• UVa-1343 The Rotation Game


      1 #include <bits/stdc++.h>
      2 #define _for(i,a,b) for(int i = (a);i < (b);i ++)
      3 
      4 using namespace std;
      5 const int maxn = 25;
      6 const int ra[maxn][maxn] = {{0,2,6,11,15,20,22},{1,3,8,12,17,21,23},
      7                             {10,9,8,7,6,5,4},{19,18,17,16,15,14,13},
      8                             {23,21,17,12,8,3,1},{22,20,15,11,6,2,0},
      9                             {13,14,15,16,17,18,19},{4,5,6,7,8,9,10}};
     10 const int ja[maxn] = {6,7,8,11,12,15,16,17};
     11 int a[maxn];
     12 string rnt;
     13 
     14 int readint() {int tmp;scanf("%d",&tmp);return tmp;}
     15 
     16 int unordered(int tmpa[maxn])
     17 {
     18     int cnt = 0;
     19     _for(i,0,8)
     20         if(tmpa[ja[i]]!=1)
     21             cnt ++;
     22     return cnt;
     23 }
     24 
     25 void init(int ta,int tmpa[maxn])
     26 {
     27     memcpy(tmpa,a,sizeof(a));
     28     _for(i,0,24)
     29         if(tmpa[i]!=ta)
     30             tmpa[i] = 0;
     31         else
     32             tmpa[i] = 1;
     33 }
     34 
     35 int g2i(int tmpa[maxn])
     36 {
     37     int rnt = 0;
     38     for(int i = 23;i >= 0;i --)
     39         if(tmpa[i])
     40             rnt += 1<<(23-i);
     41     return rnt;
     42 }
     43 
     44 void i2g(int I,int tmpa[maxn])
     45 {
     46     memset(tmpa,0,sizeof(int)*maxn);
     47     for(int i = 23;i >= 0;i --)
     48         if((I>>i)&0x1)    tmpa[23-i] = 1;
     49 }
     50 
     51 void rotate(int di,int tmpa[maxn])
     52 {
     53     int t = tmpa[ra[di][0]];
     54     _for(i,1,7)
     55         tmpa[ra[di][i-1]] = tmpa[ra[di][i]];
     56     tmpa[ra[di][6]] = t;
     57 }
     58 
     59 struct cmp
     60 {
     61     bool operator() (const pair<int,string> a,const pair<int,string> b) const
     62     {
     63         int tmpa[maxn];
     64         int tmpb[maxn];
     65         i2g(a.first,tmpa);i2g(b.first,tmpb);
     66         int aa = unordered(tmpa),bb = unordered(tmpb);
     67         if(aa>bb)
     68             return true;
     69         return false;
     70     }
     71 };
     72 
     73 int flag = 0;
     74 string bfs(int ta)
     75 {
     76     int tmpa[maxn];
     77     set<int> vis;
     78     string bs;
     79     init(ta,tmpa);
     80     if(!unordered(tmpa)) {flag = 1;return bs;}
     81     
     82     queue<pair<int,string>> q;
     83     q.push({g2i(tmpa),bs});
     84     while(!q.empty())
     85     {
     86         int g = q.front().first;
     87         string s = q.front().second;
     88         i2g(g,tmpa);
     89         if(!unordered(tmpa)) return s;
     90         q.pop();
     91         _for(i,0,8)
     92         {
     93             i2g(g,tmpa);
     94             rotate(i,tmpa);
     95             
     96             int ttg = g2i(tmpa);
     97             if(!vis.count(ttg))
     98             {
     99                 vis.insert(ttg);
    100                 s += i+'A';
    101                 q.push({ttg,s});
    102                 s.pop_back();
    103             }
    104         }
    105     }
    106     return bs;
    107 }
    108 
    109 int solve()
    110 {
    111     string rnts;
    112     rnt.clear();
    113     rnt = bfs(1);
    114     int nnuumm = 1;
    115     _for(i,2,4)
    116     {
    117         rnts = bfs(i);
    118         if(rnts.size()<rnt.size()||rnts.size()==rnt.size()&&rnts<rnt)
    119         {
    120             rnt = rnts;
    121             nnuumm = i;
    122         }
    123     }
    124     return nnuumm;
    125 }
    126 
    127 void print_ans(int ans)
    128 {
    129     if(flag)
    130     {
    131         cout<<"No moves needed"<<endl;
    132         cout << a[6] << endl;
    133         return ;
    134     }
    135     cout << rnt << endl;
    136     cout << ans << endl;
    137 }
    138 
    139 int main()
    140 {
    141     while(~scanf("%d",&a[0])&&a[0]!=0)
    142     {
    143         flag = 0;
    144         _for(i,1,24)
    145             a[i] = readint();
    146         int ans = solve();
    147         print_ans(ans);
    148     }
    149     return 0;
    150 }

    这是一份又臭又长,没有用IDA*所以慢的一塌糊涂就算时间限制再加个0都过不了的BFS无优化代码,放上来纯属个人娱乐,主要具有纪念意义,没有任何参考价值

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  • 原文地址:https://www.cnblogs.com/Asurudo/p/10077485.html
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