insert1(int &x,int v){	//按大小
    	if(!x){
    		x=++nodecnt;
    		l[x]=r[x]=0;
    		val[x]=v;happen[x]=size[x]=1;rnd[x]=rand();return;
    	}
    	size[x]++;
    	if(val[x]==v)happen[x]++;
    	else if(v<val[x]){
    		insert1(l[x],v);
    		if(rnd[l[x]]<rnd[x])rturn(x);
    	}else{
    		insert1(r[x],v);
    		if(rnd[r[x]]<rnd[x])lturn(x);
    	}
    }
    void insert2(int &x,int v,int pos){	//按位置,0号位最前
    	if(!x){
    		x=++nodecnt;
    		val[x]=v;
    		rnd[x]=rand();size[x]=happen[x]=1;l[x]=r[x]=0;
    		return;
    	}
    	size[x]++;
    	if(size[l[x]]<pos){
    		insert2(r[x],v,pos-size[l[x]]-1);
    		if(rnd[r[x]]<rnd[x])lturn(x);
    	}else{
    		insert2(l[x],v,pos);
    		if(rnd[l[x]]<rnd[x])rturn(x);
    	}
    }
    void del(int &x,int v){
    	if(!x)return;
    	if(val[x]==v){
    		if(happen[x]>1){happen[x]--;size[x]--;return;}
    		if(!l[x]||!r[x])x=l[x]+r[x];
    		else if(rnd[l[x]]<rnd[r[x]]){rturn(x);del(x,v);}
    		else{lturn(x);del(x,v);}
    	}else{
    		size[x]--;
    		if(v<val[x])del(l[x],v);
    		else del(r[x],v);
    	}
    }
    int rnk(int x,int v){
    	if(!x)return 0;
    	if(val[x]==v)return size[l[x]]+1;
    	else if(v<val[x])return rnk(l[x],v);
    	else return size[l[x]]+happen[x]+rnk(r[x],v);
    }
    int kth(int x,int k){
    	if(!x)return 0;
    	if(k<=size[l[x]])return kth(l[x],k);
    	else if(k>size[l[x]]+happen[x])
    		return kth(r[x],k-size[l[x]]-happen[x]);
    	else return val[x];
    }
    int ans;
    void pre(int x,int v){
    	if(!x)return;
    	if(v>val[x])ans=x,pre(r[x],v);
    	else pre(l[x],v);
    }
    void suf(int x,int v){
    	if(!x)return;
    	if(v<val[x])ans=x,suf(l[x],v);
    	else suf(r[x],v);
    }
    
    int main(){
    	int n;scanf("%d",&n);
    	int op,num;
    	FOR(n){
    		scanf("%d%d",&op,&num);
    		if(op==1){
    			insert1(root,num);
    		}else if(op==2){
    			del(root,num);
    		}else if(op==3){
    			printf("%d
    ",rnk(root,num));
    		}else if(op==4){
    			printf("%d
    ",kth(root,num));
    		}else if(op==5){
    			ans=0;
    			pre(root,num);
    			printf("%d
    ",val[ans]);
    		}else{
    			ans=0;
    			suf(root,num);
    			printf("%d
    ",val[ans]);
    		}
    	}	
    }


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  • 原文地址:https://www.cnblogs.com/Drenight/p/8611269.html
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