• MYSQL之select的高级用法


    作用:
    # 多表联查,联表查询
    

    1.传统连接

    1.集合
    #集合
    [xiaoqiu,xiaowang,qiandao]
    [80,90,100]
    
    #数据库
    id:[1,2,3]
    name:[xiaoqiu,xiaowang,qiandao]
    
    id:[1,2,3]
    mark:[80,90,100]
    
    2.建表
    mysql> create table students(id int,name varchar(10));
    Query OK, 0 rows affected (0.08 sec)
    
    mysql> create table score(id int,mark int);
    Query OK, 0 rows affected (0.05 sec)
    
    3.插入数据
    mysql> insert into students values(1,'xiaoqiu'),(2,'qianqian'),(3,'xiaowang');
    Query OK, 3 rows affected (0.02 sec)
    Records: 3  Duplicates: 0  Warnings: 0
    
    mysql> insert into score values(1,80),(2,90),(3,100);
    Query OK, 3 rows affected (0.01 sec)
    Records: 3  Duplicates: 0  Warnings: 0
    
    4.数据查询
    # 查看两个表的数据
    mysql> select * from students;
    +------+---------+
    | id   | name    |
    +------+---------+
    |    1 | xiaoqiu |
    |    2 | qiandao |
    |    3 | xiaowang|
    +------+---------+
    3 rows in set (0.00 sec)
    
    mysql> select * from score;
    +------+------+
    | id   | mark |
    +------+------+
    |    1 |   80 |
    |    2 |   90 |
    |    3 |  100 |
    +------+------+
    3 rows in set (0.00 sec)
    
    # 查看xiaoqiu的分数
    mysql> select students.name,score.mark from students,score where students.id=1 and score.id=1;
    
    mysql> select students.name,score.mark from students,score where students.id=score.id and name='xiaoqiu';
    +--------+------+
    | name   | mark |
    +--------+------+
    | xiaoqiu |   80 |
    +--------+------+
    1 row in set (0.01 sec)
    
    # 查询所有学生成绩
    mysql> select students.name,score.mark from students,score where students.id=score.id
    
    5.连表查询:世界上小于100人的城市在哪个国家?请列出城市名字,国家名字与人口数量
    # 1.确认我要查哪些内容
    国家名字  城市名字  城市人口数量   小于100人
    
    # 2.确认在哪个表
    country.name   city.name   city.population   
    
    # 3.找出两个表相关联的字段
    city.countrycode   country.code
    
    # 4.编写语句
    mysql> select country.name,city.name,city.population from country,city where city.countrycode=country.code and city.population < 100;
    +----------+-----------+------------+
    | name     | name      | population |
    +----------+-----------+------------+
    | Pitcairn | Adamstown |         42 |
    +----------+-----------+------------+
    1 row in set (0.01 sec)
    
    6.练习题二:连表查询:世界上小于100人的城市在哪个国家,是用什么语言?请列出城市名字,国家名字与人口数量和国家语言
    # 1.确认我要查哪些内容
    国家名字  城市名字  城市人口数量   国家使用的语言   小于100人
    
    # 2.确认在哪个表
    country.name   city.name   city.population   countrylanguage.language
    
    # 3.找出三个表相关联的字段
    country.code   city.countrycode   countrylanguage.countrycode
    
    # 4.写sql语句
    mysql> select country.name,city.name,city.population,countrylanguage.language from country,city,countrylanguage where country.code=city.countrycode and city.countrycode=countrylanguage.countrycode and city.population < 100;
    +----------+-----------+------------+-------------+
    | name     | name      | population | language    |
    +----------+-----------+------------+-------------+
    | Pitcairn | Adamstown |         42 | Pitcairnese |
    +----------+-----------+------------+-------------+
    1 row in set (0.04 sec)
    

    2.自连接

    #自己查找相同字段,使用自连接,两个关联的表必须有相同字段和相同数据
    SELECT city.name,city.countrycode,countrylanguage.language,city.population
    FROM  city NATURAL JOIN countrylanguage 
    WHERE population > 1000000
    ORDER BY population;
    
    #两个表中没有相同字段不行,字段相同值不同不行
    SELECT country.name,city.name,city.population FROM city NATURAL JOIN country WHERE population < 100;
    
    #注意:
    1.自连接必须有相同字段和相同值
    2.两个表中的数据必须完全相同
    

    3.内连接

    1.语法格式

    select * from 表1 join 表2 on 相关联的条件 where 条件;
    #注意:命中率(驱动的概念)
    	表1 小表
    	表2 大表
    	
    select * from 表1 inner join 表2 on 相关联的条件 where 条件;
    

    2.例子1:两表联查

    #小于100人的城市在哪个国家,国家代码是什么?
    select city.name,city.population,city.countrycode,country.name 
    from city join country on city.countrycode=country.code 
    where city.population < 100;
    

    3.例子2:三表联查

    #世界上小于100人的城市在哪个国家?是用什么语言?
    select country.name,city.name,city.population,countrylanguage.language
    from city join country on city.countrycode=country.code 
    join countrylanguage on country.code=countrylanguage.countrycode
    where city.population < 100;
    

    4.外连接(有问题)

    1.左外连接

    select city.name,city.countrycode,country.name,city.population
    from city left join country 
    on city.countrycode=country.code 
    and city.population < 100 limit 5;
    +----------------+-------------+------+------------+
    | name           | countrycode | name | population |
    +----------------+-------------+------+------------+
    | Kabul          | AFG         | NULL |    1780000 |
    | Qandahar       | AFG         | NULL |     237500 |
    | Herat          | AFG         | NULL |     186800 |
    | Mazar-e-Sharif | AFG         | NULL |     127800 |
    | Amsterdam      | NLD         | NULL |     731200 |
    +----------------+-------------+------+------------+
    
    

    2.右外连接

    select city.name,city.countrycode,country.name,city.population
    from city right join country 
    on city.countrycode=country.code
    and city.population < 100 limit 5;
    +------+-------------+-------------+------------+
    | name | countrycode | name        | population |
    +------+-------------+-------------+------------+
    | NULL | NULL        | Aruba       |       NULL |
    | NULL | NULL        | Afghanistan |       NULL |
    | NULL | NULL        | Angola      |       NULL |
    | NULL | NULL        | Anguilla    |       NULL |
    | NULL | NULL        | Albania     |       NULL |
    +------+-------------+-------------+------------+
    
    
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  • 原文地址:https://www.cnblogs.com/Applogize/p/13332303.html
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