第十五周 12.6-12.12

12.6

状况百出的迎新杯。惶恐。

12.7

补个BC。

HDU 5593 ZYB's Tree

对树上每点求与其距离不超过k点数。k<=10.

一开始想的是用一个a[]存孩子中不超过k数，用另一个b[]存父亲传递过来的不超过k数。

但是这样转移不过来。因为父亲那边过来的不仅有父亲的父亲。还有父亲的其他孩子树。

所以想到换成用b[]存父亲+所有孩子不超过k数就可以转移了。

转移方程是 b[pos][i+1] = b[fa][i] - a[pos][i-1] + a[pos][i+1] 。

每个点的答案就是b[]求和。

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstring>
 4 using namespace std;
 5 const int maxn = 500000 + 10;
 6 typedef long long LL;
 7 int cnt, headlist[maxn];
 8 int a[maxn][11], b[maxn][11];
 9 int ans[maxn];
10 LL N, K, A, B;
11 
12 struct node
13 {
14     int to,pre;
15 } edge[maxn * 2];
16 
17 void add(int from,int to)
18 {
19     cnt++;
20     edge[cnt].pre = headlist[from];
21     edge[cnt].to = to;
22     headlist[from] = cnt;
23 }
24 
25 void dfs1(int pos, int fa)
26 {
27     a[pos][0] = 1;
28     for(int i = headlist[pos]; i; i = edge[i].pre)
29     {
30         int to = edge[i].to;
31         if(to == fa) continue;
32         dfs1(to, pos);
33         a[pos][1]++;
34         for(int j = 1; j < K; j++) a[pos][j+1] += a[to][j];
35     }
36     return;
37 }
38 
39 void dfs2(int pos, int fa)
40 {
41     if(fa != 0)
42     {
43         b[pos][1]++;
44         for(int i = 1; i < K; i++) b[pos][i+1] += b[fa][i] - a[pos][i-1];
45     }
46     for(int i = 0; i <= K; i++) b[pos][i] += a[pos][i] ,ans[pos] += b[pos][i];
47     for(int i = headlist[pos]; i; i = edge[i].pre)
48     {
49         int to = edge[i].to;
50         if(to == fa) continue;
51         dfs2(to, pos);
52     }
53     return;
54 }
55 
56 int main(void)
57 {
58     int T;
59     scanf("%d", &T);
60     while(T--)
61     {
62         scanf("%I64d %I64d %I64d %I64d", &N, &K, &A, &B);
63         cnt = 0;
64         memset(headlist, 0, sizeof(headlist));
65         memset(a, 0, sizeof(a));
66         memset(b, 0, sizeof(b));
67         memset(ans, 0, sizeof(ans));
68         for(LL i = 2; i <= N; i++)
69         {
70             LL b = (A * i + B) % (i - 1) + 1;
71             add(i, b);
72             add(b, i);
73         }
74         dfs1(1,0);
75         dfs2(1,0);
76         int ret = 0;
77         for(int i = 1; i <= N; i++) ret ^= ans[i];
78         printf("%d
", ret);
79     }
80     return 0;
81 }

