自己做的:
dic = {'k1':'v1','k2':'v2','k3':'v3','k4':'v4'} #1.循环所有k,value,key和value # for k in dic: # print(k) # for v in dic: # print(dic[v]) # for i in dic: # print(i,dic[i]) #2.添加: # dic['k5']='v5' # print(dic) #3.删除k1,v1 # dic.pop('k1') # print(dic) #4.删除k2 # print(dic) # for k in dic : # if k == 'k2': # dic['k2']='' # print(dic) # else: # print('None') #5.'k2'对应的值 # print(dic['k2']) # print(dic.get('k2')) #6.获取k3值 # for k in dic : # if k == 'k3': # print(dic['k3']) # else: # print('None') #7. # dic2 = {'k1':'v111','a':'b'} # dic2.update({'k2':'v2','k3':'v3'}) # # print(dic2) #8. lis = [['k',['qwe',20,{'k1':['tt',3,'1']},89]]] #1, # lis[0][1][2]['k1'][0]='TT' # print(lis) # 2. # lis[0][1][2].update({'k1':['TT',3,'1']}) # print(lis) # lis[0][1][2]['k1'][0]=(lis[0][1][2]['k1'][0]).upper() # print(lis) #2. # lis[0][1][2]['k1'][1] = '100' # print(lis) #3. # lis[0][1][2]['k1'][2] = 101 # print(lis) # #11. # li = [1,2,3,'a','b',4,'c'] # dic3 = {} # dic3.update({'k1':[]}) # for index,i in enumerate(li) : # if index%2 != 0: # dic3['k1'].append(i) # print(dic3)