• 面试题 35 : 复杂链表的复制


    还是得多做题,细节的地方老出错误。

    解题思路:

    /**
     * @Author: Allen
     * @Version:v1.00
     * @CreateData:
     * 输入一个复杂链表(每个节点中有节点值,以及两个指针,一个指向下一个节点,
     * 另一个特殊指针指向任意一个节点),返回结果为复制后复杂链表的head。
     * (注意,输出结果中请不要返回参数中的节点引用,否则判题程序会直接返回空)
     */
    public class FuZaLianBiaoDeFuZhi {
        public static void main(String[] args) {
            RandomListNode headListNode = new RandomListNode(1);
            headListNode.next = new RandomListNode(2);
            headListNode.random = headListNode.next;
            Solution19 solution19 = new Solution19();
            RandomListNode head = solution19.Clone(headListNode);
        }
    }
    
    class RandomListNode {
        int label;
        RandomListNode next = null;
        RandomListNode random = null;
    
        RandomListNode(int label) {
            this.label = label;
        }
    }
    
    class Solution19 {
        public RandomListNode Clone(RandomListNode pHead)
        {
            if(pHead==null){
                return null;
            }
            RandomListNode clonedHead = null;
            RandomListNode pListHead = null;
            pListHead = CloneNode(pHead);
            pListHead = makeRandomIndex(pListHead);
            clonedHead = splitList(pListHead);
             return clonedHead;
        }
        //1.复制每个节点,将每个复制的节点放置于被复制的节点后面
        private RandomListNode CloneNode(RandomListNode pHead){
            RandomListNode pNode = pHead;
            while(pNode!=null){
                RandomListNode clonedNode = new RandomListNode(pNode.label);
                clonedNode.next=pNode.next;
                pNode.next=clonedNode;
                pNode=clonedNode.next;
            }
            return pHead;
        }
        //2.为每个复制的节点的random引用赋值,其值是原来节点的random引用的下一个节点
        private RandomListNode makeRandomIndex(RandomListNode pHead){
            RandomListNode pNode = pHead;
            while(pNode!=null){
                RandomListNode clonedNode = pNode.next;
                if(pNode.random!=null)//报空指针了,节操何在
                    clonedNode.random = pNode.random.next;
                pNode = clonedNode.next;
            }
            return pHead;
        }
        //3.拆分链表
        private RandomListNode splitList(RandomListNode pHead){
            RandomListNode pNode = pHead;
            RandomListNode clonedHead = null;
            RandomListNode clonedNode = null;
            if(pNode!=null){
                clonedHead = pHead.next;
                clonedNode = clonedHead;
                pNode.next = clonedNode.next;
                pNode = clonedNode.next;
            }
            
            while(pNode!=null){
                clonedNode.next = pNode.next;
                clonedNode = clonedNode.next;
                pNode.next = clonedNode.next;
                pNode = pNode.next;
            }
            return clonedHead;
        }
    }
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  • 原文地址:https://www.cnblogs.com/Allen-win/p/8855165.html
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