Hdu1097（计算a的b次幂最后一位数值）

#include <stdio.h>
#include <math.h> 
int main()
{
    int Num1,Num2;
    while(scanf("%d %d",&Num1,&Num2)!=EOF)
    {
        printf("%d
",getLastNum(Num1,Num2));    
    }    
    return 0;
}
// 求a的b次幂最后一位数字为什么 
int getLastNum(int a, int b)
{
    int n = b%4;
    int x = a%10;
    int lastNum = 0;
    if(n == 0)
    {
        lastNum = pow(x,4);
    }
    else
    {
        lastNum = pow(x,n);
    }
    lastNum = lastNum%10; 
    return lastNum;    
}