• 复利4.0


    #include<stdio.h>
    
    #include<math.h>
    
    double principal=0,mount=0;
    
    int year=0;
    
    int n=1;
    
    double rate;
    
     void meu()
     {
    printf("|----------------------------------------|
    ");
    
    printf("|          1.复利计算                    |
    ");
    
    printf("|          2.单利计算                    |
    ");
    
    printf("|          3.计算本金                    |
    ");
    
    printf("|          4.年限计算                    |
    ");
    
    printf("|          5.利率估算                    |
    ");
    
    printf("|          6.等额定投                    |
    ");
    
    printf("|          7.等额还款                    |
    ");
    
    printf("|----------------------------------------|
    ");
     } 
    
    void danli(){
    
        printf("请输入的本金:");
    
        scanf("%lf",&principal);
    
        printf("请输入年限:");
    
        scanf("%d",&year);
        printf("请输入年利率:");
    
        scanf("%lf",&rate);
    
        mount=principal+principal*rate*year;
    
        printf("本息为:%.2lf
    ",mount); 
    
    }
    
     
    
    void fuli(){
    
     
    
        printf("请输入本金:");
    
        scanf("%lf",&principal);
    
        printf("请输入年限:");
    
        scanf("%d",&year);
    
        printf("请输入年利率:");
    
        scanf("%lf",&rate);
    
        printf("请输入年复利次数:");
    
        scanf("%d",&n);
    
        rate=pow((1+rate/n),n)-1;
    
        mount=principal*pow((1+rate),year);
    
        printf("本息为:%.2lf
    ",mount);
    
     
    
    }
    
     
    
    void principaljisuan(){
    
        printf("请输入期望的收益:");
    
        scanf("%lf",&mount);  
    
        printf("请输入年限:");
    
        scanf("%d",&year);
    
        printf("请输入年利率:");
    
        scanf("%lf",&rate);
    
        printf("请输入年复利次数:");
    
        scanf("%d",&n);
    
        rate=pow((1+rate/n),n)-1;
    
        principal=mount/pow((1+rate),year);
    
        printf("输出所需本金为:%.2lf
    ",principal);
    
     
    
    }
    
     
    void time()
    {
        int flat=0;
        
        printf("请输入本利和:"); 
        scanf("%lf",&mount); 
        printf("请输入年回报率:"); 
        scanf("%lf",&rate); 
        printf("请输入本金:"); 
        scanf("%lf",&principal); 
        for(n=1;n<100;n++)    //穷举法求100年满足的计息期数
        {
            if((principal*(pow((1+rate),n)))>=mount)
            {
                printf("计息期数:%d
    
    ",n);
                flat=1;
                break;
            }
        }
        if(flat==0)
            printf("在100年内没有符合计息期数!
    
    ");
        
    }
    
    void lilv()
    {
        
        printf("请输入本利和:"); 
        scanf("%lf",&mount); 
        printf("请输入复利次数(年):"); 
        scanf("%d",&year); 
        printf("请输入本金:"); 
        scanf("%lf",&principal); 
        rate=pow(mount/principal, 1.0/year)-1;
        printf("年利率为:%lf",rate);
    }
    void yearmount()//计算年金终值
     {
      int n;
         printf("存入本金:");
         scanf("%lf",&principal);
        printf("存入年限:");
        scanf("%d",&year);
         printf("年利率:");
         scanf("%lf",&rate);
         printf("		1:按年投资
    		2:按月投资
    ");
     A:printf("请选择你要的功能<1|2>:");
       scanf("%d",&n);
       if(n==1)
       {
           mount=principal*(pow(1+rate,year)-1)/rate;
          
       }
       else if(n==2)
       {
           mount=principal*12*(1+rate)*(pow(1+rate,year)-1)/rate;
       }
       else
       {
           printf("输入有误!请重新输入
    ");
           goto A;
       }
       printf("%d年后的总产值:%.4lf
    ",year,mount);
      
     }
     void huankuan()
     {
    
         printf("贷款金额:");
         scanf("%lf",&mount);
         printf("贷款年限:");
         scanf("%d",&year);
        printf("年利率:");
         scanf("%lf",&rate);
         principal=mount*rate/(12*(1-rate)*(pow(1-rate,year)-1));
        printf("贷款%.4lf每月需要还款%.4lf
    ",mount,principal);
     }
    
    
     main(){
         while(1){
        int num=0;
    meu();
    
    printf("请输入选择:");
    
    scanf("%d",&num);
    
    switch(num){
    
    case 1:
    
        fuli(); 
    
        break;
    
    case 2:
    
       danli();
    
        break;
    
    case 3:
    
        principaljisuan();
    
    break;
     case 4:
    
         time();
                
     break;
    
     case 5:
    
       lilv();
    
        break;
    case 6:
    
       yearmount();
    
        break;
    
        case 7:
    
       huankuan();
    
        break;
    
    
    
    
    }
    
     }
     }
  • 相关阅读:
    Parquet 格式文件
    spark DataFrame 常见操作
    scala 资料集结
    scala 基础知识总结
    python 玩具代码
    大数据常见错误解决方案(转载)
    scala 基础到高阶
    win8.1简单快速安装phpnow的方法
    如何搭建本地WordPress
    Delphi Code Editor 之 几个特性(转)
  • 原文地址:https://www.cnblogs.com/7763255qw/p/5299143.html
Copyright © 2020-2023  润新知