Aguin

停滞很久的AC自动姬。

HDU 2457 DNA repair

没有注意到可以有20*50*1000的做法。

偷看题解一开始还以为要在Trie图上dp。然而直接dp就可以了。

由于曾在写法上被坑过。先是很乖的写了sb法。

  1 #include <iostream>
  2 #include <cstdio>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <queue>
  6 using namespace std;
  7 const int maxnode = 1010, sigma_size = 4;
  8 char str[] = "AGCT", s[1010];
  9 int N;
 10 
 11 struct Ac_auto
 12 {
 13     int Next[maxnode][sigma_size];
 14     int fail[maxnode];
 15     int val[maxnode];
 16     int sz;
 17 
 18     Ac_auto(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 19     void init(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 20 
 21     int idx(char c)
 22     {
 23         if(c == 'A') return 0;
 24         else if(c == 'G') return 1;
 25         else if(c == 'C') return 2;
 26         return 3;
 27     }
 28 
 29     void insert(char *s)
 30     {
 31         int u = 0, n = strlen(s);
 32         for(int i = 0; i < n; i++)
 33         {
 34             int c = idx(s[i]);
 35             if(!Next[u][c])
 36             {
 37                 memset(Next[sz], 0, sizeof(Next[sz]));
 38                 val[sz] = 0;
 39                 Next[u][c] = sz++;
 40             }
 41             u = Next[u][c];
 42         }
 43         val[u] = 1;
 44     }
 45 
 46     void build()
 47     {
 48         queue<int> q;
 49         fail[0] = 0;
 50         for(int i = 0; i < sigma_size; i++) if(Next[0][i])
 51         {
 52             fail[Next[0][i]] = 0;
 53             q.push(Next[0][i]);
 54         }
 55         while(!q.empty())
 56         {
 57             int pos = q.front(); q.pop();
 58             for(int i = 0; i < sigma_size; i++)
 59             {
 60                 if(!Next[pos][i]) Next[pos][i] = Next[fail[pos]][i];
 61                 else
 62                 {
 63                     fail[Next[pos][i]] = Next[fail[pos]][i];
 64                     q.push(Next[pos][i]);
 65                 }
 66             }
 67         }
 68     }
 69 
 70 }ACA;
 71 
 72 const int INF = 100000;
 73 int dp[1010][1010];
 74 int solve()
 75 {
 76     int len = strlen(s);
 77     for(int i = 0; i <= len; i++)
 78         for(int j = 0; j < ACA.sz; j++)
 79             dp[i][j] = INF;
 80     dp[0][0] = 0;
 81     for(int i = 0; i < len; i++)
 82     {
 83         for(int j = 0; j < ACA.sz; j++)
 84         {
 85             if(dp[i][j] == INF) continue;
 86             for(int k = 0; k < 4; k++)
 87             {
 88                 int pos = ACA.Next[j][k], ok = 1;
 89                 while(pos)
 90                 {
 91                     if(ACA.val[pos]) {ok = 0; break;}
 92                     pos = ACA.fail[pos];
 93                 }
 94                 if(!ok) continue;
 95                 int & t = dp[i+1][ACA.Next[j][k]];
 96                 t = min(t, dp[i][j] + (str[k] != s[i]) );
 97             }
 98         }
 99     }
100     int ans = INF;
101     for(int i = 0; i < ACA.sz; i++) ans = min(ans, dp[len][i]);
102     return ans == INF ? -1 : ans;
103 }
104 
105 int main(void)
106 {
107     int kase = 0;
108     while(~scanf("%d", &N) && N)
109     {
110         ACA.init();
111         for(int i = 1; i <= N; i++)
112         {
113             char tmp[22];
114             scanf("%s", tmp);
115             ACA.insert(tmp);
116         }
117         ACA.build();
118         scanf("%s", s);
119         printf("Case %d: %d
", ++kase, solve());
120     }
121     return 0;
122 }

