• PAT 1147 Heaps


    In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))

    Your job is to tell if a given complete binary tree is a heap.

    Input Specification:
    Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.

    Output Specification:
    For each given tree, print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.

    Sample Input:

    3 8
    98 72 86 60 65 12 23 50
    8 38 25 58 52 82 70 60
    10 28 15 12 34 9 8 56

    Sample Output:

    Max Heap
    50 60 65 72 12 23 86 98
    Min Heap
    60 58 52 38 82 70 25 8
    Not Heap
    56 12 34 28 9 8 15 10

    #include<iostream> //水题
    #include<vector>
    using namespace std;
    vector<int> v;
    int m, n, flag=0;
    void postorder(int r){
    	if(r*2+1<n)
    		postorder(r*2+1);
    	if(2*r+2<n)
    		postorder(2*r+2);
    	flag++==0?cout<<v[r]:cout<<" "<<v[r];
    }
    int main(){
    	cin>>m>>n;
    	v.resize(n);
    	for(int i=0; i<m; i++){
    		int type=-1;
    		flag=0;
    		for(int j=0; j<n; j++)
    			cin>>v[j];
    		if(v[0]>v[1]) type=1;
    		for(int i=0; i<=(n-1)/2; i++)
    			if(type==1&&(v[i*2+1]>v[i]||(i*2+2<n&&v[i*2+2]>v[i]))){
    				type=0;
    				break;
    			}else if(type==-1&&(v[i*2+1]<v[i]||(i*2+2<n&&v[i*2+2]<v[i]))){
    				type=0;
    				break;
    			} 
    		if(type==1) cout<<"Max Heap"<<endl;
    		else if(type==-1) cout<<"Min Heap"<<endl;
    		else cout<<"Not Heap"<<endl;
    		postorder(0);
    		cout<<endl;
    	}
    }
    
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  • 原文地址:https://www.cnblogs.com/A-Little-Nut/p/9652316.html
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