Given a 2D binary matrix filled with 0’s and 1’s, find the largest square containing only 1’s and return its area.
For example, given the following matrix:
1 0 1 0 0
1 0 1 1
1 1 11 1
1 0 0 1 0
Return 4.
class Solution {
public:
int maximalSquare(vector<vector<char>>& matrix) {
if(matrix.size()==0) return 0;
int len=0;
for(int i=0; i<matrix.size(); i++)
if(matrix[i][0]=='1')
len=1;
for(int i=0; i<matrix[0].size(); i++)
if(matrix[0][i]=='1')
len=1;
for(int i=1; i<matrix.size(); i++)
for(int j=1; j<matrix[0].size(); j++){
if(matrix[i][j]!='0'){
matrix[i][j]='0'+(min(matrix[i-1][j]-'0',min(matrix[i][j-1]-'0',matrix[i-1][j-1]-'0'))+1);
len=max(len,matrix[i][j]-'0');
}
}
return len*len;
}
};