for(初始条件;比较;状态改变 )
{
循环体
}
打印100遍helloword
for(int i=0;i<100,i++)
{
console.writeline("helloword");
}
求1-100的和
int s = 0;
for(int i=1;i<=100;i++)
{
s = s + i;
}
Console.WriteLine(s);
Console.ReadLine();
100以内所有与7相关的数和,奇数和,偶数和
int s = 0;
for (int i = 1; i <= 100; i++)
{
if ((i%7==0)||(i%10==7)||(i/10 ==7))
{
s = s + i;
}
}
Console.WriteLine(s);
Console.ReadLine();
100以内的所有质数和
int sum = 0;
for (int i=2;i<=100;i++)
{
int a = 0;
for (int j = 1; j <=i; j++)
if (i % j == 0)//如果i能被它本身和1以外的数整除,那么他就不是质数
{
a++;
}
}
if (a == 2) //能被整除的数只有两个,即为质数
{
sum = sum + i;
}
}
Console.Write(sum);
Console.ReadLine();
打印☆,排列成图形
右上
for (int m=1;m <10;m++)
{
for(int n=1;n<=m;n++)
{
Console.Write("☆");
}
Console.Write("
");
}
右下
for (int m = 10; m > 1; m--)
{
for (int n = 1; n < m; n++)
{
Console.Write("☆");
}
Console.Write("
");
}
左下
for (int m = 1; m < 10; m++)
{
for (int n = 1; n < m; n++)
{
Console.Write(" ");
}
for (int l = 10; l > m; l--)
{
Console.Write("☆");
}
Console.Write("
");
}
左上
for (int m = 1; m < 10; m++)
{
for (int n = 9; n >m; n--)
{
Console.Write(" ");
}
for (int l = 1; l <= m;l++ )
{
Console.Write("☆");
Console.Write("
");
}
上半部分
for (int m = 1; m < 10; m++)
{
for (int n = 9; n > m; n--)
{
Console.Write(" ");
}
for (int l = 1; l <= (2 * m - 1); l++)
{
Console.Write("☆");
}
Console.Write("
");
}
下半部分
for (int m = 1; m < 9; m++)
{
for (int l = 1; l <= m; l++)
{
Console.Write(" ");
}
for (int n = 1; n <= (2 * (9 - m) - 1); n++)
{
Console.Write("☆");
}
Console.Write("
");
}
一对幼兔一个月后长成小兔,再过一个月长成成兔并生下一对小兔,两年后有多少对兔子?
int a = 1, b = 0, c = 0;
for (int i = 2; i <= 24; i++)
{
if (i == 1)
{
c = 0;
b = 0;
a = 1;
}
else
{
c = c + b;
b = a;
a = c;
}
Console.WriteLine("第{0}个月,成兔数量:{1}小兔数量{2}:幼兔数量{3}", i, c, b, a);
Console.ReadLine();
}
Console.WriteLine("总数量为" + (c + a + b));
Console.ReadLine();
穷举问题:铅笔一支2元,笔盒5元,文件夹10元,彩笔5元,买正好100块的文具,每种至少买一种,
列举出所有方法
for (int qianbi = 1; qianbi <= 50; qianbi++)
{
for (int he = 1; he <= 20; he++)
{
for (int wenjianjia = 1; wenjianjia <= 10; wenjianjia++)
{
for (int caibi = 1; caibi <= 7; caibi++)
{
int a = qianbi * 2 + he * 5 + wenjianjia * 10 + caibi * 15;
if (a == 100)
{
Console.WriteLine("铅笔买{0}只,盒买{1}个,文件夹买{2}个,彩笔买{3}支",
qianbi, he, wenjianjia, caibi);
}
}
}
}
}
Console.ReadLine();