在dfs的过程中枚举质因子瞎搞搞就好啦, 不过这个题意真的表述不清。。
#include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ull unsigned long long using namespace std; const int N = 1e5 + 7; const int M = 2e6 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 1e6 + 3; const double eps = 1e-8; int n, q, a[N], ans[N], depth[N]; bool prime[M]; vector<int> pfac[M]; vector<PII> Set[M]; vector<int> G[N]; void dfs(int u, int fa) { depth[u] = depth[fa] + 1; ans[u] = -1; for(auto& t : pfac[a[u]]) if(SZ(Set[t]) && (ans[u] == -1 || Set[t][SZ(Set[t])-1].fi > depth[ans[u]])) ans[u] = Set[t][SZ(Set[t])-1].se; for(auto& t : pfac[a[u]]) Set[t].push_back(mk(depth[u], u)); for(auto& v : G[u]) { if(v == fa) continue; dfs(v, u); } for(auto& t : pfac[a[u]]) Set[t].pop_back(); } int main() { memset(prime, true, sizeof(prime)); prime[0] = prime[1] = false; for(int i = 2; i < M; i++) { if(!prime[i]) continue; pfac[i].push_back(i); for(int j = i + i; j < M; j += i) prime[j] = false, pfac[j].push_back(i); } scanf("%d%d", &n, &q); for(int i = 1; i <= n; i++) scanf("%d", &a[i]); for(int i = 1; i < n; i++) { int u, v; scanf("%d%d", &u, &v); G[u].push_back(v); G[v].push_back(u); } dfs(1, 0); while(q--) { int op, v, w; scanf("%d%d", &op, &v); if(op == 1) { printf("%d ", ans[v]); } else { scanf("%d", &w); a[v] = w; dfs(1, 0); } } return 0; } /* */