思路:挺裸的费用流,拆拆点就好啦。
#include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PII pair<int, int> #define y1 skldjfskldjg #define y2 skldfjsklejg using namespace std; const int N = 500 + 7; const int M = 5e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 1000000007; int n, m, edgenum, S, T, head[N], dist[N], pre[N]; bool vis[N]; struct Edge { int from, to, cap, flow, cost, next; } edge[M]; void init() { edgenum = 0; memset(head, -1, sizeof(head)); } void addEdge(int u, int v, int w, int c) { Edge E1 = {u, v, w, 0, c, head[u]}; edge[edgenum] = E1; head[u] = edgenum++; Edge E2 = {v, u, 0, 0, -c, head[v]}; edge[edgenum] = E2; head[v] = edgenum++; } bool SPFA(int s, int t) { queue<int> Q; memset(dist, INF, sizeof(dist)); memset(vis, false, sizeof(vis)); memset(pre, -1, sizeof(pre)); dist[s] = 0; vis[s] = true; Q.push(s); while(!Q.empty()) { int u = Q.front(); Q.pop(); vis[u] = false; for(int i = head[u]; i != -1; i = edge[i].next) { Edge E = edge[i]; if(dist[E.to] > dist[u] + E.cost && E.cap > E.flow) { dist[E.to] = dist[u] + E.cost; pre[E.to] = i; if(!vis[E.to]) { vis[E.to] = true; Q.push(E.to); } } } } return pre[t] != -1; } void MCMF(int s, int t, int &cost, int &flow) { flow = 0; cost = 0; while(SPFA(s, t)) { int Min = INF; for(int i = pre[t]; i != -1; i = pre[edge[i^1].to]) { Edge E = edge[i]; Min = min(Min, E.cap - E.flow); } for(int i = pre[t]; i != -1; i = pre[edge[i^1].to]) { edge[i].flow += Min; edge[i^1].flow -= Min; cost += edge[i].cost * Min; } flow += Min; } } int main() { init(); scanf("%d%d", &n, &m); S = 1, T = 2 * n; for(int i = 2; i < n; i++) addEdge(i, i + n, 1, 0); addEdge(1, 1 + n, inf, 0); addEdge(n, n + n, inf, 0); for(int i = 1; i <= m; i++) { int u, v, c; scanf("%d%d%d", &u, &v, &c); addEdge(u + n, v, 1, c); } int cost, flow; MCMF(S, T, cost, flow); printf("%d %d ", flow, cost); return 0; } /* */