• Codeforces 240F TorCoder 线段树


    TorCoder

    开26个线段树维护数量, 然后就没了。。

    #include<bits/stdc++.h>
    #define LL long long
    #define LD long double
    #define ull unsigned long long
    #define fi first
    #define se second
    #define mk make_pair
    #define PLL pair<LL, LL>
    #define PLI pair<LL, int>
    #define PII pair<int, int>
    #define SZ(x) ((int)x.size())
    #define ALL(x) (x).begin(), (x).end()
    #define fio ios::sync_with_stdio(false); cin.tie(0);
    
    using namespace std;
    
    const int N = 1e5 + 7;
    const int inf = 0x3f3f3f3f;
    const LL INF = 0x3f3f3f3f3f3f3f3f;
    const int mod = 1000000007;
    const double eps = 1e-8;
    const double PI = acos(-1);
    
    template<class T, class S> inline void add(T& a, S b) {a += b; if(a >= mod) a -= mod;}
    template<class T, class S> inline void sub(T& a, S b) {a -= b; if(a < 0) a += mod;}
    template<class T, class S> inline bool chkmax(T& a, S b) {return a < b ? a = b, true : false;}
    template<class T, class S> inline bool chkmin(T& a, S b) {return a > b ? a = b, true : false;}
    
    int n, m;
    char s[N];
    int cnt[26];
    
    struct SegmentTree {
    #define lson l, mid, rt << 1
    #define rson mid + 1, r, rt << 1 | 1
        int sum[N << 2], lazy[N << 2];
        inline void pull(int rt) {
            sum[rt] = sum[rt << 1] + sum[rt << 1 | 1];
        }
        inline void push(int rt, int l, int r) {
            if(~lazy[rt]) {
                int mid = l + r >> 1;
                sum[rt << 1] = lazy[rt] * (mid - l + 1);
                sum[rt << 1 | 1] = lazy[rt] * (r - mid);
                lazy[rt << 1] = lazy[rt];
                lazy[rt << 1 | 1] = lazy[rt];
                lazy[rt] = -1;
            }
        }
        void build(char c, int l, int r,  int rt) {
            lazy[rt] = -1;
            if(l == r) {
                sum[rt] = s[l] == c;
                return;
            }
            int mid = l + r >> 1;
            build(c, lson); build(c, rson);
            pull(rt);
        }
        void update(int L, int R, int val, int l, int r, int rt) {
            if(R < l || r < L || R < L) return;
            if(L <= l && r <= R) {
                sum[rt] = val * (r - l + 1);
                lazy[rt] = val;
                return;
            }
            push(rt, l, r);
            int mid = l + r >> 1;
            update(L, R, val, lson);
            update(L, R, val, rson);
            pull(rt);
        }
        int query(int L, int R, int l, int r, int rt) {
            if(R < l || r < L || R < L) return 0;
            if(L <= l && r <= R) return sum[rt];
            push(rt, l, r);
            int mid = l + r >> 1;
            return query(L, R, lson) + query(L, R, rson);
        }
    } Tree[26];
    
    
    int main() {
        freopen("input.txt", "r", stdin);
        freopen("output.txt", "w", stdout);
        scanf("%d%d", &n, &m);
        scanf("%s", s + 1);
        for(int i = 0; i < 26; i++) Tree[i].build(i + 'a', 1, n, 1);
        while(m--) {
            int L, R; scanf("%d%d", &L, &R);
            for(int i = 0; i < 26; i++) cnt[i] = Tree[i].query(L, R, 1, n, 1);
            int odd = -1;
            bool can = true;
            for(int i = 0; i < 26; i++) {
                if(cnt[i] & 1) {
                    if(~odd) {
                        can = false;
                        break;
                    } else odd = i;
                }
            }
            if(can) {
                for(int i = 0; i < 26; i++) Tree[i].update(L, R, 0, 1, n, 1);
                if(~odd) Tree[odd].update(L + R >> 1, L + R >> 1, 1, 1, n, 1), cnt[odd]--;
                int be = L, ed = R;
                for(int i = 0; i < 26; i++) {
                    cnt[i] >>= 1;
                    Tree[i].update(be, be + cnt[i] - 1, 1, 1, n, 1);
                    Tree[i].update(ed - cnt[i] + 1, ed, 1, 1, n, 1);
                    be += cnt[i];
                    ed -= cnt[i];
                }
            }
        }
        for(int i = 1; i <= n; i++) {
            for(int j = 0; j < 26; j++) {
                if(Tree[j].query(i, i, 1, n, 1)) {
                    s[i] = 'a' + j;
                    break;
                }
            }
        }
        puts(s + 1);
        return 0;
    }
    
    /*
    */
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  • 原文地址:https://www.cnblogs.com/CJLHY/p/10885262.html
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