地址:https://leetcode-cn.com/problems/water-bottles/
<?php /** * Created by PhpStorm. * User: huahua * Date: 2020/10/21 * Time: 下午2:37 小区便利店正在促销,用 numExchange 个空酒瓶可以兑换一瓶新酒。你购入了 numBottles 瓶酒。 如果喝掉了酒瓶中的酒,那么酒瓶就会变成空的。 请你计算 最多 能喝到多少瓶酒。 示例 1: 输入:numBottles = 9, numExchange = 3 输出:13 解释:你可以用 3 个空酒瓶兑换 1 瓶酒。 所以最多能喝到 9 + 3 + 1 = 13 瓶酒。 示例 2: 输入:numBottles = 15, numExchange = 4 输出:19 解释:你可以用 4 个空酒瓶兑换 1 瓶酒。 所以最多能喝到 15 + 3 + 1 = 19 瓶酒。 示例 3: 输入:numBottles = 5, numExchange = 5 输出:6 示例 4: 输入:numBottles = 2, numExchange = 3 输出:2 提示: 1 <= numBottles <= 100 2 <= numExchange <= 100 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/water-bottles 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 */ class Solution { /** * @param Integer $numBottles * @param Integer $numExchange * @return Integer */ function numWaterBottles1($numBottles, $numExchange) { $count = $numBottles; while($numBottles >= $numExchange && $numBottles > 0){ $count = $count + (int)($numBottles/$numExchange); $numBottles = ($numBottles % $numExchange)+ (int)($numBottles/$numExchange); } return $count; } function numWaterBottles($numBottles, $numExchange) { return (int)(($numBottles * $numExchange-1)/($numExchange-1)); } }