• ZOJ 3705 Applications 模拟


    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("in.txt","r",stdin);
        freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    const int maxn=505;
    const double eps=1e-8;
    int isprime(int n)
    {
        if(n==1||n==0)return 0;
        if(n==2)return 1;
        for(int i=2;i*i<=n;i++)
            if(n%i==0)return false;
        return true;
    }
    struct APP
    {
        char name[50];
        char belong[50];
        char sex;
        vector<int> solved;
        vector<int> rating;
        double score;
        bool operator < (const APP &ant ) const
        {
            if(fabs(score-ant.score)>eps) return score>ant.score;
            else return strcmp(name,ant.name)<0?1:0;
        }
    }da[maxn];
    map<string,int> prize;
    int prob[10005];
    int n,m;
    
    void cal()
    {
        for(int i=1;i<=n;i++)
        {
            da[i].score=0;
            for(int j=0;j<da[i].solved.size();j++)
            {
                int id=da[i].solved[j];
                if(prob[id]==1) da[i].score+=2.5;
                else if(prob[id]==2) da[i].score+=1.5;
                else if(isprime(id)) da[i].score+=1;
                else da[i].score+=0.3;
            }
            int x=prize[string(da[i].belong)];
            if(x!=0&&x<=3) da[i].score+= (5-x)*9;
    
            int rat;
            if(da[i].rating.size()>=3)
                rat=max(1200,da[i].rating[2]);
            else rat=1200;
    
            da[i].score+= (rat-1200)/100.0*1.5;
    
            if(da[i].sex=='F') da[i].score += 33;
        }
        sort(da+1,da+n+1);
    }
    int main()
    {
        int t;
        scanf("%d",&t);
        for(int ca=1;ca<=t;ca++)
        {
            scanf("%d%d",&n,&m);
            memset(prob,0,sizeof(prob));
            for(int i=1;i<=2;i++)
            {
                int x; scanf("%d",&x);
                for(int j=1;j<=x;j++)
                {
                    int a; scanf("%d",&a);
                    prob[a]=i;
                }
            }
            int teamnum;
            scanf("%d",&teamnum);
            prize.clear();
            for(int i=1;i<=teamnum;i++)
            {
                char s[50];
                int x;
                scanf("%s%d",s,&x);
                prize[string(s)]=x;
            }
    
            for(int i=1;i<=n;i++)
            {
                da[i].solved.clear();
                da[i].rating.clear();
                scanf("%s%s",da[i].name,da[i].belong);
                da[i].sex=getch();
                int a,b; scanf("%d%d",&a,&b);
                for(int j=1;j<=a;j++)
                {
                    int id; scanf("%d",&id);
                    da[i].solved.push_back(id);
                }
                for(int j=1;j<=b;j++)
                {
                    int rat; scanf("%d",&rat);
                    da[i].rating.push_back(rat);
                }
                sort(da[i].rating.begin(),da[i].rating.end(),greater<int>());
            }
            cal();
    
            for(int i=1;i<=m;i++)
            {
                printf("%s %.3lf
    ",da[i].name,da[i].score);
            }
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3713642.html
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