• Python流程控制语句练习题


    '''
    1、求偶数元素的和[1,2,1,2,3,3,6,5,8]

    b1 = 0
    a1 = [1,2,1,2,3,3,6,5,8]
    for i in a1:
    if i%2 == 0:#当i除以2余数为0,偶数
    b1 += i
    print(b1)
    ==============================
    2、写代码:计算 1 - 2 + 3 - 4 + ... + 99 中除了88以外所有数的总和?

    a1 = 0
    for i in range(1,100):
    if i%2 == 0: # 当i除以2余数为0,偶数
    if i == 88:
    continue
    else:
    a1 -= i
    else:
    a1 += i
    print(a1)
    ==============================
    3、求1+2+3+4+……+100的和.

    a1 = 0
    for i in range(1,101): #[1,2,3,...,100]
    a1 += i
    print(a1)
    ==============================

    4、斐波那契数列指的是这样一个数列 0, 1, 1, 2, 3, 5, 8, 13,特别指出:第0项是0,第1项是第一个1。从第三项开始,每一项都等于前两项之和。
    计算索引为10的斐波那契数列对应的值

    思路:
    nterms = 5
    n1 = 0
    n2 = 1
    n3 = n1 + n2
    n4 = n2 +n3
    if nterms == 1:
    print(n1)
    elif nterms == 2:
    print(n2)
    elif nterms == 3:
    n3 = n1 + n2
    print(n3)
    elif nterms == 4:
    n4 = n2 + n3
    print(n4)
    elif nterms == 5:
    n5 = n3 + n4
    print(n5)
    ...
    ==============================

    方法:
    weizhi = int(input("请输入斐波那契数列对应的索引位置:>>"))
    n1 = 0
    n2 = 1
    count = 2
    if weizhi == 1:
    print(n1,",")
    elif weizhi == 2:
    print(n1,",",n2,",")
    else:
    print(n1,",",n2,end=" , ")
    while count < weizhi:
    n3 = n1 + n2
    print(n3,end=" , ")
    n1 = n2
    n2 = n3
    count +=1
    ==============================
    5、打印菱形小星星
    *
    ***
    *****
    *******
    *********
    ***********
    ***********
    *********
    *******
    *****
    ***
    *

    思路:
    第一行 空格3 *1 (即*个数为7-3*2)

    第二行 空格2 *3 (即*个数为7-2*2)

    第三行 空格1 *5 (即*个数为7-1*2)

    第四行 空格0 *7

    第五行 空格1 *5

    第六行 空格2 *3

    第七行 空格3 *1

    方法:
    n = 7
    for i in range(-int(n/2),int(n/2)+1):
    print(" "*abs(i),"*"*abs(n-abs(i)*2))
    ==============================
    '''
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  • 原文地址:https://www.cnblogs.com/A121/p/16047516.html
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