• C++回溯法走迷宫


      1 #include <iostream>  
      2 #include <iomanip>  
      3 #include <cstdlib>  
      4 using namespace std;
      5 
      6 #define MaxSize 100  
      7 int maze[10][10] =   //定义一个迷宫,0表示通道,1表示墙  
      8 {
      9     { 1,1,1,1,1,1,1,1,1,1 },
     10     { 1,0,0,1,1,0,0,1,0,1 },
     11     { 1,0,0,1,0,0,0,1,0,1 },
     12     { 1,0,0,0,0,1,1,0,0,1 },
     13     { 1,0,1,1,1,0,0,0,0,1 },
     14     { 1,0,0,0,1,0,0,0,0,1 },
     15     { 1,0,1,0,0,0,1,0,0,1 },
     16     { 1,0,1,1,1,0,1,1,0,1 },
     17     { 1,1,0,0,0,0,0,0,0,1 },
     18     { 1,1,1,1,1,1,1,1,1,1 }
     19 };
     20 
     21 struct Try //定义一个栈,保存路径  
     22 {
     23     int i;               //当前方块的行号  
     24     int j;               //当前广场的列号  
     25     int d;              //di是下一可走方位的方位号  
     26 } path[MaxSize];         //定义栈  
     27 
     28 int top = -1;            //初始化栈指针  
     29 
     30 void findPath(int xb, int yb, int xe, int ye);
     31 
     32 int main()
     33 {
     34     int x1, x2, y1, y2;
     35     cout << "请设定起点(x1,y1):" << endl;
     36     cout << "x1:"; 
     37     cin >> x1;
     38     cout << "y1:";
     39     cin >> y1;
     40     cout << "请设定终点(x2,y2):" << endl;
     41     cout << "x2:";
     42     cin >> x2;
     43     cout << "y2:";
     44     cin >> y2;
     45     findPath(x1, y1, x2, y2);    //从(x1,y1)进入,从(x2,y2)出
     46     system("pause");
     47     return 0;
     48 }
     49 
     50 void findPath(int xb, int yb, int xe, int ye)            //路径为从(xb,yb)到(xe,ye)  
     51 {
     52     int i, j, d, find, k;
     53     top++;                                             //初始方块进栈  
     54     path[top].i = xb;
     55     path[top].j = yb;
     56     path[top].d = -1;
     57     maze[xb][yb] = -1;
     58     while (top>-1)                                      //栈不为空时循环  
     59     {
     60         i = path[top].i;
     61         j = path[top].j;
     62         d = path[top].d;
     63         if (i == xe && j == ye)                             //找到了出口,输出路径  
     64         {
     65             cout << "迷宫路径如下:
    ";
     66             for (k = 0; k <= top; k++)
     67             {
     68                 cout << "	(" << path[k].i << "," << path[k].j << ")";
     69                 if ((k + 1) % 5 == 0) 
     70                     cout << endl;            //每输出五个方块后换一行  
     71             }
     72             cout << endl;
     73             return;
     74         }
     75         find = 0;
     76         while (d<4 && find == 0)                          //找下一个可走的点  
     77         {
     78             d++;
     79             switch (d)
     80             {
     81             case 0:  //向上  
     82                 i = path[top].i - 1;
     83                 j = path[top].j;
     84                 break;
     85             case 1: //向右  
     86                 i = path[top].i;
     87                 j = path[top].j + 1;
     88                 break;
     89             case 2:  //向下  
     90                 i = path[top].i + 1;
     91                 j = path[top].j;
     92                 break;
     93             case 3:  //向左  
     94                 i = path[top].i;
     95                 j = path[top].j - 1;
     96                 break;
     97             }
     98             if (maze[i][j] == 0) find = 1;                      //找到通路  
     99         }
    100         if (find == 1)                                        //找到了下一个可走方块  
    101         {
    102             path[top].d = d;                               //修改原栈顶元素的d值  
    103             top++;                                         //下一个可走方块进栈  
    104             path[top].i = i;
    105             path[top].j = j;
    106             path[top].d = -1;
    107             maze[i][j] = -1;                                 //避免重复走到这个方块  
    108                                                              //cout << "	(" << path[top].i << "," << path[top].j << ")"; //显示经过的试探  
    109         }
    110         else  //没有路可走,则退栈  
    111         {
    112             maze[path[top].i][path[top].j] = 0;                  //让该位置变成其它路径可走方块  
    113             top--;
    114         }
    115     }
    116     cout << "没有可走路径!"<<endl;
    117 }

    作者:耑新新,发布于  博客园

    转载请注明出处,欢迎邮件交流:zhuanxinxin@aliyun.com

  • 相关阅读:
    GJM :用JIRA管理你的项目(三)基于LDAP用户管理 [转载]
    GJM :用JIRA管理你的项目(二)JIRA语言包支持及插件支持 [转载]
    GJM : 用JIRA管理你的项目(一)JIRA环境搭建 [转载]
    javascripct导图
    Sublime Text 中使用Git插件连接GitHub
    使用webstorm上传代码到github
    jQuery.ajax()的一些例子
    jQuery.ajax()
    prefix和unprefix
    MVC , MVP , MVVM【转 阮一峰的网络日志】
  • 原文地址:https://www.cnblogs.com/Arthurian/p/6171215.html
Copyright © 2020-2023  润新知