Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 487269 Accepted Submission(s):
123725
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online
Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one
integer per line.
Output
For each case, output SUM(n) in one line, followed by a
blank line. You may assume the result will be in the range of 32-bit signed
integer.
Sample Input
1
100
Sample Output
1
5050
水题不加题解 可以直接看明白的
1 #include<stdio.h> 2 #include<cmath> 3 #include<iostream> 4 #include<cstring> 5 #include<algorithm> 6 #include<queue> 7 using namespace std; 8 int main () 9 { 10 long int n,i,sum; 11 while(scanf("%ld",&n)!=EOF) 12 { 13 sum=0; 14 for(i=1;i<=n;i++) 15 { 16 sum+=i; 17 } 18 printf("%ld ",sum); 19 printf(" "); 20 } 21 return 0; 22 }