Aguin

不过这次改了一下写法还是过的。也如预期快了一点点。（并不

  1 #include <iostream>
  2 #include <cstdio>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <queue>
  6 using namespace std;
  7 const int maxnode = 1010, sigma_size = 4;
  8 char str[] = "AGCT", s[1010];
  9 int N;
 10 
 11 struct Ac_auto
 12 {
 13     int Next[maxnode][sigma_size];
 14     int fail[maxnode];
 15     int val[maxnode];
 16     int sz;
 17 
 18     Ac_auto(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 19     void init(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 20 
 21     int idx(char c)
 22     {
 23         if(c == 'A') return 0;
 24         else if(c == 'G') return 1;
 25         else if(c == 'C') return 2;
 26         return 3;
 27     }
 28 
 29     void insert(char *s)
 30     {
 31         int u = 0, n = strlen(s);
 32         for(int i = 0; i < n; i++)
 33         {
 34             int c = idx(s[i]);
 35             if(!Next[u][c])
 36             {
 37                 memset(Next[sz], 0, sizeof(Next[sz]));
 38                 val[sz] = 0;
 39                 Next[u][c] = sz++;
 40             }
 41             u = Next[u][c];
 42         }
 43         val[u] = 1;
 44     }
 45 
 46     void build()
 47     {
 48         queue<int> q;
 49         fail[0] = 0;
 50         for(int i = 0; i < sigma_size; i++) if(Next[0][i])
 51         {
 52             fail[Next[0][i]] = 0;
 53             q.push(Next[0][i]);
 54         }
 55         while(!q.empty())
 56         {
 57             int pos = q.front(); q.pop();
 58             for(int i = 0; i < sigma_size; i++)
 59             {
 60                 if(!Next[pos][i]) Next[pos][i] = Next[fail[pos]][i];
 61                 else
 62                 {
 63                     fail[Next[pos][i]] = Next[fail[pos]][i];
 64                     q.push(Next[pos][i]);
 65                 }
 66                 if(val[fail[Next[pos][i]]]) val[Next[pos][i]] = 1;
 67             }
 68         }
 69     }
 70 
 71 }ACA;
 72 
 73 const int INF = 100000;
 74 int dp[1010][1010];
 75 int solve()
 76 {
 77     int len = strlen(s);
 78     for(int i = 0; i <= len; i++)
 79         for(int j = 0; j < ACA.sz; j++)
 80             dp[i][j] = INF;
 81     dp[0][0] = 0;
 82     for(int i = 0; i < len; i++)
 83     {
 84         for(int j = 0; j < ACA.sz; j++)
 85         {
 86             if(dp[i][j] == INF) continue;
 87             for(int k = 0; k < 4; k++)
 88             {
 89                 if(ACA.val[ACA.Next[j][k]]) continue;
 90                 int & t = dp[i+1][ACA.Next[j][k]];
 91                 t = min(t, dp[i][j] + (str[k] != s[i]) );
 92             }
 93         }
 94     }
 95     int ans = INF;
 96     for(int i = 0; i < ACA.sz; i++) ans = min(ans, dp[len][i]);
 97     return ans == INF ? -1 : ans;
 98 }
 99 
100 int main(void)
101 {
102     int kase = 0;
103     while(~scanf("%d", &N) && N)
104     {
105         ACA.init();
106         for(int i = 1; i <= N; i++)
107         {
108             char tmp[22];
109             scanf("%s", tmp);
110             ACA.insert(tmp);
111         }
112         ACA.build();
113         scanf("%s", s);
114         printf("Case %d: %d
", ++kase, solve());
115     }
116     return 0;
117 }

Aguin

12.8

HNU 11187 Emoticons :-)

找到一个就回原点。gets读。

  1 #include <iostream>
  2 #include <cstdio>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <queue>
  6 using namespace std;
  7 const int maxnode = 2222, sigma_size = 256;
  8 int N, M;
  9 
 10 struct Ac_auto
 11 {
 12     int Next[maxnode][sigma_size];
 13     int fail[maxnode];
 14     int val[maxnode];
 15     int sz;
 16 
 17     Ac_auto(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 18     void init(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 19 
 20     int idx(char c){return c;}
 21 
 22     void insert(char *s)
 23     {
 24         int u = 0, n = strlen(s);
 25         for(int i = 0; i < n; i++)
 26         {
 27             int c = idx(s[i]);
 28             if(!Next[u][c])
 29             {
 30                 memset(Next[sz], 0, sizeof(Next[sz]));
 31                 val[sz] = 0;
 32                 Next[u][c] = sz++;
 33             }
 34             u = Next[u][c];
 35         }
 36         val[u] = 1;
 37     }
 38 
 39     void build()
 40     {
 41         queue<int> q;
 42         fail[0] = 0;
 43         for(int i = 0; i < sigma_size; i++) if(Next[0][i])
 44         {
 45             fail[Next[0][i]] = 0;
 46             q.push(Next[0][i]);
 47         }
 48         while(!q.empty())
 49         {
 50             int pos = q.front(); q.pop();
 51             for(int i = 0; i < sigma_size; i++)
 52             {
 53                 if(!Next[pos][i]) Next[pos][i] = Next[fail[pos]][i];
 54                 else
 55                 {
 56                     fail[Next[pos][i]] = Next[fail[pos]][i];
 57                     if(val[fail[Next[pos][i]]]) val[Next[pos][i]] = 1;
 58                     q.push(Next[pos][i]);
 59                 }
 60             }
 61         }
 62     }
 63 
 64     int cal(char * s)
 65     {
 66         int ret = 0;
 67         int len = strlen(s), pos = 0;
 68         for(int i = 0; i < len; i++)
 69         {
 70             pos = Next[pos][idx(s[i])];
 71             int tmp = pos, flag = 0;
 72             while(tmp)
 73             {
 74                 if(val[tmp]) {flag = 1; break;}
 75                 tmp = fail[tmp];
 76             }
 77             if(flag) {pos = 0; ret++;}
 78         }
 79         return ret;
 80     }
 81 
 82 }ACA;
 83 
 84 int main(void)
 85 {
 86     while(~scanf("%d %d", &N, &M) && N && M)
 87     {
 88         getchar();
 89         ACA.init();
 90         for(int i = 1; i <= N; i++)
 91         {
 92             char tmp[111];
 93             gets(tmp);
 94             ACA.insert(tmp);
 95         }
 96         ACA.build();
 97         int ans = 0;
 98         for(int i = 1; i <= M; i++)
 99         {
100             char s[111];
101             gets(s);
102             ans += ACA.cal(s);
103         }
104         printf("%d
", ans);
105     }
106     return 0;
107 }

