• SQL综合练习(一)


    练习一: 各部门工资最高的员工(难度:中等)

    创建Employee 表,包含所有员工信息,每个员工有其对应的 Id, salary 和 department Id。

    +----+-------+--------+--------------+
    | Id | Name  | Salary | DepartmentId |
    +----+-------+--------+--------------+
    | 1  | Joe   | 70000  | 1            |
    | 2  | Henry | 80000  | 2            |
    | 3  | Sam   | 60000  | 2            |
    | 4  | Max   | 90000  | 1            |
    +----+-------+--------+--------------+
    

    创建Department 表,包含公司所有部门的信息。

    +----+----------+
    | Id | Name     |
    +----+----------+
    | 1  | IT       |
    | 2  | Sales    |
    +----+----------+
    CREATE TABLE employee(
    id int(11) NOT NULL,
    name VARCHAR(50) NOT NULL,
    salary DECIMAL(10,2) NOT NULL DEFAULT '0.00',
    departmentid int(11) NOT NULL,
    PRIMARY KEY (`id`)
    );
    
    INSERT INTO `employee` VALUES ('1', 'Joe', '70000.00', '1');
    INSERT INTO `employee` VALUES ('2', 'Herry', '80000.00', '2');
    INSERT INTO `employee` VALUES ('3', 'Sam', '60000.00', '2');
    INSERT INTO `employee` VALUES ('4', 'Max', '90000.00', '1');
    

    CREATE TABLE department( id int(11) NOT NULL, name VARCHAR(100) NOT NULL, PRIMARY KEY (`id`) ); INSERT INTO `department` VALUES ('1', 'IT'); INSERT INTO `department` VALUES ('2', 'Sales');

    编写一个 SQL 查询,找出每个部门工资最高的员工。例如,根据上述给定的表格,Max 在 IT 部门有最高工资,Henry 在 Sales 部门有最高工资。

    +------------+----------+--------+
    | Department | Employee | Salary |
    +------------+----------+--------+
    | IT         | Max      | 90000  |
    | Sales      | Henry    | 80000  |
    +------------+----------+--------+
    
    SELECT employee.*,t.name department,t.maxsal
    FROM employee
    INNER JOIN
    
    (SELECT employee.departmentid, department.`name`, MAX(salary) maxsal
    FROM employee
    INNER JOIN department
    ON employee.departmentid=department.id
    GROUP BY employee.departmentid, department.`name`) AS t
    
    ON employee.departmentid = t.departmentid
    
    WHERE employee.salary=t.maxsal
    1    IT    90000.00
    2    Sales    80000.00


    2    Herry    80000.00    2    Sales    80000.00
    4    Max    90000.00    1    IT    90000.00

    select Department.Name as Department,Employee.Name as Employee,Salary
    from Employee join Department
    on Employee.DepartmentId = Department.Id 
    where (Salary,DepartmentId) in 
    (select max(Salary),DepartmentId
    from Employee
    group by DepartmentId)

    90000.00    1
    80000.00    2

    Sales    Herry    80000.00
    IT    Max    90000.00

    练习二: 换座位(难度:中等)

    小美是一所中学的信息科技老师,她有一张 seat 座位表,平时用来储存学生名字和与他们相对应的座位 id。

    其中纵列的id是连续递增的

    小美想改变相邻俩学生的座位。

    你能不能帮她写一个 SQL query 来输出小美想要的结果呢?

    请创建如下所示seat表:

    示例:

    +---------+---------+
    |    id   | student |
    +---------+---------+
    |    1    | Abbot   |
    |    2    | Doris   |
    |    3    | Emerson |
    |    4    | Green   |
    |    5    | Jeames  |
    +---------+---------+
    

    假如数据输入的是上表,则输出结果如下:

    +---------+---------+
    |    id   | student |
    +---------+---------+
    |    1    | Doris   |
    |    2    | Abbot   |
    |    3    | Green   |
    |    4    | Emerson |
    |    5    | Jeames  |
    +---------+---------+
    

    注意:
    如果学生人数是奇数,则不需要改变最后一个同学的座位。

    SELECT
                CASE WHEN id = (SELECT MAX(id) FROM seat) THEN id#最后一个
                         WHEN MOD(id,2)=1 THEN id+1#奇数
                         WHEN MOD(id,2)=0 THEN id-1#偶数
                         ELSE NULL END AS id,
          student
     FROM seat
    ORDER BY id;
    SELECT (
        CASE
            #学生人数为奇数时,学生的id加一 
            WHEN MOD(id,2)!=0 AND id!=counts THEN id+1       
            #学生人数为奇数时,最后一个学生的id不变
            WHEN MOD(id,2)!=0 AND id=counts THEN id
            ELSE id-1 
        END )AS id,student
    from seat,(SELECT COUNT(*) AS counts FROM seat) AS seat_counts 
    ORDER BY id;
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  • 原文地址:https://www.cnblogs.com/Cookie-Jing/p/14888753.html
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