• UVA 1391 Astronauts 2-sat


    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<int,int> pii;
    #define pb(a) push(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("d:\in1.txt","r",stdin);
        freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    
    struct Edge
    {
        int u,v;
    };
    const double eps=10e-6;
    const int maxn=100005;
    double x;
    
    int age[maxn];
    
    struct TwoSat
    {
        int n;
        int mark[maxn*2];
        vector<int> g[maxn*2];
        int s[maxn],c;
    
        void init(int n)
        {
            this->n=n;
            for(int i=0;i<n*2;i++)
                g[i].clear();
            memset(mark,0,sizeof(mark));
        }
        void add_clause(int u,int v)
        {
            g[u].push_back(v);
        }
    
        bool dfs(int u)
        {
            if(mark[u^1])return false;
            if(mark[u])return true;
            mark[u]=1;
            s[c++]=u;
    
            for(int i=0;i<g[u].size();i++)
            {
                if(!dfs(g[u][i]))return false;
            }
            return true;
        }
    
        bool solve()
        {
            for(int i=0;i<n*2;i+=2)
            {
                if(!mark[i]&&!mark[i+1])
                {
                    c=0;
                    if(!dfs(i))
                    {
                        while(c)mark[s[--c]]=0;
                        if(!dfs(i+1))return false;
                    }
                }
            }
            return true;
        }
    };
    
    int n,m;
    TwoSat solver;
    
    
    bool same(int a,int b)
    {
        if(age[a]>=x&&age[b]>=x)return true;
        if(age[a]<x&&age[b]<x)return true;
        return false;
    }
    int main()
    {
        while(scanf("%d%d",&n,&m)!=EOF&&(n||m))
        {
            x=0;
            solver.init(n);
            for(int i=0;i<n;i++)
            {
                scanf("%d",&age[i]);
                x+=age[i];
            }
            x/=n;
    
            for(int i=0;i<m;i++)
            {
                int u,v;
                scanf("%d%d",&u,&v);
                u--;v--;
                if(same(u,v))
                {
                    solver.add_clause(u*2,v*2+1);
                    solver.add_clause(u*2+1,v*2);
                    solver.add_clause(v*2,u*2+1);
                    solver.add_clause(v*2+1,u*2);
                }else
                {
                    solver.add_clause(u*2,v*2+1);
                    solver.add_clause(v*2,u*2+1);
                }
            }
            bool res=solver.solve();
            if(!res)
                printf("No solution.
    ");
            else
            {
                for(int i=0;i<n;i++)
                {
                    if(solver.mark[i*2])
                    {
                        printf("C
    ");
                    }else
                    {
                        printf("%c
    ",age[i]>=x?'A':'B');
                    }
                }
            }
        }
        return 0;
    }
    View Code
  • 相关阅读:
    HTTP概述
    【HTTP权威指南】第二章URL与资源
    【HTTP权威指南】第三章HTTP报文
    列表生成式
    六一问候
    NYOJ 528 找球号(三)
    NYOJ 138 找球号(二)
    HDU3790 最短路径问题
    NYOJ 228 士兵杀敌(五)
    NYOJ3 3 多边形重心问题
  • 原文地址:https://www.cnblogs.com/BMan/p/3612612.html
Copyright © 2020-2023  润新知