• Binary Search Tree III Aizu


    Write a program which performs the following operations to a binary search tree TT by adding delete operation to B: Binary Search Tree II.

    insert kk: Insert a node containing kk as key into TT.
    find kk: Report whether TT has a node containing kk.
    delete kk: Delete a node containing kk.
    print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.
    The operation delete kk for deleting a given node zz containing key kk from TT can be implemented by an algorithm which considers the following cases:

    If zz has no children, we modify its parent z.pz.p to replace zz with NIL as its child (delete zz).
    If zz has only a single child, we “splice out” zz by making a new link between its child and its parent.
    If zz has two children, we splice out zz's successor yy and replace zz's key with yy's key.

    Input

    In the first line, the number of operations mm is given. In the following mm lines, operations represented by insert kk, find kk, delete kk or print are given.

    Output

    For each find kk operation, print “yes” if TT has a node containing kk, “no” if not.

    In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key

    Constraints

    The number of operations 500,000leq 500,000
    The number of print operations 10leq 10.
    2,000,000,000key2,000,000,000-2,000,000,000 leq key leq 2,000,000,000
    The height of the binary tree does not exceed 100 if you employ the above pseudo code.
    The keys in the binary search tree are all different.

    Sample Input 1

    18
    insert 8
    insert 2
    insert 3
    insert 7
    insert 22
    insert 1
    find 1
    find 2
    find 3
    find 4
    find 5
    find 6
    find 7
    find 8
    print
    delete 3
    delete 7
    print

    Sample Output 1

    yes
    yes
    yes
    no
    no
    no
    yes
    yes
    1 2 3 7 8 22
    8 2 1 3 7 22
    1 2 8 22
    8 2 1 22

    Reference

    Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

    Code

    /*
                                    ^....0
                                   ^ .1 ^1^
                                   ..     01
                                  1.^     1.0
                                 ^ 1  ^    ^0.1
                                 1 ^        ^..^
                                 0.           ^ 0^
                                 .0            1 .^
                                 .1             ^0 .........001^
                                 .1               1. .111100....01^
                                 00                 11^        ^1. .1^
                                 1.^                              ^0  0^
                                   .^                                 ^0..1
                                   .1                                   1..^
                                 1 .0                                     ^  ^
                                  00.                                     ^^0.^
                                  ^ 0                                     ^^110.^
                              0   0 ^                                     ^^^10.01
                       ^^     10  1 1                                      ^^^1110.1
                       01     10  1.1                                      ^^^1111110
                       010    01  ^^                                        ^^^1111^1.^           ^^^
                       10  10^ 0^ 1                                            ^^111^^^0.1^       1....^
                        11     0                                               ^^11^^^ 0..  ....1^   ^ ^
                        1.     0^                                               ^11^^^ ^ 1 111^     ^ 0.
                       10   00 11                                               ^^^^^   1 0           1.
                       0^  ^0  ^0                                                ^^^^    0            0.
                       0^  1.0  .^                                               ^^^^    1 1          .0
                       ^.^  ^^  0^                             ^1                ^^^^     0.         ^.1
                       1 ^      11                             1.                ^^^     ^ ^        ..^
                      ^..^      ^1                             ^.^               ^^^       .0       ^.0
                      0..^      ^0                              01               ^^^       ..      0..^
                     1 ..        .1                             ^.^              ^^^       1 ^  ^0001
                    ^  1.        00                              0.             ^^^        ^.0 ^.1
                    . 0^.        ^.^                             ^.^            ^^^         ..0.0
                   1 .^^.         .^                  1001        ^^            ^^^         . 1^
                   . ^ ^.         11                0.    1         ^           ^^          0.
                    0  ^.          0              ^0       1                   ^^^          0.
                  0.^  1.          0^             0       .1                   ^^^          ..
                  .1   1.          00            .        .1                  ^^^           ..
                 1      1.         ^.           0         .^                  ^^            ..
                 0.     1.          .^          .         0                                  .
                 .1     1.          01          .        .                                 ^ 0
                ^.^     00          ^0          1.       ^                                 1 1
                .0      00           .            ^^^^^^                                   .
                .^      00           01                                                    ..
               1.       00           10                                                   1 ^
              ^.1       00           ^.                                            ^^^    .1
              ..        00            .1                                        1..01    ..
             1.1         00           1.                                       ..^      10
            ^ 1^         00           ^.1                                      0 1      1
            .1           00            00                                       ^  1   ^
             .           00            ^.^                                        10^  ^^
           1.1           00             00                                              10^
           ..^           1.             ^.                                               1.
          0 1            ^.              00                 00                            .^
            ^            ^.              ^ 1                00   ^0000^     ^               01
         1 0             ^.               00.0^              ^00000   1.00.1              11
         . 1              0               1^^0.01                      ^^^                01
          .^              ^                1   1^^                                       ^.^
        1 1                                                                              0.
        ..                                                                              1 ^
         1                                                                               1
       ^ ^                                                                             .0
       1                                                                             ^ 1
       ..                                                          1.1            ^0.0
      ^ 0                                                           1..01^^100000..0^
      1 1                                                            ^ 1 ^^1111^ ^^
      0 ^                                                             ^ 1      1000^
      .1                                                               ^.^     .   00
      ..                                                                1.1    0.   0
      1.                                                                  .    1.   .^
      1.                                                                 1    1.   ^0
     ^ .                                                                 ^.1 00    01
     ^.0                                                                  001.     .^
     */
    // Virtual_Judge —— Binary Search Tree III Aizu - ALDS1_8_C.cpp created by VB_KoKing on 2019-05-10:08.
    /* Procedural objectives:
    
