pat1061-1070

1061 我想吐槽这题的题意不够清楚，不过下次得长记性，对于模糊的题意要大胆猜测，而不是固执己见

#include<iostream>
#include<cstdio>
#include<map>
#include<cstring>
using namespace std;

char a[4][65];
char week[10][10] = {"MON", "TUE", "WED", "THU","FRI","SAT", "SUN"};
int main() {
    map<char, int > mp;
    for(int i = 0; i < 4; ++i) {
        gets(a[i]);
    }

    char t1 = 0,t2 = 0; int t3 = 0;
    int l1 = strlen(a[0]); int l2= strlen(a[1]);

    int pos;
    for(int i = 0; i < min(l1, l2); ++i) {
        if(a[0][i] == a[1][i] && a[0][i] >= 'A' && a[0][i] <= 'G') {
            t1 = a[0][i];
            pos = i;
            break;
          //  t3 = i; break;
        }
    }

    for(int i = pos+1; i < min(l1, l2); ++i) {
        if(a[0][i] == a[1][i] && ( (a[0][i] >= 'A' && a[0][i] <= 'N') || (a[0][i] >= '0' && a[0][i] <= '9')) ) {
            t2 = a[0][i];
            break;
          //  t3 = i; break;
        }
    }

    l1 = strlen(a[2]); l2= strlen(a[3]);
    for(int i = min(l1, l2)-1; i >= 0; --i) {
        if(a[2][i] == a[3][i] && ( (a[2][i] >= 'a' && a[2][i] <= 'z') || (a[2][i] >= 'A' && a[2][i] <= 'Z') ) ){
            t3 = i; break;
        }
    }

    int t4;
    if(t2 >= 'A' && t2 <='Z') t4 = t2-'A'+10;
    else t4 = t2-'0'+0;

  //  printf("%c %c
", t1,t2);
    printf("%s %02d:%02d
", week[t1-'A'], t4, t3);
    return 0;
}

1062

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1e5+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int n, l, h;
struct Node{
  int num, vir, tal;
  Node(int a=0, int b=0, int c=0):num(a), vir(b), tal(c){}
}E[N];
int tot;
int jud(Node x) {
  if(x.vir >= h && x.tal >= h) return 1;
  else if(x.vir >= h) return 2;
  else if(x.tal < h && x.tal <= x.vir) return 3;
  else return 4;
}
int cmp(Node a, Node b) {
  int tya = jud(a); int tyb = jud(b);
  if(tya != tyb) return tya < tyb;
  else if(a.vir+a.tal != b.vir+b.tal) 
    return a.vir+a.tal > b.vir+b.tal;
  else if(a.vir != b.vir)
    return a.vir > b.vir;
  else return a.num < b.num;
}

int main() {
  while(~scanf("%d %d %d", &n, &l, &h)) {
    tot = 0;
    for(int i = 0; i < n; ++i) {
      int a, b, c; scanf("%d %d %d", &a, &b, &c);
      if(c < l || b < l) continue;
      E[++tot] = Node(a, b, c);
    }  
    sort(E+1, E+tot+1, cmp);

    printf("%d
", tot);
    for(int i = 1; i <= tot; ++i) printf("%08d %d %d
", E[i].num, E[i].vir, E[i].tal);
  }
  return 0;
}

1063

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1e5+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

set<int> st[55];
set<int> ::iterator it;
double mp[55][55];
int main() {
  int n, k;
  while(~scanf("%d", &n)) {
    for(int i = 1; i <= n; ++i) {
      int m; scanf("%d", &m);
      for(int j = 0; j < m; ++j) {
        int a; scanf("%d", &a);
        st[i].insert(a);
      }
    }
    scanf("%d", &k);
    set<int> s;
    for(int i = 0; i < k; ++i) {
      int a, b; scanf("%d %d", &a, &b);
      if(a > b) swap(a, b);
      if(mp[a][b] != 0) {
        printf("%.1f%%
", mp[a][b]);
        continue;
      }
      int all = st[b].size();
      for(it = st[a].begin(); it != st[a].end(); ++it) {
        if(st[b].find(*it) == st[b].end()) {
          all ++;
        }
      }
      mp[a][b] = (st[a].size()+st[b].size() - all)*100.0/all;
      printf("%.1f%%
", mp[a][b]);
    }
  }
  return 0;

