• 2018 ACM-ICPC, Syrian Collegiate Programming Contest F


    #include<bits/stdc++.h>
    #define LL long long
    #define fi first
    #define se second
    #define mk make_pair
    #define PLL pair<LL, LL>
    #define PLI pair<LL, int>
    #define PII pair<int, int>
    #define SZ(x) ((int)x.size())
    #define ull unsigned long long
    using namespace std;
    
    const int N = 2e5 + 7;
    const int inf = 0x3f3f3f3f;
    const LL INF = 0x3f3f3f3f3f3f3f3f;
    const int mod = 1e9 + 7;
    const double eps = 1e-3;
    const double PI = acos(-1);
    
    int T, m, n, up, dp2[1<<20], dp[1<<20], pre[1<<20];
    char s[100];
    vector<int> ans;
    
    int main() {
    //    freopen("tests.in", "r", stdin);
        scanf("%d", &T);
        while(T--) {
            ans.clear();
            scanf("%d%d", &m, &n);
            up = 1 << m;
            for(int i = 0; i < up; i++) dp2[i] = 0, dp[i] = inf;
            for(int i = 0; i < n; i++) {
                scanf("%s", s); int x = 0;
                for(int j = 0; j < m; j++)
                    if(s[j] == '1') x += 1 << j;
                dp2[x]++;
            }
            for(int i = 0; i < m; i++)
                for(int s = 0; s < up; s++)
                    if(s>>i&1) dp2[s^(1<<i)] += dp2[s];
            dp[0] = 0;
            for(int s = 0; s < up; s++) {
                for(int i = 0; i < m; i++) {
                    if(s>>i&1) continue;
                    int nexs = s | (1<<i);
                    if(dp[s]+dp2[s] < dp[nexs]) {
                        dp[nexs] = dp[s]+dp2[s];
                        pre[nexs] = s;
                    }
                }
            }
            int nows = up-1, nexs;
            while(nows) {
                nexs = pre[nows];
                int xo = nexs ^ nows;
                for(int i = 0; i < m; i++) {
                    if(1<<i == xo) {
                        ans.push_back(i+1);
                        break;
                    }
                }
                nows = nexs;
            }
            reverse(ans.begin(), ans.end());
            printf("%d
    ", dp[up-1]);
            for(int t : ans) printf("%d ", t);
            puts("");
        }
        return 0;
    }
    /*
    */
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  • 原文地址:https://www.cnblogs.com/CJLHY/p/10200426.html
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