• 【杭电】[1213]How Many Tables


    How Many Tables

    Time Limit: 2000/1000 MS (Java/Others)

    Memory Limit: 65536/32768 K (Java/Others)

    Problem Description

    Today is Ignatius’ birthday. He invites a lot of friends. Now it’s dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay with strangers.

    One important rule for this problem is that if I tell you A knows B, and B knows C, that means A, B, C know each other, so they can stay in one table.

    For example: If I tell you A knows B, B knows C, and D knows E, so A, B, C can stay in one table, and D, E have to stay in the other one. So Ignatius needs 2 tables at least.

    Input

    The input starts with an integer T(1<=T<=25) which indicate the number of test cases. Then T test cases follow. Each test case starts with two integers N and M(1<=N,M<=1000). N indicates the number of friends, the friends are marked from 1 to N. Then M lines follow. Each line consists of two integers A and B(A!=B), that means friend A and friend B know each other. There will be a blank line between two cases.

    Output

    For each test case, just output how many tables Ignatius needs at least. Do NOT print any blanks.

    Sample Input

    2
    5 3
    1 2
    2 3
    4 5

    5 1
    2 5

    Sample Output

    2
    4

    基础并查集题目

    合并同关系的

    然后查找共有多少顶点(i==find(i))

    #include<stdio.h>
    int par[1200];
    int find(int m) {
        if(m==par[m])
            return m;
        else
            return par[m]=find(par[m]);
    }
    void unite(int x,int y) {
        x=find(x);
        y=find(y);
        if(x==y)
            return ;
        else
            par[y]=x;
    }
    int main() {
        int T;
        scanf("%d",&T);
        while(T--) {
            int n,m;
            scanf("%d %d",&n,&m);
            for(int i=1; i<=n; i++)
                par[i]=i;
            while(m--) {
                int a,b;
                scanf("%d %d",&a,&b);
                unite(a,b);
            }
            int res=0;
            for(int i=1; i<=n; i++)
                if(i==find(i))
                    res++;
            printf("%d
    ",res);
        }
        return 0;
    }

    题目地址:【杭电】[1213]How Many Tables
  • 相关阅读:
    Codeforces Ilya and Matrix
    poj 1308 Is It A Tree?
    Codeforces Sereja and Array
    poj 1041 John's trip
    Codeforces Continued Fractions
    WM_COPYDATA实现进程间数据通信
    虚拟机中安装ubuntu后,终端模式和图形模式切换
    IIS上配置运行cgi,php,aspx运行环境
    linux c main函数参数
    Linux网络编程入门 (转载)
  • 原文地址:https://www.cnblogs.com/BoilTask/p/12569448.html
Copyright © 2020-2023  润新知