     Variables required by the program:
    
     Procedural thinking:
    
     Functions required by the program:
     
     Determination algorithm:
     
     Determining data structure:
     
    
    */
    /* My dear Max said:
    "I like you,
    So the first bunch of sunshine I saw in the morning is you,
    The first gentle breeze that passed through my ear is you,
    The first star I see is also you.
    The world I see is all your shadow."
    
    FIGHTING FOR OUR FUTURE!!!
    */
    #include <iostream>
    #include <cstdlib>
    #include <string>
    
    using namespace std;
    
    struct Node {
        int key;
        Node *right, *left, *parent;
    };
    
    Node *root, *NIL;
    
    Node *tree_minimum(Node *x) {
        while (x->left != NIL)
            x = x->left;
        return x;
    }
    
    Node *find(Node *u, int k) {
        while (u != NIL && k != u->key) {
            if (k<u->key) u=u->left;
            else u=u->right;
        }
        return u;
    }
    
    Node *tree_successor(Node *x){
        if (x->right!=NIL) return tree_minimum(x->right);
        Node *y=x->parent;
        while(y!=NIL&&x==y->right){
            x=y;
            y=y->parent;
        }
        return y;
    }
    
    void tree_delete(Node *z){
        Node *x,*y;
        if (z->left==NIL||z->right==NIL) y=z;
        else y=tree_successor(z);
    
        if (y->left!=NIL) x=y->left;
        else x=y->right;
    
        if (x!=NIL) x->parent=y->parent;
    
        if (y->parent==NIL) root=x;
        else {
            if (y==y->parent->left) y->parent->left=x;
            else y->parent->right=x;
        }
    
        if (y!=z) z->key=y->key;
    
        free(y);
    }
    
    void insert(int k) {
        Node *y = NIL;
        Node *x = root;
        Node *z;
    
        z = (Node *) malloc(sizeof(Node));
        z->key = k;
        z->left = NIL;
        z->right = NIL;
    
        while (x != NIL) {
            y = x;
            if (z->key < x->key)
                x = x->left;
            else
                x = x->right;
        }
    
        z->parent = y;
        if (y == NIL)
            root = z;
        else {
            if (z->key < y->key)
                y->left = z;
            else y->right = z;
        }
    }
    
    //前序遍历
    void pre_parse(Node *u) {
        if (u == NIL) return;
        cout << " " << u->key;
        pre_parse(u->left);
        pre_parse(u->right);
    }
    
    //中序遍历
    void in_parse(Node *u) {
        if (u == NIL) return;
        in_parse(u->left);
        cout << " " << u->key;
        in_parse(u->right);
    }
    
    int main() {
        int n;
        string com;
        cin >> n;
        for (int i = 0; i < n; i++) {
            cin >> com;
            if (com == "insert") {
                int x;
                cin >> x;
                insert(x);
            } else if (com == "print") {
                in_parse(root);
                cout << endl;
                pre_parse(root);
                cout << endl;
            } else if (com=="find"){
                int x;
                cin>>x;
                Node *t=find(root,x);
                if (t!=NIL) cout<<"yes"<<endl;
                else cout<<"no"<<endl;
            } else if (com=="delete"){
                int x;
                cin>>x;
                tree_delete(find(root,x));
            }
        }
        return 0;
    }
    
  • 相关阅读:
    Linux常用命令
    关于MUI v0.18.0版本 Table组件里的复选框不能选的解决方案
    React---点击按钮实现内容复制功能
    js作用域相关笔记
    React监听窗口变化事件
    Express搭建NodeJS项目
    react +MUI checkbox使用
    React鼠标事件
    初入React(一)
    彻底搞懂hashCode与equals的作用与区别及应当注意的细节
  • 原文地址:https://www.cnblogs.com/AlexKing007/p/12338319.html
Copyright © 2020-2023  润新知