1064

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1e3+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int n;
int a[N];
int Rank[N]; int tot;

int L[N], R[N];

void dfs(int x) {
//  printf("hh %d
", x);
  if(2*x <= n) {
    L[x] = 2*x; dfs(2*x); 
  }
  if(2*x+1 <= n) {
    R[x] = 2*x+1; dfs(2*x+1);
  }
}
void _dfs(int x) {
//  printf("%d
", x);
  if(L[x]) _dfs(L[x]);
  Rank[x] = ++tot;
  if(R[x]) _dfs(R[x]);
}
void bfs(int x) {
  queue<int> Q;
  Q.push(x);
  while(!Q.empty()) {
    int tt = Q.front(); Q.pop();
    if(tt != x) printf(" ");
    printf("%d", a[Rank[tt]]);

    if(L[tt]) Q.push(L[tt]);
    if(R[tt]) Q.push(R[tt]);
  }
  printf("
");
}
int main() {
  while(~scanf("%d", &n)) {
    memset(L, 0, sizeof(L));
    memset(R, 0, sizeof(R));
    tot = 0;

    for(int i = 1; i <= n; ++i) scanf("%d", &a[i]);
    sort(a+1, a+n+1);

    dfs(1);
    _dfs(1);
  //  for(int i = 1; i <= n; ++i) printf("%d ", Rank[i]); printf("
");
    bfs(1);

  }
  return 0;
}

1065 这题偷了懒 = = ，写java也过不了就很气。其实我看网上的题解还是有缺陷的，等我又时间写个大数减法

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1e3+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int main() {
  int t; scanf("%d", &t);
  ll a,b,c;
  for(int _=1; _<=t; ++_) {
    scanf("%lld %lld %lld", &a, &b, &c);
    ll tmp = a+b;


    printf("Case #%d: ",_);
    if( (a>0 && b>0 && tmp<=0) || ( ( a + b > c) && !(a<0 && b<0 && tmp>=0) ) ) printf("true
");
    else printf("false
");
  }
  return 0;
}

1066avl问题，做pat历史上用的时间最多的一次，我的算法其实是自己xjb想的，有机会尝试下别人的算法

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 100;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int root;
int num[N];
int L[N], R[N], fa[N];

void insert(int x, int tag) {
//  printf("tag: %d
", x);
  if(!root) {
    root = tag; fa[tag] = tag; return; 
  }
  if(num[x] > num[tag]) {
    if(!L[x])  L[x] = tag, fa[tag] = x;
    else insert(L[x], tag);
  }else {
    if(!R[x])  R[x] = tag, fa[tag] = x;
    else insert(R[x], tag);
  }
}


struct Node{
  int po, val;
  Node(int a=0, int b=0):po(a), val(b){}
}E[10];
int cmp(Node a,Node b) {
  return a.val < b.val;
}

void LL(int x) {
//  printf("LL
");
  int fart = fa[fa[x]];
  int t1 = x; int t2 = R[x]; int t3 = fa[x];
  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  R[t1] = t3; fa[t3] = t1;
  L[t3] = t2; fa[t2] = t3;

  if(t3 == root) {
    root = t1; fa[t1] = t1;
  }else if(L[fart] == t3) {
    L[fart] = t1; fa[t1] = fart;
  }else R[fart] = t1, fa[t1] = fart;
}
void RR(int x) {
//  printf("RR
");
  int fart = fa[fa[x]];
  int t1 = x; int t2 = L[x]; int t3 = fa[x];
  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  L[t1] = t3; fa[t3] = t1;
  R[t3] = t2; fa[t2] = t3;

  if(t3 == root) {
    root = t1; fa[t1] = t1;
  }else if(L[fart] == t3) {
    L[fart] = t1; fa[t1] = fart;
  }else R[fart] = t1, fa[t1] = fart;
}
void LR(int x, int tag) {
//  printf("LR
");

  int fart = fa[fa[x]];
  int t1 = x; int t2 = R[x]; int t3 = fa[x];
  int a1 = L[t2]; int a2 = R[t2];

  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  R[t1] = 0; L[t3] = 0;
  L[t2] = t1; fa[t1] = t2;
  R[t2] = t3; fa[t3] = t2;
     if(t3 == root) {
    root = t2; fa[t2] = t2;
  }else if(L[fart] == t3) {
    L[fart] = t2; fa[t2] = fart;
  }else {
    R[fart] = t2; fa[t2] = fart;
  }

  if(a1) insert(root, a1);
  if(a2) insert(root, a2);
}
void RL(int x, int tag) {
//  printf("RL
");
  int fart = fa[fa[x]];
  int t1 = x; int t2 = L[x]; int t3 = fa[x];
  int a1 = L[t2]; int a2 = R[t2];

