• POJ 1065 Wooden Sticks Greed,DP


    排序后贪心或根据第二关键字找最长下降子序列

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("in.txt","r",stdin);
        freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    const int maxn=5005;
    struct node
    {
        int l,w;
        bool operator < (const node &ant) const
        {
            return l<ant.l||l==ant.l&&w<ant.w;
        }
    };
    node da[maxn];
    int vis[maxn];
    int main()
    {
        int t;
        scanf("%d", &t);
        for(int ca = 1; ca <= t; ca++)
        {
            int n;
            scanf("%d", &n);
            for(int i = 0; i < n; i++)
                scanf("%d%d", &da[i].l, &da[i].w);
            sort(da, da + n);
            memset(vis,0,sizeof(vis));
            int res=0;
            for(int cnt=0;;)
            {
                res++;
                int curl=-1,curw=-1;
                for(int i=0;i<n;i++)
                {
                    if(!vis[i]&&da[i].l>=curl&&da[i].w>=curw)
                    {
                        vis[i] = 1; cnt++;
                        curl=da[i].l;curw=da[i].w;
                    }
                }
                if(cnt==n)break;
            }
            printf("%d
    ",res);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3713636.html
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