• CF877E Danil and a Part-time Job


    CF877E Danil and a Part-time Job

    树剖然后线段树维护即可,维护取反操作本质就是交换 01 的个数即可。

    代码:

    #include<bits/stdc++.h>
    using namespace std;
    template <typename T>
    inline void read(T &x){
    	x=0;char ch=getchar();bool f=false;
    	while(!isdigit(ch)){if(ch=='-'){f=true;}ch=getchar();}
    	while(isdigit(ch)){x=(x<<1)+(x<<3)+(ch^48);ch=getchar();}
    	x=f?-x:x;
    	return ;
    }
    template <typename T>
    inline void write(T x){
    	if(x<0) putchar('-'),x=-x;
    	if(x>9) write(x/10);
    	putchar(x%10^48);
    	return ;
    }
    const int N=2e5+5;
    struct TREE{
    	struct node{
    		int l,r;
    		int tag,val;
    	}tree[N<<2];
    	#define l(x) tree[(x)].l
    	#define r(x) tree[(x)].r
    	#define mid(x) (tree[(x)].l+tree[(x)].r>>1)
    	#define tag(x) tree[(x)].tag
    	#define val(x) tree[(x)].val
    	#define ls x<<1
    	#define rs x<<1|1
    	int a[N];
    	void pushdown(int x){
    		if(tag(x)){
    			tag(ls)^=1,val(ls)=r(ls)-l(ls)+1-val(ls);
    			tag(rs)^=1,val(rs)=r(rs)-l(rs)+1-val(rs);
    			tag(x)=0;
    		}
    	} 
    	void Pushup(int x){
    		val(x)=val(ls)+val(rs);
    	}
    	void build(int x,int l,int r){
    		l(x)=l,r(x)=r;tag(x)=0;
    		if(l==r){val(x)=a[l];return;}
    		build(ls,l(x),mid(x));
    		build(rs,mid(x)+1,r(x));
    		Pushup(x);
    	}
    	void Modify(int x,int l,int r){
    		if(r<l(x)||r(x)<l)return;
    		if(l<=l(x)&&r(x)<=r){
    			tag(x)^=1;
    			val(x)=r(x)-l(x)+1-val(x);
    			return;
    		}
    		pushdown(x);
    		Modify(ls,l,r);
    		Modify(rs,l,r);
    		Pushup(x);
    	}
    	int Query(int x,int l,int r){
    		if(r<l(x)||r(x)<l)return 0;
    		if(l<=l(x)&&r(x)<=r)return val(x);
    		pushdown(x);
    		return Query(ls,l,r)+Query(rs,l,r); 
    	}
    }T; 
    int n,m,a;
    struct Graph{
    	struct node{
    		int v,nex;
    	}e[N<<1];
    	int cnt,head[N];
    	void add(int x,int y){e[++cnt]=(node){y,head[x]};head[x]=cnt;}
    	int tot,dfn[N],siz[N];
    	void dfs(int x,int fa){
    		dfn[x]=++tot,siz[x]=1;
    		for(int i=head[x];i;i=e[i].nex) if(e[i].v!=fa)dfs(e[i].v,x),siz[x]+=siz[e[i].v];
    	}
    }G;
    signed main(){
    	read(n);
    	for(int i=1;i<n;i++) read(a),G.add(a,i+1);
    	G.dfs(1,0);
    	for(int i=1;i<=n;i++) read(a),T.a[G.dfn[i]]=a;
    	T.build(1,1,n);
    	read(m);
    	while(m--){
    		char op[5];scanf("%s",op);
    		int x;read(x);
    		if(op[0]=='g'){
    			write(T.Query(1,G.dfn[x],G.dfn[x]+G.siz[x]-1));
    			putchar('
    ');	
    		}
    		else T.Modify(1,G.dfn[x],G.dfn[x]+G.siz[x]-1);
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Akmaey/p/14676970.html
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