• 2019江西省省赛


     

     1 #include <bits/stdc++.h>
     2 
     3 using namespace std;
     4 typedef long long ll;
     5 char c[1000];
     6 ll l,k1,k2,k3,k4,k,kk,d;
     7 
     8 int main(){
     9     while (~scanf("%lld",&l)) {
    10         scanf("%s", c);
    11         k1=k2=k3=k4=0;
    12         for (int i = 0; i < l; i++) {
    13             if (c[i] == 'a') k1++;
    14             if (c[i] == 'v') k2++;
    15             if (c[i] == 'i') k3++;
    16             if (c[i] == 'n') k4++;
    17         }
    18         k = k2 * k1 * k3 * k4;
    19         kk = l * l * l * l;
    20         if (k == 0) {
    21             printf("0/1
    ");
    22             continue;
    23         }
    24         d = __gcd(k, kk);
    25         k = k / d;
    26         kk = kk / d;
    27         printf("%lld/%lld
    ", k, kk);
    28     }
    29 }
    View Code

     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 
     4 int a[2000],b[2000],c[2000],d[2000],t,f,n,m;
     5 int main() {
     6     while (~scanf("%d%d",&n,&m)) {
     7         for (int i = 1; i <= n; i++) {
     8             scanf("%d", &a[i]);
     9         }
    10         for (int i = 1; i <= m; i++) {
    11             scanf("%d", &b[i]);
    12         }
    13         t=0;
    14         while (1) {
    15             memset(c,0, sizeof(c));
    16             memset(d,0, sizeof(d));
    17             for (int i = 1; i <= n; i++) {
    18                 c[a[i]] = 1;
    19             }
    20             for (int i = 1; i <= m; i++) {
    21                 d[b[i] + t] = 1;
    22             }
    23             f=0;
    24             for (int i=1;i<=1000;i++){
    25                 if (c[i]&&d[i]==1){
    26                     f=1;
    27                     break;
    28                 }
    29             }
    30             if (!f){
    31                 printf("%d
    ",t);
    32                 break;
    33             }
    34             t++;
    35         }
    36     }
    37 }
    View Code

     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 const int mod = 1000000007;
     4 long long quickpow(long long a, long long b) {
     5     if (b < 0) return 0;
     6     long long ret = 1;
     7     a %= mod;
     8     while(b) {
     9         if (b & 1) ret = (ret * a) % mod;
    10         b >>= 1;
    11         a = (a * a) % mod;
    12     }
    13     return ret;
    14 }
    15 long long inv(long long a) {
    16     return quickpow(a, mod - 2);
    17 }
    18 int main() {
    19     long long  n;
    20     scanf("%lld",&n);
    21     long long ans=((n+1)*inv(2*n))%mod;
    22     printf("%lld
    ",ans);
    23     return 0;
    24 }
    View Code

     1 #include <bits/stdc++.h>
     2 
     3 using namespace std;
     4 typedef long long ll;
     5 ll n,b[1000],a[2000],m,lcm,x[2000],k,sum;
     6 
     7 ll gcd(ll a,ll b){
     8     if (!b){
     9         return a;
    10     }
    11     return gcd(b,a%b);
    12 }
    13 int main() {
    14     while (~scanf("%lld%lld", &n,&m)) {
    15         for (int i=1;i<=n;i++){
    16             scanf("%lld",&a[i]);
    17             b[a[i]]++;
    18         }
    19         lcm=1;
    20         for (int i=1;i<=10;i++){
    21             if (b[i]){
    22                 lcm=i/gcd(i,lcm)*lcm;
    23             }
    24         }
    25         for (int i=1;i<=n;i++){
    26             x[i]=lcm/a[i];
    27             sum+=x[i];
    28         }
    29         if (m%sum==0){
    30             k=m/sum;
    31             printf("Yes
    ");
    32             for (int i=1;i<=n;i++){
    33                 printf("%lld",x[i]*k);
    34                 if (i==n){
    35                     printf("
    ");
    36                 }else{
    37                     printf(" ");
    38                 }
    39             }
    40         }else{
    41             printf("No
    ");
    42         }
    43     }
    44 }
    View Code

    1 #include<bits/stdc++.h>
    2 using namespace std;
    3 
    4 int main()
    5 {
    6     int x,y;
    7     scanf("%d%d",&x,&y);
    8     printf("%d
    ",(x*x-y*y)/4);
    9 }
    View Code

     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 char c[100];
     4 double ans;
     5 int n,l;
     6 int main() {
     7     while (~scanf("%d", &n)) {
     8         ans=0;
     9         for (int i = 1; i <= n; i++) {
    10             scanf("%s", &c);
    11             l = strlen(c);
    12             if (c[l - 1] < '5') {
    13                 ans -= 0.001 * (c[l - 1] - '0');
    14             } else {
    15                 ans += (10 - (c[l - 1] - '0')) * 0.001;
    16             }
    17         }
    18         printf("%.3lf
    ", ans);
    19     }
    20 }
    View Code

     1 #include<bits/stdc++.h>
     2 
     3 using namespace std;
     4 vector<int>a[105];
     5 int ans,n,c,x,s1,s2,k1,k2,sum,tmp;
     6 int main() {
     7     scanf("%d%d", &n, &c);
     8     for (int i = 1; i <= n; i++) {
     9         scanf("%d", &x);
    10         a[x].push_back(i);
    11     }
    12     for (int i = 1; i <= c; i++) {
    13         for (int j = 1; j <= c; j++) {
    14             if (i != j) {
    15                 s1 = a[i].size();
    16                 s2 = a[j].size();
    17                 k1 = k2 = sum = tmp = 0;
    18                 while (1) {
    19                     while (k1 < s1 && a[i][k1] < tmp) {
    20                         k1++;
    21                     }
    22                     if (k1 == s1) {
    23                         break;
    24                     }
    25                     tmp = a[i][k1];
    26                     sum++;
    27                     while (k2 < s2 && a[j][k2] < tmp) {
    28                         k2++;
    29                     }
    30                     if (k2 == s2) {
    31                         break;
    32                     }
    33                     tmp = a[j][k2];
    34                     sum++;
    35                 }
    36                 ans = max(ans, sum);
    37             }
    38         }
    39     }
    40     printf("%d
    ", ans);
    41 }
    View Code

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  • 原文地址:https://www.cnblogs.com/Accpted/p/11222566.html
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