• [Leetcode][Python]21: Merge Two Sorted Lists


    # -*- coding: utf8 -*-
    '''
    __author__ = 'dabay.wang@gmail.com'

    21: Merge Two Sorted Lists
    https://oj.leetcode.com/problems/merge-two-sorted-lists/

    Merge two sorted linked lists and return it as a new list.
    The new list should be made by splicing together the nodes of the first two lists.

    ===Comments by Dabay===
    基本链表的操作。先做一个头节点,用两个指针来记录两个链表的位置。
    比较两个链表的节点,把小的挂后边,之后移动指针。
    最后,当一个链表已经比较完了之后,把另外一个链表中剩下的部分挂上。
    '''

    # Definition for singly-linked list.
    class ListNode:
    def __init__(self, x):
    self.val = x
    self.next = None

    class Solution:
    # @param two ListNodes
    # @return a ListNode
    def mergeTwoLists(self, l1, l2):
    node = root = ListNode(0)
    node1 = l1
    node2 = l2
    while node1 and node2:
    if node1.val < node2.val:
    node.next = node1
    node1 = node1.next
    else:
    node.next = node2
    node2 = node2.next
    node = node.next
    if node1:
    node.next = node1
    else:
    node.next = node2
    return root.next


    def main():
    sol = Solution()
    l1 = ListNode(1)
    l2 = ListNode(2)
    merged = sol.mergeTwoLists(l1, l2)
    node = merged
    while node:
    print "%s ->" % node.val,
    print "End"


    if __name__ == '__main__':
    import time
    start = time.clock()
    main()
    print "%s sec" % (time.clock() - start)
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  • 原文地址:https://www.cnblogs.com/Dabay/p/4251809.html
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