Aguin

ZOJ 3545 Rescue the Rabbit

更重要的是状压dp的部分。

  1 #include <iostream>
  2 #include <cstdio>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <queue>
  6 using namespace std;
  7 const int maxnode = 1111, sigma_size = 4;
  8 int n, l, w[10];
  9 int dp[2][1111][1111];
 10 
 11 struct Ac_auto
 12 {
 13     int Next[maxnode][sigma_size];
 14     int fail[maxnode];
 15     int val[maxnode];
 16     int sz;
 17 
 18     Ac_auto(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 19     void init(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 20 
 21     int idx(char c)
 22     {
 23         if(c == 'A') return 0;
 24         else if(c == 'G') return 1;
 25         else if(c == 'T') return 2;
 26         return 3;
 27     }
 28 
 29     void insert(char *s, int v)
 30     {
 31         int u = 0, n = strlen(s);
 32         for(int i = 0; i < n; i++)
 33         {
 34             int c = idx(s[i]);
 35             if(!Next[u][c])
 36             {
 37                 memset(Next[sz], 0, sizeof(Next[sz]));
 38                 val[sz] = 0;
 39                 Next[u][c] = sz++;
 40             }
 41             u = Next[u][c];
 42         }
 43         val[u] |= (1 << v);
 44     }
 45 
 46     void build()
 47     {
 48         queue<int> q;
 49         fail[0] = 0;
 50         for(int i = 0; i < sigma_size; i++) if(Next[0][i])
 51         {
 52             fail[Next[0][i]] = 0;
 53             q.push(Next[0][i]);
 54         }
 55         while(!q.empty())
 56         {
 57             int pos = q.front(); q.pop();
 58             for(int i = 0; i < sigma_size; i++)
 59             {
 60                 if(!Next[pos][i]) Next[pos][i] = Next[fail[pos]][i];
 61                 else
 62                 {
 63                     fail[Next[pos][i]] = Next[fail[pos]][i];
 64                     q.push(Next[pos][i]);
 65                 }
 66                 val[Next[pos][i]] |= val[fail[Next[pos][i]]];
 67             }
 68         }
 69     }
 70 
 71     void solve()
 72     {
 73         memset(dp[0], 0, sizeof(dp[0]));
 74         dp[0][0][0] = 1;
 75         int cur = 1;
 76         for(int i = 0; i < l; i++)
 77         {
 78             memset(dp[cur], 0, sizeof(dp[cur]));
 79             cur ^= 1;
 80             for(int j = 0; j < sz; j++)
 81             {
 82                 for(int k = 0; k < (1 << n); k++)
 83                 {
 84                     if(!dp[cur][j][k]) continue;
 85                     for(int p = 0; p < 4; p++) dp[cur^1][Next[j][p]][k|val[Next[j][p]]] = 1;
 86                 }
 87             }
 88         }
 89         int ans = -1;
 90         for(int i = 0; i < sz; i++)
 91         {
 92             for(int j = 0; j < (1 << n); j++)
 93             {
 94                 if(!dp[cur^1][i][j]) continue;
 95                 int tmp = 0;
 96                 for(int k = 0; k < n; k++)
 97                     if( j & (1 << k) ) tmp += w[k];
 98                 ans = max(ans, tmp);
 99             }
100         }
101         if(ans == -1) puts("No Rabbit after 2012!");
102         else printf("%d
", ans);
103     }
104 
105 }ACA;
106 
107 int main(void)
108 {
109     while(~scanf("%d %d", &n, &l))
110     {
111         ACA.init();
112         for(int i = 0; i < n; i++)
113         {
114             char tmp[111];
115             scanf("%s %d", tmp, w+i);
116             ACA.insert(tmp, i);
117         }
118         ACA.build();
119         ACA.solve();
120     }
121     return 0;
122 }