  L[t1] = 0; R[t3] = 0;
  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  L[t2] = t3; fa[t3] = t2;
  R[t2] = t1; fa[t1] = t2;
  //   printf("hh %d %d %d
", num[t1], num[t2], num[t3]);
  if(t3 == root) {
    root = t2; fa[t2] = t2;
  }else if(L[fart] == t3) {
    L[fart] = t2; fa[t2] = fart;
  }else {
    R[fart] = t2; fa[t2] = fart;
  }
//  printf("hh %d %d", fart, R[fart]);
  if(a1) insert(root, a1);
  if(a2) insert(root, a2);
}
void fix(int x) {
  int rt = fa[fa[x]]; int fart = fa[rt];
  if( (L[rt]==0) + (R[rt]==0) == 1) {
    int tot = 0;
    for(int i = 0, tt = x; i < 3; ++i) {
      E[tot++] = Node(tt, num[tt]); 
      tt = fa[tt];
    }  
    sort(E, E+tot, cmp);
    L[E[1].po] = E[0].po; fa[E[0].po] = E[1].po;  
    R[E[1].po] = E[2].po; fa[E[2].po] = E[1].po;
    L[E[0].po] = 0; R[E[0].po] = 0;
    L[E[2].po] = 0; R[E[2].po] = 0;

    if(root == rt) {
      root = E[1].po; fa[root] = root;
    }else if(L[fart] == rt) {
      L[fart] = E[1].po; fa[E[1].po] = fart;
    }else {
      R[fart] = E[1].po; fa[E[1].po] = fart;
    }
  }else {
  //  printf("%d %d %d
", x, rt, fa[rt]);
    if     (L[fa[rt]] == rt && L[rt] == fa[x] ) LL(rt);
    else if(R[fa[rt]] == rt && R[rt] == fa[x] ) RR(rt);
    else if(L[fa[rt]] == rt && R[rt] == fa[x] ) LR(rt, x);
    else if(R[fa[rt]] == rt && L[rt] == fa[x] ) RL(rt, x);
  }
}
void test(int x, int pre) {
  printf("%d from %d
", x, pre);
  if(L[x]) test(L[x], x);
  if(R[x]) test(R[x], x);
}

int height[N]; int tag;
void dfs(int x) {
  int t1 = 0, t2 = 0;
  if(L[x]) dfs(L[x]), t1 = height[L[x]];
     if(R[x]) dfs(R[x]), t2 = height[R[x]];
  height[x] = max(t1, t2)+1;
  if( abs(t1- t2) > 1  && !tag) tag = x;
}
void solve(int x) {
//  printf("do %d
", x);
  memset(height, 0, sizeof(height));
  tag = 0;
  dfs(root);
  if(tag) {
    int t1 = tag;
    if(height[L[t1]] > height[R[t1]]) t1 = L[t1];
    else t1 = R[t1];

    if(height[L[t1]] > height[R[t1]]) t1 = L[t1];
    else t1 = R[t1];

    if(height[L[t1]] > height[R[t1]]) t1 = L[t1];
    else if(height[L[t1]] < height[R[t1]]) t1 = R[t1];

  //  printf("%d %d
", tag, t1);
    fix(t1);
  }
//  test(root, root);
//  printf("
");
}
int main() {
  int n;
  while(~scanf("%d", &n)) {
    root = 0;
    memset(fa, 0, sizeof(fa));
    memset(L, 0, sizeof(L));
    memset(R, 0, sizeof(R));

    for(int i = 1; i <= n; ++i) {
      scanf("%d", &num[i]);
      insert(root, i);
      solve(i);
    //  fa[root] = root;
    //  check(root);
    }

    printf("%d
", num[root]);
  }
  return 0;
}

1067好题啊，这道，需要思考如何贪心，最后想到并查集。一个集合的算一次

#include<iostream>
#include<cstdio>
#include<cstring>
#include<vector>
#include<cmath>
#include<queue>
#include<algorithm>
#include<ctime>
#include<cstdlib>
#include<map>
#include<set>

using namespace std;
const int INF = 0x3f3f3f3f;
const int N = 1e5+5;
typedef long long ll;
#define MP(x, y) make_pair(x, y);


int n;
int a[N];
int pre[N];
int cnt[N];
int fa(int x) {
  return x==pre[x]? x: pre[x] = fa(pre[x]);
}
int main() {
  while(~scanf("%d", &n)) {
    memset(cnt, 0, sizeof(cnt));
    int ans = 0;
    for(int i = 1; i <= n; ++i) pre[i] = i;

    for(int i = 1; i <= n; ++i) {
      scanf("%d", &a[i]), a[i] ++;
      int t1 = fa(a[i]); int t2 = fa(i);

      if(t1 != t2) {
        pre[t1] = t2;
      }
    }

    for(int i = 1; i <= n; ++i) {
      cnt[fa(i)] ++;
    }

    for(int i = 1; i <= n; ++i) {
      if(cnt[i] > 1) ans += cnt[i]+1;  
    }

    if(a[1] != 1) ans -= 2;


