【链接】 我是链接,点我呀:)
【题意】
【题解】
同一个联通块里面答案都一样。 把每个联通块的答案都算出来 然后赋值就好【代码】
#include <bits/stdc++.h>
using namespace std;
const int N = 1000;
int n,m,k;
int dx[4] = {0,0,1,-1};
int dy[4] = {1,-1,0,0};
char s[N+10][N+10];
bool bo[N+10][N+10];
int ans[N+10][N+10];
pair<int,int> dl[N*N+10];
int head,tail;
int main(){
ios::sync_with_stdio(0),cin.tie(0);
cin >> n >> m >> k;
for (int i = 1;i <= n;i++) cin >> (s[i]+1);
for (int i = 1;i <= n;i++)
for (int j = 1;j <= m;j++)
if (!bo[i][j] && s[i][j]=='.'){
head = 1,tail = 1;
dl[head] = {i,j};
int cnt = 0;
bo[i][j] = true;
while (head<=tail){
int x = dl[head].first,y = dl[head].second;
head++;
for (int l = 0;l < 4;l++){
int tx = x + dx[l],ty = y + dy[l];
if (tx>=1 && tx <= n && ty>=1 && ty<=m){
if (!bo[tx][ty] && s[tx][ty]=='.'){
bo[tx][ty] = true;
tail++;
dl[tail].first = tx;
dl[tail].second = ty;
}else if (s[tx][ty]=='*'){
cnt++;
}
}
}
}
for (int i = 1;i <= tail;i++){
ans[dl[i].first][dl[i].second] = cnt;
}
}
for (int i = 1;i <= k;i++){
int x,y;
cin >> x >> y;
cout<<ans[x][y]<<endl;
}
return 0;
}