Aguin

12.9

什么都没干。

12.10

补个CF。

CF 606 C Sorting Railway Cars

和一个BC很像。看最长的连续子列有多长。

 1 #include <iostream>
 2 #include <cstdio>
 3 using namespace std;
 4 const int maxn = 1e5 + 10;
 5 int a[maxn];
 6 
 7 int main(void)
 8 {
 9     int N, Max = 0;
10     scanf("%d", &N);
11     for(int i = 1; i <= N; i++)
12     {
13         int x;
14         scanf("%d", &x);
15         a[x] = 1;
16         a[x] += a[x-1];
17         if(a[x] > Max) Max = a[x];
18     }
19     printf("%d
", N - Max);
20     return 0;
21 }

Aguin

CF 606 D Lazy Student

构造一颗菊花树即可。加边顺序弄错WA到死。

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <algorithm>
 4 using namespace std;
 5 typedef long long LL;
 6 const int maxn = 1e5 + 10;
 7 
 8 struct edge
 9 {
10     int id, used, l;
11     int from, to;
12 }e[maxn];
13 
14 bool cmp1(edge A, edge B)
15 {
16     if(A.l != B.l) return A.l < B.l;
17     return A.used > B.used;
18 }
19 
20 bool cmp2(edge A, edge B)
21 {
22     return A.id < B.id;
23 }
24 
25 int main(void)
26 {
27     int N, M;
28     scanf("%d%d", &N, &M);
29     for(int i = 1; i <= M; i++)
30     {
31         scanf("%d%d", &e[i].l, &e[i].used);
32         e[i].id = i;
33     }
34     sort(e+1, e+1+M, cmp1);
35     int cnt = 0, tot = 0, ok = 1;
36     for(int i = 1; i <= M; i++)
37     {
38         if(e[i].used) cnt++;
39         else
40         {
41             tot++;
42             if((LL) cnt * (cnt - 1) / 2 < tot) {ok = 0; break;}
43         }
44     }
45     if(ok)
46     {
47         int t1 = 1, t2 = 1;
48         for(int i = 1; i <= M; i++) if(e[i].used)
49         {
50             e[i].from = 1;
51             e[i].to = ++t1;
52         }
53         for(int i = 3; i <= N; i++)
54         {
55             if(t2 > M) break;
56             for(int j = 2; j < i; j++)
57             {
58                 if(t2 > M) break;
59                 while(e[t2].used) t2++;
60                 e[t2].from = i;
61                 e[t2].to = j;
62                 t2++;
63             }
64         }
65         sort(e+1, e+1+M, cmp2);
66         for(int i = 1; i <= M; i++) printf("%d %d
", e[i].from, e[i].to);
67     }
68     else puts("-1");
69     return 0;
70 }

