• 关于PHP数据库mysql的一些案例


    案例1:查询select
    使用php连接数据库class9,
    获取数据库的表student中的信息,
    然后输出到页面上(用表格套住)
     1 <?php
     2 header("Content-type:text/html; charset=utf-8");
     3 // 建立mysql的链接
     4 // 参数:主机名,用户,密码,需要的数据库
     5 /*
     6 在PHP函数方法前面加@符号,表示忽略警告
     7 */
     8 $conn =@mysqli_connect("localhost","root","","lanou0322");
     9 // 判断数据库链接是否成功
    10 /*if($conn){
    11 echo "成功了!";
    12 }else{
    13 echo "失败了!";
    14 }
    15 */
    16 if(!$conn){
    17 echo "失败";
    18 // 终止
    19 exit;
    20 }
    21 $conn->query('set names utf8');
    22 $sql ="SELECT * FROM student";
    23 $result = $conn->query($sql);
    24 // 5.判断
    25 // mysqli_num_rows 返回的条数
    26 // echo mysqli_num_rows($result);
    27 if(mysqli_num_rows($result)>0){
    28 echo "<table border=1>";
    29 echo "<tr>
    30 <th>id</th>
    31 <th>name</th>
    32 <th>sex</th>
    33 <th>age</th>
    34 </tr>";
    35 while($row = $result -> fetch_assoc()){
    36 echo "<tr>
    37 <td style='20'>{$row['id']}</td>
    38 <td style='80; text-align:center;'>{$row['name']}</td>
    39 <td style='20'>{$row['sex']}</td>
    40 <td style='20'>{$row['age']}</td>
    41 </tr>";
    42 }
    43 echo "</table>";
    44 //如果想在一个页面输出同样的两个数据库表格那么可以在执行一次$conn->query($sql);然后打印
    45 echo "<hr/>";
    46 $result = $conn->query($sql);
    47 echo "<table border=1>";
    48 echo "<tr>
    49 <th>id</th>
    50 <th>name</th>
    51 <th>sex</th>
    52 <th>age</th>
    53 </tr>";
    54 while($row = $result -> fetch_assoc()){
    55 echo "<tr>
    56 <td style='20'>{$row['id']}</td>
    57 <td style='80; text-align:center;'>{$row['name']}</td>
    58 <td style='20'>{$row['sex']}</td>
    59 <td style='20'>{$row['age']}</td>
    60 </tr>";
    61 }
    62 echo "</table>";
    63 }
    64 // 关闭数据库
    65 $conn->close();//关闭数据库
    66 
    67 ?>
    View Code
    效果:
    案例2:插入insert

    使用php连接数据库

    1. 向数据表student,插入一条信息:"小明", 28, "男"   添加成功输出提示"添加成功"
     
