A

A - Matrix

Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Submit Status

Appoint description:  System Crawler  (2013-11-23)

Description

You have a string of decimal digits s. Let's define b_ij = s_i·s_j. Find in matrix b the number of such rectangles that the sum b_ij for all cells(i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t)(x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 10⁹), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64dspecifier.

Sample Input

Input

10
12345

Output

6

Input

16
439873893693495623498263984765

Output

40

const int INF = 1000000000;
const double eps = 1e-8;
const int maxn = 4010;
char s[maxn];
LL b[maxn][maxn];
LL sum[maxn];
map<LL,LL> mp;
int main() 
{
    //freopen("in.txt","r",stdin);
    LL a;
    while(cin>>a)
    {
        scanf("%s",s+1);
        int len = strlen(s+1);
        int n  = len;
        LL ans = 0;
        sum[0] = 0;
        LL cnt = 0;
        repf(i,1,n)
            sum[i] = sum[i - 1] + s[i] - '0';
        
        repf(i,1,n)
            repf(j,i,n)
            {
                LL temp = sum[j] - sum[i-1];
                mp[temp] = mp[temp] + 1;
            }
        
        if(a == 0)
        {
            rep(i,1,50000)
                ans += mp[0]*mp[i];
            ans *= 2;
            ans += mp[0]*mp[0];
            cout<<ans<<endl;
            continue;
        }
        for(LL i = 1;i < 50000;++i)
        {
            if(a%i == 0)
            {
                ans += mp[i]*mp[a/i];
            }
        }
        cout<<ans<<endl;
    }
    return 0;
}