java 实例 按CGPA大小排列名字

要求：

2<=N<=1000

0<=ID<=100000

5<=|NAME|<=30

0<=CGPA<=4.0

N表示个数

输入：

5
33 Rumpa 3.68
85 Ashis 3.85
56 Samiha 3.75
19 Samara 3.75
22 Fahim 3.76

输出：

Ashis
Fahim
Samara
Samiha
Rumpa

代码：

import java.util.*;

class Student
{
   public int id;
   public String fname;
   public double cgpa;
   public Student(int id, String fname, double cgpa) 
   {
      this.id = id;
      this.fname = fname;
      this.cgpa = cgpa;
   }
}

class Checker implements Comparator<Student>
{
    @Override
    public int compare(Student p, Student q) 
    {
        if (q.cgpa == p.cgpa)
        {
            if(p.fname == q.fname)
            {
                return q.id - p.id;
            }
            return p.fname.compareTo(q.fname);
        } 
        else 
        {
            return q.cgpa > p.cgpa ? 1 : -1;
        }
    }
}

public class Solution
{
   public static void main(String[] args)
   {
      Scanner scan = new Scanner(System.in);
      int n = Integer.parseInt(scan.nextLine());
      
      Student[] student = new Student[n];
      Checker checker = new Checker();
      for(int i = 0; i < n; i++)
      {
         int id = scan.nextInt();
         String fname = scan.next();
         double cgpa = scan.nextDouble();
         
         student[i] = new Student(id, fname, cgpa);
      }
      
      Arrays.sort(student, checker);
      for(Student st : student)
      {
         System.out.println(st.fname);
      }
   }
}