// 面试题68:树中两个结点的最低公共祖先 // 题目:输入两个树结点,求它们的最低公共祖先。 #include <iostream> #include "Tree.h" #include <list> using namespace std; bool GetNodePath(const TreeNode* pRoot, const TreeNode* pNode, list<const TreeNode*>& path)//找到根节点到指定节点的路径 { if (pRoot == pNode) return true; path.push_back(pRoot); bool found = false; vector<TreeNode*>::const_iterator i = pRoot->m_vChildren.begin();//m_vChildren是个数组,详见Tree.h while (!found && i < pRoot->m_vChildren.end()) { found = GetNodePath(*i, pNode, path); ++i; } if (!found) path.pop_back(); return found; } const TreeNode* GetLastCommonNode//找最后一个公共节点 ( const list<const TreeNode*>& path1, const list<const TreeNode*>& path2 ) { list<const TreeNode*>::const_iterator iterator1 = path1.begin(); list<const TreeNode*>::const_iterator iterator2 = path2.begin();//迭代器 const TreeNode* pLast = nullptr; while (iterator1 != path1.end() && iterator2 != path2.end()) { if (*iterator1 == *iterator2) pLast = *iterator1; iterator1++; iterator2++; } return pLast; } const TreeNode* GetLastCommonParent(const TreeNode* pRoot, const TreeNode* pNode1, const TreeNode* pNode2) { if (pRoot == nullptr || pNode1 == nullptr || pNode2 == nullptr)//判断边界 return nullptr; list<const TreeNode*> path1; GetNodePath(pRoot, pNode1, path1); list<const TreeNode*> path2; GetNodePath(pRoot, pNode2, path2); return GetLastCommonNode(path1, path2); } // ====================测试代码==================== void Test(const char* testName, const TreeNode* pRoot, const TreeNode* pNode1, const TreeNode* pNode2, TreeNode* pExpected) { if (testName != nullptr) printf("%s begins: ", testName); const TreeNode* pResult = GetLastCommonParent(pRoot, pNode1, pNode2); if ((pExpected == nullptr && pResult == nullptr) || (pExpected != nullptr && pResult != nullptr && pResult->m_nValue == pExpected->m_nValue)) printf("Passed. "); else printf("Failed. "); } // 形状普通的树 // 1 // / // 2 3 // / // 4 5 // / / | // 6 7 8 9 10 void Test1() { TreeNode* pNode1 = CreateTreeNode(1); TreeNode* pNode2 = CreateTreeNode(2); TreeNode* pNode3 = CreateTreeNode(3); TreeNode* pNode4 = CreateTreeNode(4); TreeNode* pNode5 = CreateTreeNode(5); TreeNode* pNode6 = CreateTreeNode(6); TreeNode* pNode7 = CreateTreeNode(7); TreeNode* pNode8 = CreateTreeNode(8); TreeNode* pNode9 = CreateTreeNode(9); TreeNode* pNode10 = CreateTreeNode(10); ConnectTreeNodes(pNode1, pNode2); ConnectTreeNodes(pNode1, pNode3); ConnectTreeNodes(pNode2, pNode4); ConnectTreeNodes(pNode2, pNode5); ConnectTreeNodes(pNode4, pNode6); ConnectTreeNodes(pNode4, pNode7); ConnectTreeNodes(pNode5, pNode8); ConnectTreeNodes(pNode5, pNode9); ConnectTreeNodes(pNode5, pNode10); Test("Test1", pNode1, pNode6, pNode8, pNode2); } // 树退化成一个链表 // 1 // / // 2 // / // 3 // / // 4 // / // 5 void Test2() { TreeNode* pNode1 = CreateTreeNode(1); TreeNode* pNode2 = CreateTreeNode(2); TreeNode* pNode3 = CreateTreeNode(3); TreeNode* pNode4 = CreateTreeNode(4); TreeNode* pNode5 = CreateTreeNode(5); ConnectTreeNodes(pNode1, pNode2); ConnectTreeNodes(pNode2, pNode3); ConnectTreeNodes(pNode3, pNode4); ConnectTreeNodes(pNode4, pNode5); Test("Test2", pNode1, pNode5, pNode4, pNode3); } // 树退化成一个链表,一个结点不在树中 // 1 // / // 2 // / // 3 // / // 4 // / // 5 void Test3() { TreeNode* pNode1 = CreateTreeNode(1); TreeNode* pNode2 = CreateTreeNode(2); TreeNode* pNode3 = CreateTreeNode(3); TreeNode* pNode4 = CreateTreeNode(4); TreeNode* pNode5 = CreateTreeNode(5); ConnectTreeNodes(pNode1, pNode2); ConnectTreeNodes(pNode2, pNode3); ConnectTreeNodes(pNode3, pNode4); ConnectTreeNodes(pNode4, pNode5); TreeNode* pNode6 = CreateTreeNode(6); Test("Test3", pNode1, pNode5, pNode6, nullptr); } // 输入nullptr void Test4() { Test("Test4", nullptr, nullptr, nullptr, nullptr); } int main(int argc, char* argv[]) { Test1(); Test2(); Test3(); Test4(); system("pause"); return 0; }