Triangle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 0 Accepted Submission(s): 0Problem DescriptionMr. Frog has n sticks, whose lengths are 1,2, 3⋯n respectively. Wallice is a bad man, so he does not want Mr. Frog to form a triangle with three of the sticks here. He decides to steal some sticks! Output the minimal number of sticks he should steal so that Mr. Frog cannot form a triangle with
any three of the remaining sticks.InputThe first line contains only one integer T (T≤20), which indicates the number of test cases.
For each test case, there is only one line describing the given integer n (1≤n≤20).OutputFor each test case, output one line “Case #x: y”, where x is the case number (starting from 1), y is the minimal number of sticks Wallice should steal.Sample Input3 4 5 6Sample OutputCase #1: 1 Case #2: 1 Case #3: 2
题目链接:
http://acm.hdu.edu.cn/showproblem.php?pid=5914
题目大意:
给你1~N(N<=20)长度的木棒,求至少拿掉几根使得剩余的木棒构成不了三角形。
题目思路:
【模拟】
画画前几个就可以得出,剩下的木棒是斐波那契数列1,2,3,5,8,13。N只有20,打表。
1 // 2 //by coolxxx 3 //#include<bits/stdc++.h> 4 #include<iostream> 5 #include<algorithm> 6 #include<string> 7 #include<iomanip> 8 #include<map> 9 #include<stack> 10 #include<queue> 11 #include<set> 12 #include<bitset> 13 #include<memory.h> 14 #include<time.h> 15 #include<stdio.h> 16 #include<stdlib.h> 17 #include<string.h> 18 //#include<stdbool.h> 19 #include<math.h> 20 #define min(a,b) ((a)<(b)?(a):(b)) 21 #define max(a,b) ((a)>(b)?(a):(b)) 22 #define abs(a) ((a)>0?(a):(-(a))) 23 #define lowbit(a) (a&(-a)) 24 #define sqr(a) ((a)*(a)) 25 #define swap(a,b) ((a)^=(b),(b)^=(a),(a)^=(b)) 26 #define mem(a,b) memset(a,b,sizeof(a)) 27 #define eps (1e-10) 28 #define J 10000 29 #define mod 1000000007 30 #define MAX 0x7f7f7f7f 31 #define PI 3.14159265358979323 32 #pragma comment(linker,"/STACK:1024000000,1024000000") 33 #define N 104 34 using namespace std; 35 typedef long long LL; 36 double anss; 37 LL aans,sum; 38 int cas,cass; 39 int n,m,lll,ans; 40 int a[]={0,0,0,0,1,1,2,3,3,4,5,6,7,7,8,9,10,11,12,13,14}; 41 int main() 42 { 43 #ifndef ONLINE_JUDGEW 44 // freopen("1.txt","r",stdin); 45 // freopen("2.txt","w",stdout); 46 #endif 47 int i,j,k; 48 // init(); 49 // for(scanf("%d",&cass);cass;cass--) 50 for(scanf("%d",&cas),cass=1;cass<=cas;cass++) 51 // while(~scanf("%s",s)) 52 // while(~scanf("%d",&n)) 53 { 54 scanf("%d",&n); 55 printf("Case #%d: ",cass); 56 printf("%d ",a[n]); 57 } 58 return 0; 59 } 60 /* 61 // 62 63 // 64 */