• P4054 [JSOI2009]计数问题


    P4054 [JSOI2009]计数问题

    P4054 [JSOI2009]计数问题

    一道三维偏序就因为数据变成了三维树状数组的水题...

    对每个权值开一个二维树状数组,然后暴力修改暴力询问即可。

    view code
    #include<bits/stdc++.h>
    using namespace std;
    template <typename T>
    inline void read(T &x){
    	x=0;char ch=getchar();bool f=false;
    	while(!isdigit(ch)){if(ch=='-'){f=true;}ch=getchar();}
    	while(isdigit(ch)){x=(x<<1)+(x<<3)+(ch^48);ch=getchar();}
    	x=f?-x:x;
    	return ;
    }
    template <typename T>
    inline void write(T x){
    	if(x<0) putchar('-'),x=-x;
    	if(x>9) write(x/10);
    	putchar(x%10^48);
    	return ;
    }
    const int N=2e5+5,M=305;
    #define y1 qwq
    int n,m,a[M][M],ans[N],tree[105][M][M];
    int lowbit(int x){return x&-x;}
    void Add(int type,int x,int y,int v){while(x<=n){int now=y;while(now<=m){tree[type][x][now]+=v;now+=lowbit(now);}x+=lowbit(x);}}
    int Ask(int type,int x,int y){
    	int tot=0;
    	while(x>=1){int now=y;while(now>=1){tot+=tree[type][x][now];now-=lowbit(now);}x-=lowbit(x);}
    	return tot;
    }
    int Query(int type,int x1,int y1,int x2,int y2){return Ask(type,x2,y2)+Ask(type,x1-1,y1-1)-Ask(type,x1-1,y2)-Ask(type,x2,y1-1);}
    int main(){
    	int q,Top=0;
    	read(n),read(m);
    	for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) read(a[i][j]),Add(a[i][j],i,j,1);
    	read(q);
    	for(int i=1;i<=q;i++){
    		int op;read(op);
    		if(op==1){
    			int x,y,c;
    			read(x),read(y),read(c);
    			Add(a[x][y],x,y,-1),Add(c,x,y,1),a[x][y]=c;
    		}
    		else{
    			int x1,y1,x2,y2,c;
    			read(x1),read(x2),read(y1),read(y2),read(c);
    			ans[++Top]=Query(c,x1,y1,x2,y2);
    		}
    	}
    	for(int i=1;i<=Top;i++) write(ans[i]),putchar('
    ');
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Akmaey/p/14648569.html
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