    printf("%d
", ans);
  }
  return 0;
}

1068 dp一下就行

#include<iostream>
#include<cstdio>
#include<cstring>
#include<vector>
#include<cmath>
#include<queue>
#include<algorithm>
#include<ctime>
#include<cstdlib>
#include<map>
#include<set>

using namespace std;
const int INF = 0x3f3f3f3f;
const int N = 1e4+5;
typedef long long ll;
#define MP(x, y) make_pair(x, y);

int coin[N];
vector<int> dp[105];


int cmp(vector<int> &a, vector<int> &b) {
  if(a.size() == 0) return 0;
  else if(b.size() == 0) return 1;

  for(int i = 0; i < min(a.size(), b.size()); ++i) {
    if(a[i] != b[i])
      return a[i] < b[i];
  }
  return a.size() < b.size();
}


int main() {
  int n, m;
  while(~scanf("%d %d", &n, &m)) {
    for(int i = 1; i <= n; ++i) scanf("%d", &coin[i]);
    for(int i = 1; i <= m; ++i) dp[i].clear();

    sort(coin+1, coin+n+1);
    vector<int> tmp;
    for(int i = 1; i <= n; ++i) {
      for(int j = m; j >= 1; --j) {
        if(j-coin[i] > 0 ) {
          if(dp[j- coin[i]].size() == 0) continue;
          tmp.clear(); copy(dp[j-coin[i]].begin(), dp[j-coin[i]].end(), back_inserter(tmp));
          tmp.push_back(coin[i]);

          if( cmp(dp[j], tmp) == 0) dp[j].swap(tmp);
        }else break;
      }

      tmp.clear(); tmp.push_back(coin[i]);
      if(coin[i] <= m && cmp(dp[coin[i]], tmp) == 0) dp[coin[i]].swap(tmp);
    }
    if(dp[m].size() == 0) {
      printf("No Solution
");
      continue;
    }

    for(int i = 0; i < dp[m].size(); ++i) {
      if(i) printf(" ");
      printf("%d", dp[m][i]);
    } 
    printf("
");
  }
  return 0;
} 

1069

#include<iostream>
#include<cstdio>
#include<cstring>
#include<vector>
#include<cmath>
#include<queue>
#include<algorithm>
#include<ctime>
#include<cstdlib>
#include<map>
#include<set>

using namespace std;
const int INF = 0x3f3f3f3f;
const int N = 1e4+5;
typedef long long ll;
#define MP(x, y) make_pair(x, y);

int main() {
  int n;
  while(~scanf("%d", &n)) {

    while(1) {
      int tmp = n;
      vector<int> vc;
      while(tmp) {
        vc.push_back(tmp%10);
        tmp /= 10;
      }
      if(vc.size() < 4) {
        int ed = 4-vc.size();
        for(int i = 0; i < ed; ++i) vc.push_back(0);
      }
      sort(vc.begin(), vc.end());
      int t1 = 0, t2 = 0;
      for(int i = 0; i < vc.size(); ++i) {
        t1 = t1*10 + vc[i];
      }
      for(int i = vc.size()-1; i >= 0; --i) {
        t2 = t2*10 + vc[i];
      }
      int _n = t2 - t1;
      n = _n;
      printf("%04d - %04d = %04d
", t2, t1, _n);

      if(_n == 0 || _n == 6174) break;
    }
  }
  return 0;
}

1070

#include<iostream>
#include<cstdio>
#include<cstring>
#include<vector>
#include<cmath>
#include<queue>
#include<algorithm>
#include<ctime>
#include<cstdlib>
#include<map>
#include<set>

using namespace std;
const int INF = 0x3f3f3f3f;
const int N = 1e3+5;
typedef long long ll;
#define MP(x, y) make_pair(x, y);

struct Node{
  double ton; double price;
}E[N];
int cmp(Node a, Node b) {
  double t1 = a.ton*1.0 / a.price;
  double t2 = b.ton*1.0 / b.price;
  return t1 < t2;
}
int main() {
  int n; double  d;
  while(~scanf("%d %lf", &n, &d)) {
    for(int i = 0; i < n; ++i) {
      scanf("%lf", &E[i].ton);
    }
    for(int i = 0; i < n; ++i) {
      scanf("%lf", &E[i].price);
  //    printf("%.2f
", E[i].ton / E[i].price);
    }
//    for(int i = 0; i < n; ++i) printf("%d ", E[i].ton); printf("
");

    sort(E, E+n, cmp);

    double aton = 0; double pro = 0;
    for(int i = 0; i < n; ++i) {
      aton += E[i].ton; pro += E[i].price;  
      if(aton >= d) {
      //  printf("%d
", aton-d)
        pro -= (aton-d)*E[i].price/ E[i].ton;
        break;
      }

    }
    printf("%.2f
", pro);

  }
  return 0;
}