Aguin

12.11

HDU 3341 Lost's revenge

先是Hash错。自己老是搞很奇怪的Hash。

然后发现了一个AC自动机的写法上的错误。

更新val的时候应该在//的位置。而不是循环外（尽管一些题目是对的。

返回去把写法上不确定的题都重新交了一次。暂无发现问题。

  1 #include <iostream>
  2 #include <cstdio>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <queue>
  6 using namespace std;
  7 const int maxnode = 555, sigma_size = 4;
  8 int N, tot, num[4], o[4], tmp[4], dp[25555][555];
  9 char s[100];
 10 
 11 struct Ac_auto
 12 {
 13     int Next[maxnode][sigma_size];
 14     int fail[maxnode];
 15     int val[maxnode];
 16     int sz;
 17 
 18     Ac_auto(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 19     void init(){sz = 1; memset(Next[0], 0, sizeof(Next[0]));}
 20 
 21     int idx(char c)
 22     {
 23         if(c == 'A') return 0;
 24         else if(c == 'G') return 1;
 25         else if(c == 'C') return 2;
 26         return 3;
 27     }
 28 
 29     void insert(char *s)
 30     {
 31         int u = 0, n = strlen(s);
 32         for(int i = 0; i < n; i++)
 33         {
 34             int c = idx(s[i]);
 35             if(!Next[u][c])
 36             {
 37                 memset(Next[sz], 0, sizeof(Next[sz]));
 38                 val[sz] = 0;
 39                 Next[u][c] = sz++;
 40             }
 41             u = Next[u][c];
 42         }
 43         val[u] += 1;
 44     }
 45 
 46     void build()
 47     {
 48         queue<int> q;
 49         fail[0] = 0;
 50         for(int i = 0; i < sigma_size; i++) if(Next[0][i])
 51         {
 52             fail[Next[0][i]] = 0;
 53             q.push(Next[0][i]);
 54         }
 55         while(!q.empty())
 56         {
 57             int pos = q.front(); q.pop();
 58             for(int i = 0; i < sigma_size; i++)
 59             {
 60                 if(!Next[pos][i]) Next[pos][i] = Next[fail[pos]][i];
 61                 else
 62                 {
 63                     fail[Next[pos][i]] = Next[fail[pos]][i];
 64                     q.push(Next[pos][i]);
 65                     val[Next[pos][i]] += val[fail[Next[pos][i]]]; //update val[]
 66                 }
 67             }
 68         }
 69     }
 70 
 71     int solve()
 72     {
 73         int ret = 0;
 74         memset(dp, -1, sizeof(dp));
 75         dp[0][0] = 0;
 76         for(int i = 0; i <= tot; i++)
 77         {
 78             for(int j = 0; j < sz; j++)
 79             {
 80                 if(dp[i][j] == -1) continue;
 81                 int p = i;
 82                 for(int k = 3; k >= 0; k--) tmp[k] = p / num[k], p %= num[k];
 83                 for(int k = 0; k < 4; k++)
 84                 {
 85                     if(tmp[k] >= o[k]) continue;
 86                     dp[i+num[k]][Next[j][k]] = max(dp[i+num[k]][Next[j][k]], dp[i][j] + val[Next[j][k]]);
 87                 }
 88                 ret = max(ret, dp[i][j]);
 89             }
 90         }
 91         return ret;
 92     }
 93 
 94 }ACA;
 95 
 96 int main(void)
 97 {
 98     int kase = 0;
 99     while(~scanf("%d", &N) && N)
100     {
101         ACA.init();
102         for(int i = 0; i < N; i++)
103         {
104             char tmp[111];
105             scanf("%s", tmp);
106             ACA.insert(tmp);
107         }
108         ACA.build();
109         scanf("%s", s);
110         memset(o, 0, sizeof(o));
111         for(int i = 0; s[i]; i++)
112         {
113             if(s[i] == 'A') o[0]++;
114             else if(s[i] == 'G') o[1]++;
115             else if(s[i] == 'C') o[2]++;
116             else o[3]++;
117         }
118 
119         num[0] = 1;
120         num[1] = o[0] + 2;
121         num[2] = num[1] * (o[1] + 1) + 1;
122         num[3] = num[2] * (o[2] + 1) + 1;
123 
124         tot = 0;
125         for(int i = 0; i < 4; i++) tot += num[i] * o[i];
126 
127         printf("Case %d: %d
", ++kase, ACA.solve());
128     }
129     return 0;
130 }

Aguin

12.12

打个BC。

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原文地址：https://www.cnblogs.com/Aguin/p/5027267.html