• 51Nod1010解题报告


    题目地址:

      https://www.51nod.com/onlineJudge/questionCode.html#!problemId=1010

    题目概述:

      以后51Nod的题面都省略了。

    大致思路:

      读完题之后感觉水水的暴力啊,交了一发T,然后发现暴力爆精度了,改了精度WA,然后打算写另外一个暴力,TLE。

      看了一下数据,发现还是WA在了精度上,改了之后过了。

      不甘心的我去看了看正解,发现只含有2、3、5因子的数竟然不会超过343000!!!建议你们还是预处理加二分吧。

    代码:

    #include <iostream>
    #include <cstdio>
    #include <cstdlib>
    #include <cmath>
    #include <vector>
    #include <ctime>
    #include <map>
    #include <assert.h>
    #include <stack>
    #include <set>
    #include <bitset>
    #include <queue>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    
    #define sacnf scanf
    #define scnaf scanf
    #define scnafi scanfi
    #define pb push_back
    #define Len size()
    #define gchar getchar()
    #define FOR(i,j,k) for(int (i)=(j);(i)<=(k);(i)++)
    #define mes(a,b) memset((a),(b),sizeof(a))
    #define scanfi(a) scanf("%d",&(a))
    #define scanfti(a,b) scanf("%d%d",&(a),&(b))
    #define println(a) printf("%d
    ",(a))
    #define print_b printf("
    ")
    #define IsNum(x) '0'<=(x)&&(x)<='9'
    #define lt dir*2
    #define rt dir*2+1
    
    #define maxn 2000010
    #define maxm 26
    #define inf 1061109567
    //const long long inf=1e15;
    #define INF 0x3f3f3f3f
    #define eps 1e-9
    #define E 2.718281828459
    const double PI=acos(-1.0);
    #define mod 998244353
    #define MAXNUM 1000000000
    
    typedef long long ll;
    typedef unsigned long long ulld;
    ll Abs(ll x) {return (x<0)?-x:x;}
    int Read() {char ch;int res=0;while(ch=getchar(),!(IsNum(ch)));while(IsNum(ch)) res=res*10+ch-'0',ch=getchar();return res;}
    
    int main()
    {
        //freopen("data.in","r",stdin);
        //freopen("std.out","w",stdout);
        //clock_t st=clock();
        int T;scanfi(T);
        while(T--)
        {
            ll n,ans=-1;
            scanf("%I64d",&n);
            if(n==1) {printf("2
    ");continue;}
            int mx=59;ll t2=1,t3=1,t5=1,tmp=0,_tmp;
            FOR(i,0,mx)
            {
                FOR(j,0,mx)
                {
                    if(t2*t3<=0) break;
                    if(t2*t3>=n) {ans=min(ans,t2*t3);break;}
                    FOR(k,0,mx-i)
                    {
                        _tmp=tmp;tmp=t2*t3*t5;_tmp=tmp;
                        if(tmp<_tmp) break;             //68719476736 14348907 125
                        if(tmp>=n)
                        {
                            if(ans==-1||ans>tmp) ans=tmp;
                            break;
                        }
                        t5*=5;
                    }
                    t3*=3;t5=1;
                }
                t2*=2;t3=t5=1;
            }
            printf("%I64d
    ",ans);
        }
        //clock_t ed=clock();
        //printf("
    
    Time Used : %.5lf Ms.
    ",(double)(ed-st)/CLOCKS_PER_SEC);
        return 0;
    }
    /*506781279576915968*/
    /*507227047723008000*/
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  • 原文地址:https://www.cnblogs.com/CtrlKismet/p/7505849.html
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