• BZOJ1102(搜索)


    随便写一下的搜索,别的OJ深搜就过了,强大的BZOJ成功栈溢出RE了我并使我屈服地用广搜过掉,第一行手动开栈惨遭无视。

    广搜:

      1 #pragma comment(linker, "/STACK:1024000000,1024000000")
      2 #include <cstdio>
      3 #include <cstring>
      4 #include <cstdlib>
      5 #include <cmath>
      6 #include <ctime>
      7 #include <cctype>
      8 #include <climits>
      9 #include <iostream>
     10 #include <iomanip>
     11 #include <algorithm>
     12 #include <string>
     13 #include <sstream>
     14 #include <stack>
     15 #include <queue>
     16 #include <set>
     17 #include <map>
     18 #include <vector>
     19 #include <list>
     20 #include <fstream>
     21 #include <bitset>
     22 #define init(a, b) memset(a, b, sizeof(a))
     23 #define rep(i, a, b) for (int i = a; i <= b; i++)
     24 #define irep(i, a, b) for (int i = a; i >= b; i--)
     25 using namespace std;
     26 
     27 typedef double db;
     28 typedef long long ll;
     29 typedef unsigned long long ull;
     30 typedef pair<int, int> P;
     31 const int inf = 0x3f3f3f3f;
     32 const ll INF = 1e18;
     33 
     34 template <typename T> void read(T &x) {
     35     x = 0;
     36     int s = 1, c = getchar();
     37     for (; !isdigit(c); c = getchar())
     38         if (c == '-')    s = -1;
     39     for (; isdigit(c); c = getchar())
     40         x = x * 10 + c - 48;
     41     x *= s;
     42 }
     43 
     44 template <typename T> void write(T x) {
     45     if (x < 0)    x = -x, putchar('-');
     46     if (x > 9)    write(x / 10);
     47     putchar(x % 10 + '0');
     48 }
     49 
     50 template <typename T> void writeln(T x) {
     51     write(x);
     52     puts("");
     53 }
     54 
     55 const int maxn = 1e3 + 5;
     56 int n, A[maxn][maxn], up, down;
     57 bool vis[maxn][maxn];
     58 
     59 int bfs(int x, int y) {
     60     queue<P> Q;
     61     Q.push(P(x, y));
     62     vis[x][y] = true;
     63     bool small = true, equal = true, large = true;
     64     while (!Q.empty()) {
     65         int i = Q.front().first, j = Q.front().second;
     66         Q.pop();
     67         rep(a, -1, 1)    rep(b, -1, 1) {
     68             int nx = i + a, ny = j + b;
     69             if (nx < 1 || nx > n || ny < 1 || ny > n)    continue;
     70 
     71             int val = A[nx][ny], k = -1;
     72             if (val == A[i][j]) {
     73                 if (vis[nx][ny])    continue;
     74                 Q.push(P(nx, ny));
     75                 vis[nx][ny] = true;
     76             } else if (val > A[i][j]) {
     77                 k = 2;
     78             } else    k = 1;
     79 
     80             if (k == 2)    small = false, equal = false;
     81             else if (k == 1)    large = false, equal = false;
     82         }
     83     }
     84     if (equal)    return 0;
     85     if (small)    return 1;
     86     if (large)    return 2;
     87     return -1;
     88 }
     89 
     90 int main() {
     91     read(n);
     92     rep(i, 1, n)    rep(j, 1, n)    read(A[i][j]);
     93     rep(i, 1, n)    rep(j, 1, n) {
     94         if (!vis[i][j]) {
     95             int k = bfs(i, j);
     96             if (k == 0) {
     97                 up++, down++;
     98             } else if (k == 1) {
     99                 up++;
    100             } else if (k == 2) {
    101                 down++;
    102             }
    103         }
    104     }
    105     printf("%d %d
    ", up, down);
    106     return 0;
    107 }

    深搜:

      1 #pragma comment(linker, "/STACK:1024000000,1024000000")
      2 #include <cstdio>
      3 #include <cstring>
      4 #include <cstdlib>
      5 #include <cmath>
      6 #include <ctime>
      7 #include <cctype>
      8 #include <climits>
      9 #include <iostream>
     10 #include <iomanip>
     11 #include <algorithm>
     12 #include <string>
     13 #include <sstream>
     14 #include <stack>
     15 #include <queue>
     16 #include <set>
     17 #include <map>
     18 #include <vector>
     19 #include <list>
     20 #include <fstream>
     21 #include <bitset>
     22 #define init(a, b) memset(a, b, sizeof(a))
     23 #define rep(i, a, b) for (int i = a; i <= b; i++)
     24 #define irep(i, a, b) for (int i = a; i >= b; i--)
     25 using namespace std;
     26 
     27 typedef double db;
     28 typedef long long ll;
     29 typedef unsigned long long ull;
     30 typedef pair<int, int> P;
     31 const int inf = 0x3f3f3f3f;
     32 const ll INF = 1e18;
     33 
     34 template <typename T> void read(T &x) {
     35     x = 0;
     36     int s = 1, c = getchar();
     37     for (; !isdigit(c); c = getchar())
     38         if (c == '-')    s = -1;
     39     for (; isdigit(c); c = getchar())
     40         x = x * 10 + c - 48;
     41     x *= s;
     42 }
     43 
     44 template <typename T> void write(T x) {
     45     if (x < 0)    x = -x, putchar('-');
     46     if (x > 9)    write(x / 10);
     47     putchar(x % 10 + '0');
     48 }
     49 
     50 template <typename T> void writeln(T x) {
     51     write(x);
     52     puts("");
     53 }
     54 
     55 const int maxn = 1e3 + 5;
     56 int n, A[maxn][maxn], up, down;
     57 bool vis[maxn][maxn];
     58 
     59 int dfs(int i, int j) {
     60     vis[i][j] = true;
     61     bool small = true, equal = true, large = true;
     62     rep(a, -1, 1)    rep(b, -1, 1) {
     63         int nx = i + a, ny = j + b;
     64         if (nx < 1 || nx > n || ny < 1 || ny > n)    continue;
     65 
     66         int val = A[nx][ny], k = -1;
     67         if (val == A[i][j]) {
     68             if (vis[nx][ny])    continue;
     69             k = dfs(nx, ny);
     70         } else if (val > A[i][j]) {
     71             k = 2;
     72         } else    k = 1;
     73 
     74         if (k == 2)    small = false, equal = false;
     75         else if (k == 1)    large = false, equal = false;
     76         else if (k == 0)    small = false, large = false;
     77         else    small = false, equal = false, large = false;
     78     }
     79     if (equal)    return 0;
     80     if (small)    return 1;
     81     if (large)    return 2;
     82     return -1;
     83 }
     84 
     85 int main() {
     86     read(n);
     87     rep(i, 1, n)    rep(j, 1, n)    read(A[i][j]);
     88     rep(i, 1, n)    rep(j, 1, n) {
     89         if (!vis[i][j]) {
     90             int k = dfs(i, j);
     91             if (k == 0) {
     92                 up++, down++;
     93             } else if (k == 1) {
     94                 up++;
     95             } else if (k == 2) {
     96                 down++;
     97             }
     98         }
     99     }
    100     printf("%d %d
    ", up, down);
    101     return 0;
    102 }
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  • 原文地址:https://www.cnblogs.com/AlphaWA/p/10487591.html
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