题目大意:
给一串数,又正有负,求每一个前缀都大于0的最长子串长度。
题目分析:
直接贪心:每次左端点向右推1,不断延伸右端点,更新答案。
code
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
namespace IO{
inline ll read(){
ll i = 0, f = 1; char ch = getchar();
for(; (ch < '0' || ch > '9') && ch != '-'; ch = getchar());
if(ch == '-') f = -1, ch = getchar();
for(; ch >= '0' && ch <= '9'; ch = getchar()) i = (i << 3) + (i << 1) + (ch - '0');
return i * f;
}
inline void wr(ll x){
if(x < 0) putchar('-'), x = -x;
if(x > 9) wr(x / 10);
putchar(x % 10 + '0');
}
}using namespace IO;
const int N = 1e5 + 5;
int n, c[N << 1];
int main(){
freopen("h.in", "r", stdin);
while(~scanf("%d", &n)){
for(int i = 1; i <= n; i++){int w = read(), l = read(); c[i] = w - l;}
for(int i = n + 1; i <= 2 * n; i++) c[i] = c[i - n];
int pos, sum = 0, ans = 0; pos = 1;
for(int i = 1; i <= n; i++){
sum -= c[i - 1];
while(sum + c[pos] >= 0 && pos < i + n) sum += c[pos++];
ans = max(ans, pos - i);
}
wr(ans), putchar('
');
}
return 0;
}