【BZOJ2836】魔法树
Description
Input
Output
Sample Input
4
0 1
1 2
2 3
4
Add 1 3 1
Query 0
Query 1
Query 2
0 1
1 2
2 3
4
Add 1 3 1
Query 0
Query 1
Query 2
Sample Output
3
3
2
3
2
题解:链剖裸题+1,一棵子树对应DFS序上的一段区间。然而又没有1A
#include <cstdio> #include <cstring> #include <iostream> #define lson x<<1 #define rson x<<1|1 using namespace std; const int maxn=100010; int n,m,cnt; typedef long long ll; int to[maxn],next[maxn],head[maxn],p[maxn],q[maxn],siz[maxn],son[maxn],dep[maxn],top[maxn],fa[maxn]; ll s[maxn<<2],ts[maxn<<2]; char str[10]; int rd() { int ret=0,f=1; char gc=getchar(); while(gc<'0'||gc>'9') {if(gc=='-')f=-f; gc=getchar();} while(gc>='0'&&gc<='9') ret=ret*10+gc-'0',gc=getchar(); return ret*f; } void dfs1(int x) { siz[x]=1; for(int i=head[x];i!=-1;i=next[i]) { fa[to[i]]=x,dep[to[i]]=dep[x]+1; dfs1(to[i]); siz[x]+=siz[to[i]]; if(siz[son[x]]<siz[to[i]]) son[x]=to[i]; } } void dfs2(int x,int tp) { top[x]=tp,p[x]=++p[0]; if(son[x]) dfs2(son[x],tp); for(int i=head[x];i!=-1;i=next[i]) if(to[i]!=son[x]) dfs2(to[i],to[i]); q[x]=p[0]; } void pushdown(int l,int r,int x) { if(ts[x]) { int mid=l+r>>1; ts[lson]+=ts[x],ts[rson]+=ts[x],s[lson]+=(mid-l+1)*ts[x],s[rson]+=(r-mid)*ts[x]; ts[x]=0; } } void pushup(int x) { s[x]=s[lson]+s[rson]; } void updata(int l,int r,int x,int a,int b,ll v) { if(a<=l&&r<=b) { s[x]+=(r-l+1)*v,ts[x]+=v; return ; } pushdown(l,r,x); int mid=l+r>>1; if(a<=mid) updata(l,mid,lson,a,b,v); if(b>mid) updata(mid+1,r,rson,a,b,v); pushup(x); } ll query(int l,int r,int x,int a,int b) { if(a<=l&&r<=b) return s[x]; pushdown(l,r,x); int mid=l+r>>1; if(b<=mid) return query(l,mid,lson,a,b); if(a>mid) return query(mid+1,r,rson,a,b); return query(l,mid,lson,a,b)+query(mid+1,r,rson,a,b); } void add(int a,int b) { to[cnt]=b,next[cnt]=head[a],head[a]=cnt++; } void ADD(int x,int y,ll z) { while(top[x]!=top[y]) { if(dep[top[x]]<dep[top[y]]) swap(x,y); updata(1,n,1,p[top[x]],p[x],z); x=fa[top[x]]; } if(dep[x]>dep[y]) swap(x,y); updata(1,n,1,p[x],p[y],z); } int main() { n=rd(); int i,a,b; memset(head,-1,sizeof(head)); for(i=1;i<n;i++) a=rd()+1,b=rd()+1,add(a,b); dep[1]=1,dfs1(1),dfs2(1,1); m=rd(); for(i=1;i<=m;i++) { scanf("%s",str); if(str[0]=='A') a=rd()+1,b=rd()+1,ADD(a,b,rd()); else a=rd()+1,printf("%lld ",query(1,n,1,p[a],q[a])); } return 0; }