1058 A+B in Hogwarts (20分)(水)

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

题目分析:进制转化

#define _CRT_SECURE_NO_WARNINGS
#include <climits>
#include<iostream>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<algorithm>
#include<string>
#include<cmath>
using namespace std;
long long N1[3];
long long N2[3];
long long Flag[3];
long long C[3] = { 10000000,17,29 };
int main()
{
    scanf("%lld.%lld.%lld %lld.%lld.%lld", &N1[0], &N1[1], &N1[2], &N2[0], &N2[1], &N2[2]);
    for (long long i = 2; i >=0; i--)
    {
        N1[i] += N2[i] + Flag[i];
        if (N1[i] >=C[i]&&i!=0)
        {
            Flag[i - 1] = N1[i]/C[i];
            N1[i] %= C[i];
        }
    }
    printf("%lld.%lld.%lld", N1[0], N1[1], N1[2]);
}