    2. 插入多条信息
     1 <?php
     2 header("Content-type:text/html;charset=utf-8");
     3 //链接数据库
     4 $conn =@mysqli_connect("localhost","root","","lanou0322");
     5 if(!$conn){
     6 echo "失败";
     7 // 终止
     8 exit;
     9 }
    10 $conn->query('set names utf8');
    11 //向数据库添加数据INSERT INTO name(数据表名) VALUE (添加的数据信息);
    12 $sql ="INSERT INTO student(name,sex,age) VALUES ('小黄','女','17')";
    13 $sql ="SELECT * FROM student";
    14 $result = $conn->query($sql);
    15 // 判断插入是否成功
    16 // 使用 mysqli_affected_rows($conn);
    17 if(mysqli_affected_rows($conn)>0){
    18 echo "成功";
    19 }else{
    20 echo "失败";
    21 }
    22 echo mysqli_num_rows($result);
    23 if(mysqli_num_rows($result)>0){
    24 echo "<table border=1>";
    25 echo "<tr>
    26 <th>id</th>
    27 <th>name</th>
    28 <th>sex</th>
    29 <th>age</th>
    30 </tr>";
    31 while($row = $result -> fetch_assoc()){
    32 echo "<tr>
    33 <td style='20'>{$row['id']}</td>
    34 <td style='80; text-align:center;'>{$row['name']}</td>
    35 <td style='20'>{$row['sex']}</td>
    36 <td style='20'>{$row['age']}</td>
    37 </tr>";
    38 }
    39 echo "</table>";
    40 }
    41     $conn->close();//关闭数据库
    42 ?>
    View Code
    效果:
    案例3:更新update
    使用php连接数据库
    更新(修改)数据表student中,年龄age=28的改为10
     1 <?php
     2 header("Content-type:text/html;charset=utf-8");
     3 $conn =@mysqli_connect("localhost","root","","lanou0322");
     4 $conn->query('set names utf8');
     5 // mysqli_query($conn,"UPDATA name SET... WHERE ...")
     6 $sql = mysqli_query($conn,"UPDATE student SET name = '我傻逼',age = '10' WHERE id = 1");
     7 $sql ="SELECT * FROM student";
     8 $result = $conn->query($sql);
     9 echo mysqli_affected_rows($conn);
    10 // 判断修改是否成功
    11 if(mysqli_affected_rows($conn)>0){
    12 echo "成功";
    13 }else{
    14 echo "失败";
    15 }
    16 echo mysqli_num_rows($result);
    17 if(mysqli_num_rows($result)>0){
    18 echo "<table border=1>";
    19 echo "<tr>
    20 <th>id</th>
    21 <th>name</th>
    22 <th>sex</th>
    23 <th>age</th>
    24 </tr>";
    25 while($row = $result -> fetch_assoc()){
    26 echo "<tr>
    27 <td style='20'>{$row['id']}</td>
    28 <td style='80; text-align:center;'>{$row['name']}</td>
    29 <td style='20'>{$row['sex']}</td>
    30 <td style='20'>{$row['age']}</td>
    31 </tr>";
    32 }
    33 echo "</table>";
    34 }
    35 $conn->close();
    36 ?>
    View Code
    效果:
    案例4:删除delete
    使用php连接数据库class9,
    删除数据库的表student中,id号为1的数据
     1 <?php
     2 header("Content-type:text/html;charset=utf-8");
     3 $conn =@mysqli_connect("localhost","root","","lanou0322");
     4 $conn->query('set names utf8');
     5 $sql = mysqli_query($conn,"DELETE FROM student WHERE id = 1");
     6 $sql ="SELECT * FROM student";
     7 $result = $conn->query($sql);
     8 // echo mysqli_affected_rows($conn);
     9 // 判断修改是否成功
    10 if(mysqli_affected_rows($conn)>0){
    11 echo "成功";
    12 }else{
    13 echo "失败";
    14 }
    15 // echo mysqli_num_rows($result);
    16 if(mysqli_num_rows($result)>0){
    17 echo "<table border=1>";
    18 echo "<tr>
    19 <th>id</th>
    20 <th>name</th>
    21 <th>sex</th>
    22 <th>age</th>
    23 </tr>";
    24 while($row = $result -> fetch_assoc()){
    25 echo "<tr>
    26 <td style='20'>{$row['id']}</td>
    27 <td style='80; text-align:center;'>{$row['name']}</td>
    28 <td style='20'>{$row['sex']}</td>
    29 <td style='20'>{$row['age']}</td>
    30 </tr>";
    31 }
    32 echo "</table>";
    33 }
    34 $conn->close();
    35 ?>
    View Code

    效果:

     



  • 相关阅读:
    在第一段ionic示例的基础上增加底部导航
    我的第一段ionic代码
    angularjs中ng-repeat的使用
    angular中$location读取url信息
    解决jenkins构建job报错“NoClassDefFoundError” in jenkins/scm/RunWithSCM问题
    完全卸载删除gitlab
    centos7端口永久开放方法
    eclipse解决maven编码UTF-8的不可映射字符
    Apache JMeter压力测试实例
    windows下安装setuptools与pip
  • 原文地址:https://www.cnblogs.com/ChenChunChang/p/6606835.html
Copyright © 2020-2023  润新知